Problem 45
Question
Find the center of mass of the given region \(\mathcal{R},\) assuming that it has uniform unit mass density. \(\mathcal{R}\) is the region bounded above by \(y=1\) for \(-1 \leq x \leq 0\) and by \(y=1-x\) for \(0 \leq x \leq 1\), below by the \(x\) -axis, and on the left by \(x=-1\).
Step-by-Step Solution
Verified Answer
The center of mass is \((-\frac{1}{3}, \frac{1}{2})\).
1Step 1: Understand the Problem
We need to find the center of mass of a region \(\mathcal{R}\) with uniform density, bounded by given lines. Region \(\mathcal{R}\) is a combination of a rectangle and a triangle, bounded at the top by \(y=1\) for \(-1 \leq x \leq 0\) and by \(y=1-x\) for \(0 \leq x \leq 1\), below by the x-axis, left by \(x=-1\).
2Step 2: Divide the Region
The region \(\mathcal{R}\) can be split into two parts: \(R_1\), a rectangle from \((-1, 0)\) to \((0, 1)\), and \(R_2\), a right triangle with vertices at \((0, 0)\), \((1, 0)\), and \((0, 1)\).
3Step 3: Calculate Area of Each Region
The area of \(R_1\) is calculated by multiplying its base and height: \(A_1 = 1 \times 1 = 1\). The area of \(R_2\) is \(A_2 = \frac{1}{2} \cdot 1 \cdot 1 = \frac{1}{2}\).
4Step 4: Find Center of Mass of Each Region
For the rectangle \(R_1\), the center of mass is \((x_1, y_1) = (-0.5, 0.5)\). For the triangle \(R_2\), the center of mass is \((x_2, y_2) = \left(\frac{1}{3}, \frac{1}{3}\right)\).
5Step 5: Use Composite Area Formula for Center of Mass
The overall center of mass \((X, Y)\) of the region \(\mathcal{R}\) is found using the formula: \[ X = \frac{A_1 x_1 + A_2 x_2}{A_1 + A_2}, \quad Y = \frac{A_1 y_1 + A_2 y_2}{A_1 + A_2} \]Substitute known values: \( X = \frac{1(-0.5) + \frac{1}{2}(\frac{1}{3})}{1 + \frac{1}{2}} = \frac{-0.5 + \frac{1}{6}}{\frac{3}{2}} = -\frac{1}{3}\) \( Y = \frac{1(0.5) + \frac{1}{2}(\frac{1}{3})}{1 + \frac{1}{2}} = \frac{0.5 + \frac{1}{6}}{\frac{3}{2}} = \frac{1}{2}\) Thus, the center of mass is \((-\frac{1}{3}, \frac{1}{2})\).
Key Concepts
Composite Area FormulaUniform DensityGeometric ShapesRectangle and Triangle Area Calculation
Composite Area Formula
When calculating the center of mass for a shape that is made up of multiple simple geometric forms, like rectangles and triangles, we use the composite area formula. It helps predict where the center of mass (centroid) of the entire shape lies by considering the areas and the centroids of its component parts.
For example, the formula to find the center of mass coordinates \(X, Y\) is given by:
This technique is crucial in simplifying the process of finding a shape's center of mass by effectively leveraging symmetry and uniformity of the shapes.
For example, the formula to find the center of mass coordinates \(X, Y\) is given by:
- For X-axis: \[ X = \frac{\sum (A_i x_i)}{\sum A_i} \]
- For Y-axis: \[ Y = \frac{\sum (A_i y_i)}{\sum A_i} \]
This technique is crucial in simplifying the process of finding a shape's center of mass by effectively leveraging symmetry and uniformity of the shapes.
Uniform Density
Uniform density is a key consideration when finding the center of mass. It means that the mass is spread evenly throughout the shape. This concept simplifies the calculation, as you can assume that mass is proportionally distributed according to area.
In practice, this means:
In practice, this means:
- Each unit area contributes equally to the mass of the entire shape.
- You can calculate the center of mass without separately weighing each section.
Geometric Shapes
In the context of finding the center of mass, understanding basic geometric shapes like rectangles and triangles is vital. Each shape has unique properties and formulas to determine crucial points like centroids.
**Key Points About Shapes**
**Key Points About Shapes**
- **Rectangle**: Regular four-sided shape. Its centroid is located symmetrically at the intersection of its diagonals which is simply at the center of the rectangle.
- **Triangle**: Its centroid, often called the center of gravity, is found at the average of its vertices' coordinates or can be computed by consistent formulas.
Rectangle and Triangle Area Calculation
Calculating the area of basic shapes like rectangles and triangles is foundational in determining the center of mass for complex shapes.**Rectangle Area**:
- The area of a rectangle is straightforward—product of its length and width. For a rectangle spanning from \(x = a\) to \(x = b\) and within the \(y = c\) plane, its area will be \(\text{Area} = (b-a) \times c\).
- The area formula \( \text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} \) helps ensure correct area calculations for triangles, which are often parts of larger regions.
Other exercises in this chapter
Problem 45
In each of Exercises \(45-52,\) calculate the length \(L\) of the given parametric curve. $$ x=t \cos (t) \quad y=t \sin (t) \quad 0 \leq t \leq 3 \pi $$
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A tank has the shape of a paraboloid of revolution that results from rotating about the \(y\) -axis the region that is bounded above by the horizontal line \(y=
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In each of Exercises 43-48, use the method of cylindrical shells to calculate the volume \(V\) of the solid that is obtained by rotating the given planar region
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In each of Exercises \(43-52\) calculate the average of the given expression over the given interval. $$ \sin ^{3}(x) \quad 0 \leq x \leq \pi $$
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