Problem 45
Question
Evaluate the integrals. $$\int \frac{d x}{17+x^{2}}$$
Step-by-Step Solution
Verified Answer
\(\frac{1}{\sqrt{17}} \arctan\left(\frac{x}{\sqrt{17}}\right) + C\)
1Step 1: Identify the Integral Form
The integral \(\int \frac{d x}{17+x^{2}}\) matches the standard form of \(\int \frac{d x}{a^2 + x^2}\), which is known to result in \(\frac{1}{a} \arctan\left(\frac{x}{a}\right) + C\) where \(C\) is the constant of integration.
2Step 2: Determine the Parameter "a"
In the given integral, compare it with the standard form. Here, \(a^2 = 17\), therefore \(a = \sqrt{17}\).
3Step 3: Apply the Integral Formula
Now, substitute \(a = \sqrt{17}\) into the formula for the standard integral. This gives us \(\frac{1}{\sqrt{17}} \arctan\left(\frac{x}{\sqrt{17}}\right) + C\).
4Step 4: Write the Final Answer
Therefore, the evaluated integral is \(\frac{1}{\sqrt{17}} \arctan\left(\frac{x}{\sqrt{17}}\right) + C\).
Key Concepts
Integration TechniquesDefinite and Indefinite IntegralsTrigonometric Substitution
Integration Techniques
Integration techniques are methods used to find the antiderivative or integral of a function. One useful technique involves recognizing standard forms of integrals.
Different problems may require different techniques. Common methods include substitution, integration by parts, and partial fraction decomposition. Each technique has its unique application scenarios for greater efficiency. Efficiency in integration depends largely on selecting the right technique for the problem at hand.
- By matching an integral to a known form, we can directly apply a formula to solve it.
- This saves time and reduces complexity, making integration more approachable.
Different problems may require different techniques. Common methods include substitution, integration by parts, and partial fraction decomposition. Each technique has its unique application scenarios for greater efficiency. Efficiency in integration depends largely on selecting the right technique for the problem at hand.
Definite and Indefinite Integrals
Integrals can be classified as definite and indefinite integrals, each serving a different purpose and involving distinct concepts:
- An indefinite integral, like \( \int f(x) \, dx \), represents a family of functions whose derivative gives the original function \( f(x) \).
- It includes a constant of integration, usually denoted by \( C \).
- Indefinite integrals capture the general form of antiderivatives.
- It is represented as \( \int_{a}^{b} f(x) \, dx \).
- Unlike indefinite integrals, definite integrals result in a specific number without the constant \( C \).
- They are very useful in calculating total quantities, such as distances or areas between curves.
Trigonometric Substitution
Trigonometric substitution is a powerful integration technique used to simplify integrals involving expressions like \( \sqrt{a^2 - x^2} \), \( \sqrt{a^2 + x^2} \), and \( \sqrt{x^2 - a^2} \).
Consider the integral \( \int \frac{d x}{a^2 + x^2} \).
- It uses trigonometric identities to transform the integrals into more manageable forms.
- By substituting variables with trigonometric functions, complex algebraic forms become simpler trigonometric expressions.
Consider the integral \( \int \frac{d x}{a^2 + x^2} \).
- Recognizing it as an inverse tangent form allows for easier calculation.
- For similar expressions, substitution like \( x = a \tan(\theta) \) helps convert it to a trigonometric integral.
- These substitutions leverage angles and trigonometric function properties to simplify further steps.
Other exercises in this chapter
Problem 45
Evaluate the integrals in Exercises \(29-50.\) $$\int e^{\sec \pi t} \sec \pi t \tan \pi t d t$$
View solution Problem 45
a. Find the inverse of the function \(f(x)=m x,\) where \(m\) is a constant different from zero. b. What can you conclude about the inverse of a function \(y=f(
View solution Problem 45
Evaluate the integrals. $$\int_{2}^{4} \frac{d x}{x(\ln x)^{2}}$$
View solution Problem 46
Evaluate the integrals. $$\int \operatorname{coth} \frac{\theta}{\sqrt{3}} d \theta$$
View solution