Problem 45
Question
Evaluate the integrals in Exercises \(13-48\) . $$ \int t^{3}\left(1+t^{4}\right)^{3} d t $$
Step-by-Step Solution
Verified Answer
\( \frac{(1 + t^4)^4}{16} + C \)
1Step 1: Decide on the substitution
We notice that the integral contains a composite function within a power: \( (1 + t^4)^3 \). This suggests using substitution. Let's set \( u = 1 + t^4 \).
2Step 2: Differentiate the substitution
Now, we differentiate \( u \) with respect to \( t \). Since \( u = 1 + t^4 \), it follows that \( \frac{du}{dt} = 4t^3 \) or \( du = 4t^3 \, dt \). Hence, \( t^3 \, dt = \frac{1}{4} \, du \).
3Step 3: Substitute into the integral
Substitute \( u = 1 + t^4 \) and \( t^3 \, dt = \frac{1}{4} \, du \) into the integral. The integral becomes: \[ \int t^3 (1 + t^4)^3 \, dt = \int \frac{1}{4} u^3 \, du. \]
4Step 4: Solve the new integral
Now we integrate with respect to \( u \): \[ \int \frac{1}{4} u^3 \, du = \frac{1}{4} \cdot \frac{u^4}{4} + C = \frac{u^4}{16} + C. \]
5Step 5: Substitute back to the original variable
Substitute back \( u = 1 + t^4 \) into \( \frac{u^4}{16} + C \), giving: \[ \frac{(1 + t^4)^4}{16} + C. \]
Key Concepts
Substitution MethodDefinite and Indefinite IntegralsPolynomial Integration
Substitution Method
The substitution method in integration helps to simplify an integral by reducing it to a more basic form. This is often done when the integral contains a composite function, where a part of the expression is more manageable if considered as a single unit. In the given problem, the expression
By substituting these into the original integral, we transform a potentially complex problem into a basic polynomial integral with respect to \(u\),
- \((1 + t^4)^3\)
- \(u = 1 + t^4\)
- \(du = 4t^3 \, dt\)
By substituting these into the original integral, we transform a potentially complex problem into a basic polynomial integral with respect to \(u\),
- \(\int \frac{1}{4} u^3 \, du\)
Definite and Indefinite Integrals
Integrals can be classified into two main types: definite and indefinite integrals. A definite integral is one that is evaluated over a specific interval, providing a numerical result, while an indefinite integral represents a family of functions.
In the given problem,
After substituting and simplifying to the integral in terms of \(u\):
In the given problem,
- \(\int t^3 (1 + t^4)^3 \, dt\)
After substituting and simplifying to the integral in terms of \(u\):
- \(\int \frac{1}{4} u^3 \, du\)
Polynomial Integration
Polynomial integration involves integrating expressions made up of sums of powers of variables, a process that aligns closely with the fundamental principles of calculus.
- Usually taking the form \(x^n\), where \(n\) is a constant.
- \(\frac{u^4}{4}\)
- \(\int \frac{1}{4} u^3 \, du\)
- \(\frac{u^4}{16} + C\)
- \(\frac{(1 + t^4)^4}{16} + C\)
Other exercises in this chapter
Problem 44
Evaluate the integrals in Exercises \(13-48\) . $$ \int\left(\theta^{4}-2 \theta^{2}+8 \theta-2\right)\left(\theta^{3}-\theta+2\right) d \theta $$
View solution Problem 45
Find the areas of the regions enclosed by the lines and curves in Exercises \(41-50 .\) $$ y=x^{2} \quad \text { and } \quad y=-x^{2}+4 x $$
View solution Problem 46
Find the areas of the regions enclosed by the lines and curves in Exercises \(41-50 .\) $$ y=7-2 x^{2} \quad \text { and } \quad y=x^{2}+4 $$
View solution Problem 46
Evaluate the integrals in Exercises \(13-48\) . $$ \int \sqrt{\frac{x-1}{x^{5}}} d x $$
View solution