Problem 45
Question
Determine the amount of money required to set up a charitable endowment that pays the amount \(P\) each year indefinitely for the annual interest rate \(r\) compounded continuously. $$ P=\$ 5000, r=7.5 \% $$
Step-by-Step Solution
Verified Answer
To evaluate, calculate the value of the denominator \(e^{0.075 * 1}\) first, then divide \$5000 by this evaluated value. The result of this calculation will give the initial endowment amount necessary to yield a perpetuity of \$5000 per year with continuous compounding at an annual interest rate of 7.5%. Always remember to express the answer in currency terms, such as dollars.$.
1Step 1: Express the interest rate as a decimal
The annually compounded rate, \(r\), is given as 7.5%. As a decimal, this can be expressed as 0.075 (= 7.5 / 100).
2Step 2: Rearrange the equation for 'Principal'
Re-arrange the equation \(P = Principal * e^{rt}\) to solve for 'Principal'. This rearrangement gives: \[Principal = P / e^{rt}\].
3Step 3: Substitute the known values into the equation
With \(P = \$5000\), \(r = 0.075\), and \(t = 1\), we can substitute these values in the equation from Step 2, which gives: \[Principal = 5000 / e^{(0.075 * 1)}\].
4Step 4: Evaluate the equation
Using the accurate value of \(e\) (approximately 2.71828) and the values we substituted, the equation can now be evaluated to determine the 'Principal'.
Other exercises in this chapter
Problem 44
Evaluate the definite integral. $$ \int_{0}^{5} \frac{x}{\sqrt{5+2 x}} d x $$
View solution Problem 44
Evaluate the definite integral. $$ \int_{1}^{e} 2 x \ln x d x $$
View solution Problem 45
Use a program similar to the Simpson's Rule program on page 906 to approximate the integral. Use \(n=100\). $$ \int_{2}^{5} 10 x e^{-x} d x $$
View solution Problem 45
Evaluate the definite integral. $$ \int_{0}^{5} \frac{x}{(4+x)^{2}} d x $$
View solution