Problem 45
Question
Calculate the molality of each of the following solutions: (a) \(10.0 \mathrm{~g}\) of benzene \(\left(\mathrm{C}_{6} \mathrm{H}_{6}\right)\) dissolved in \(50.0 \mathrm{~g}\) of carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right),(\mathbf{b}) 5.00 \mathrm{~g}\) of \(\mathrm{NaCl}\) dissolved in \(0.100 \mathrm{~L}\) of water.
Step-by-Step Solution
Verified Answer
In conclusion, the molality of solution (a) containing \(10.0\,g\) of benzene dissolved in \(50.0\,g\) of carbon tetrachloride is \(2.56\,m\), and the molality of solution (b) containing \(5.00\,g\) of NaCl dissolved in \(0.100\,L\) of water is \(0.86\,m\).
1Step 1: Calculate moles of benzene
The molecular formula of benzene is \(C_6H_6\), so the molar mass of benzene is \((6 × 12.01)+(6 × 1.01)=78.12 g/mol\).
Given 10.0 g of benzene, we can calculate the number of moles by:
Moles of benzene = \(\frac{10.0\,\text{g}}{78.12\,\text{g/mol}} = 0.128\, \text{moles}\)
2Step 2: Convert mass of carbon tetrachloride
We must convert the mass of carbon tetrachloride from grams to kilograms:
50.0 g = \(50.0\, \times 10^{-3}\) kg = 0.050 kg
3Step 3: Calculate molality for (a)
Now, we can calculate the molality of the solution (a) as follows:
Molality = \(\frac{\text{moles of solute}}{\text{mass of solvent in kg}} = \frac{0.128\,\text{moles}}{0.050\,\text{kg}} = 2.56\,m\)
For (b):
4Step 4: Calculate moles of NaCl
The molecular formula of NaCl; the molar mass of NaCl is \((1 × 22.99)+(1 × 35.45)=58.44\,g/mol\).
Given 5.00 g of NaCl, we can calculate the number of moles by:
Moles of NaCl = \(\frac{5.00\,\text{g}}{58.44\,\text{g/mol}} = 0.086\,\text{moles}\)
5Step 5: Convert mass of water
We know that the density of water is about \(1\,\text{g/mL}\), so the mass of 0.100 L of water is:
0.100 L = 100.0 mL = 100.0 g
100.0 g = \(100.0\, \times 10^{-3}\) kg = 0.100 kg
6Step 6: Calculate molality for (b)
Now, we can calculate the molality of the solution (b) as follows:
Molality = \(\frac{\text{moles of solute}}{\text{mass of solvent in kg}} = \frac{0.086\,\text{moles}}{0.100\,\text{kg}} = 0.86\,m\)
In conclusion, the molality of solution (a) is \(2.56\,m\()), and the molality of solution (b) is \(0.86\,m\().
Key Concepts
Moles CalculationMolar MassSolvent Mass Conversion
Moles Calculation
To calculate the molality of a solution, one must first determine the number of moles of the solute present. The concept of moles is central in chemistry because it allows us to relate the mass of a substance to the number of particles contained within it. The number of moles () can be calculated using the formula:
\[\text{Moles} = \frac{\text{Given Mass}}{\text{Molar Mass}}\]
For example, in calculating the moles of benzene (C_6H_6), given that we have 10.0 grams of benzene, we will first need its molar mass. As each carbon atom contributes 12.01 g/mol and each hydrogen atom 1.01 g/mol, benzene's molar mass totals to 78.12 g/mol. To find the moles of benzene:
\[\text{Moles} = \frac{\text{Given Mass}}{\text{Molar Mass}}\]
For example, in calculating the moles of benzene (C_6H_6), given that we have 10.0 grams of benzene, we will first need its molar mass. As each carbon atom contributes 12.01 g/mol and each hydrogen atom 1.01 g/mol, benzene's molar mass totals to 78.12 g/mol. To find the moles of benzene:
- Use the molar mass of benzene (78.12 g/mol)
- Plug into the formula: \( \frac{10.0\, \text{g}}{78.12\, \text{g/mol}} = 0.128\; \text{moles} \)
Molar Mass
Molar mass is a fundamental concept as it connects the mass of a substance with the amount of particles, or the number of moles, it contains. It is defined as the mass of one mole of a given substance in grams and is expressed in g/mol. To calculate molar mass, sum the average atomic masses of all atoms in the molecular formula.
Take benzene ( C_6H_6 ) as an example. It consists of 6 carbon atoms and 6 hydrogen atoms:
For NaCl, you have:
Understanding molar mass is crucial for converting between grams and moles, which is necessary for calculating other solution properties like molality.
Take benzene ( C_6H_6 ) as an example. It consists of 6 carbon atoms and 6 hydrogen atoms:
- Carbon contributes: 6 atoms × 12.01 g/mol = 72.06 g/mol
- Hydrogen contributes: 6 atoms × 1.01 g/mol = 6.06 g/mol
For NaCl, you have:
- Sodium (Na): 1 atom × 22.99 g/mol = 22.99 g/mol
- Chlorine (Cl): 1 atom × 35.45 g/mol = 35.45 g/mol
Understanding molar mass is crucial for converting between grams and moles, which is necessary for calculating other solution properties like molality.
Solvent Mass Conversion
Solvent mass conversion becomes crucial, particularly in chemistry solutions, where the mass of the solvent influences concentration calculations such as molality. For precise molality calculations, solvent mass must be expressed in kilograms.
In many experimental setups, it's common to begin with mass in grams. For instance, in solution (a), the mass of carbon tetrachloride is initially 50.0 grams. To convert:
In many experimental setups, it's common to begin with mass in grams. For instance, in solution (a), the mass of carbon tetrachloride is initially 50.0 grams. To convert:
- Start by dividing the mass by 1000 to convert to kilograms, since 1 kg = 1000 g.
- Thus, 50.0 g becomes 0.050 kg.
- Convert 100 g to kilograms: 100 g = 0.100 kg
Other exercises in this chapter
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