Problem 45
Question
Approximate all zeros of the function to the nearest hundredth. $$ f(x)=-4.9 x^{2}+5.1 x+1.2 $$
Step-by-Step Solution
Verified Answer
The zeros are approximately -0.20 and 1.24.
1Step 1: Identify Method to Use
To approximate the zeros of a quadratic function like \( f(x) = -4.9x^2 + 5.1x + 1.2 \), we can use the quadratic formula: \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = -4.9 \), \( b = 5.1 \), and \( c = 1.2 \).
2Step 2: Calculate the Discriminant
Compute the discriminant \( \Delta = b^2 - 4ac \).Substitute the values in: \( \Delta = 5.1^2 - 4(-4.9)(1.2) = 26.01 + 23.52 = 49.53 \).
3Step 3: Compute the Square Root of the Discriminant
Evaluate \( \sqrt{\Delta} \):\( \sqrt{49.53} \approx 7.039 \).
4Step 4: Calculate the Zeros Using the Quadratic Formula
Substitute \( a, b, \) and \( \sqrt{\Delta} \) into the quadratic formula to find the zeros.1. \( x_1 = \frac{-5.1 + 7.039}{2(-4.9)} = \frac{1.939}{-9.8} \approx -0.198 \).2. \( x_2 = \frac{-5.1 - 7.039}{2(-4.9)} = \frac{-12.139}{-9.8} \approx 1.238 \).
5Step 5: Round the Solutions to the Nearest Hundredth
Round the results to the nearest hundredth:\( x_1 \approx -0.20 \) and \( x_2 \approx 1.24 \).
Key Concepts
Quadratic FormulaDiscriminantZeros of FunctionsApproximation Methods
Quadratic Formula
When dealing with quadratic equations, the quadratic formula is often our best friend. This formula allows us to find the roots or zeros of a quadratic equation, which is critical for understanding the behavior of the function. The quadratic formula is: \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]In this formula, \( a \), \( b \), and \( c \) are the coefficients from the quadratic equation in the form \( ax^2 + bx + c = 0 \). The symbol "±" indicates that there are usually two solutions: one for the plus and another for the minus. This method is powerful because it doesn't assume that the quadratic can be easily factored, making it suitable for all forms of quadratic equations.
By using this formula, we can systematically find the zeros of functions like \( f(x)=-4.9x^2+5.1x+1.2 \).
By using this formula, we can systematically find the zeros of functions like \( f(x)=-4.9x^2+5.1x+1.2 \).
Discriminant
The discriminant is a pivotal component of the quadratic formula. You find it inside the square root: \( b^2 - 4ac \). It helps determine the nature of the roots of a quadratic equation.
- If the discriminant is positive, like in our example where \( \Delta = 49.53 \), this means there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root, which means the parabola touches the x-axis at a single point.
- If the discriminant is negative, there are no real roots, indicating that the graph does not intersect the x-axis at all.
Zeros of Functions
The zeros of a function are the x-values that make the function equal to zero. For quadratic functions, finding the zeros is akin to finding the x-intercepts of the graph of the function.In the exercise at hand, we used the quadratic formula to approximate these values for \( f(x)=-4.9x^2+5.1x+1.2 \) where we found two zeros:
- \(x_1 \approx -0.20\)
- \(x_2 \approx 1.24\)
Approximation Methods
In real-life applications, sometimes solving exactly isn't feasible or necessary, and approximation becomes important. For quadratic functions, once we have applied the quadratic formula and derived solutions, we often need to round these solutions to make them more manageable.In our example, we approximated:
- \(x_1 \approx -0.20\)
- \(x_2 \approx 1.24\)
Other exercises in this chapter
Problem 44
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