Problem 45
Question
Algebraic and Graphical Approaches In Exercises \(31-46\), find all real zeros of the function algebraically. Then use a graphing utility to confirm your results. $$f(x)=x^{3}-3 x^{2}+2 x-6$$
Step-by-Step Solution
Verified Answer
The real zeros of the function are \(x = -2\), \(x = 1\), and \(x = 3\).
1Step 1: Apply the Rational Root Theorem
The Rational Root Theorem can help in identifying potential rational zeroes of a polynomial. This theorem states that any rational zero \(p/q\) of a polynomial \(P(x)\) with integer coefficients must satisfy: \(p\) is a factor of the constant term, and \(q\) is a factor of the leading coefficient. In the equation \(f(x)=x^{3}-3 x^{2}+2 x-6\), the constant term is -6 and the leading coefficient is 1. Thus, the potential rational zeroes of \(f(x)\) are ± factors of 6.
2Step 2: Test Potential Rational Zeros
After identifying the potential rational zeros, substitute each into the given function \(f(x)\) to find values that will make the function zero. Doing the substitutions, we get zeros as \(-2,1,3\) which satisfies the function \(f(x) = 0\).
3Step 3: Confirm Zeros using Graphing Utility
To verify the zeros obtained, plot the function and observe where it crosses the x-axis which indicates the x-values where function value is zero. The function should cross at \(x = -2, 1, 3\), which confirms our algebraic solution.
Key Concepts
Rational Root TheoremGraphing Utility for PolynomialIdentifying Polynomial Zeros Algebraically
Rational Root Theorem
When we're dealing with polynomials and hunting for real zeros, the Rational Root Theorem is like our mathematical detective tool. It gives us clues about where to start our investigation. According to this theorem, if a polynomial has real, rational zeros (that means the solutions are nice fractions), then they are likely hiding among the factors of the constant term when divided by the factors of the leading coefficient.
Let's apply this to a polynomial like f(x) = x^3 - 3x^2 + 2x - 6. The constant term is -6, and the leading coefficient (the one attached to the highest power of x) is 1. Our theorem suggests looking at the factors of -6, which are ±1, ±2, ±3, and ±6. Since the leading coefficient is 1, we don't have to worry about dividing by other factors. So, our suspects for rational zeros are these factors themselves.
In simpler terms, imagine you're given a bag of cookie pieces and told that only whole cookies are your actual treats. The Rational Root Theorem says your whole cookies could only come from the pieces in that bag — it narrows down the hunt significantly!
Let's apply this to a polynomial like f(x) = x^3 - 3x^2 + 2x - 6. The constant term is -6, and the leading coefficient (the one attached to the highest power of x) is 1. Our theorem suggests looking at the factors of -6, which are ±1, ±2, ±3, and ±6. Since the leading coefficient is 1, we don't have to worry about dividing by other factors. So, our suspects for rational zeros are these factors themselves.
In simpler terms, imagine you're given a bag of cookie pieces and told that only whole cookies are your actual treats. The Rational Root Theorem says your whole cookies could only come from the pieces in that bag — it narrows down the hunt significantly!
Graphing Utility for Polynomial
Once we have a list of potential rational zeros from the Rational Root Theorem, it's time for visual confirmation. Enter the graphing utility for polynomials. This is like getting a bird's-eye view of the polynomial's behavior across the number line. By inputting our polynomial function into a graphing calculator or software, we get a curve that shows us where the function's output, or f(x), equals zero, which is exactly when the curve crosses the x-axis.
These crossings are the real zeros we're after. In the case of our polynomial f(x) = x^3 - 3x^2 + 2x - 6, we expect to see the curve touch or cross the x-axis at the zeros we calculated: -2, 1, and 3. It's a satisfying moment when the visual matches up with the algebra — it's like catching the suspects red-handed at the scene of the crime!
These crossings are the real zeros we're after. In the case of our polynomial f(x) = x^3 - 3x^2 + 2x - 6, we expect to see the curve touch or cross the x-axis at the zeros we calculated: -2, 1, and 3. It's a satisfying moment when the visual matches up with the algebra — it's like catching the suspects red-handed at the scene of the crime!
Identifying Polynomial Zeros Algebraically
While the Rational Root Theorem and graphing utilities are great, often the most reliable way to find zeros is the old-fashioned algebraic approach. This is where we roll up our sleeves and substitute potential zeros into the polynomial to see which ones make the output zero. It's like a numerical game of 'Guess Who?'.
Working with our example, f(x) = x^3 - 3x^2 + 2x - 6, we try plugging in our guessed zeros from the Rational Root Theorem. If we find that inserting a number for x makes the whole function equal zero, that number is a confirmed zero. Here, when we plug in -2, 1, and 3, voila! The function outputs zero for all three. It's algebraic validation that these are indeed the real zeros of our polynomial. It might feel like a bit of a workout, but this method flexes your algebra muscles and solidifies the theoretical groundwork laid by the Rational Root Theorem with some good old calculation.
Working with our example, f(x) = x^3 - 3x^2 + 2x - 6, we try plugging in our guessed zeros from the Rational Root Theorem. If we find that inserting a number for x makes the whole function equal zero, that number is a confirmed zero. Here, when we plug in -2, 1, and 3, voila! The function outputs zero for all three. It's algebraic validation that these are indeed the real zeros of our polynomial. It might feel like a bit of a workout, but this method flexes your algebra muscles and solidifies the theoretical groundwork laid by the Rational Root Theorem with some good old calculation.
Other exercises in this chapter
Problem 44
Use the zero or root feature of a graphing utility to approximate the real zeros of \(f\). Give your approximations to the nearest thousandth. $$f(x)=3 x^{4}-12
View solution Problem 44
Write the function in the form \(f(x)=(x-k) q(x)+r\) for the given value of \(k\), and demonstrate that \(f(k)=r\). $$f(x)=3 x^{3}-19 x^{2}+27 x-7, \quad k=3-\s
View solution Problem 45
Find two quadratic functions whose graphs have the given \(x\) -intercepts. Find one function whose graph opens upward and another whose graph opens downward. (
View solution Problem 45
Sketch the graph of the rational function. To aid in sketching the graphs, check for intercepts, symmetry, vertical asymptotes, and horizontal asymptotes. $$g(x
View solution