Problem 45
Question
$$a^{2}-5 a b+6 b^{2}$$
Step-by-Step Solution
Verified Answer
The expression factors to \((a - 3b)(a - 2b)\).
1Step 1: Identify the Terms
The expression is given as \(a^{2} - 5ab + 6b^{2}\). It is a trinomial with three terms that contain the variables \(a\) and \(b\).
2Step 2: Analyze Possible Factorization
Consider the expression as a quadratic in terms of \(a\), which gives a leading coefficient of 1. The expression is an attempt to be factorized as \((a - x)(a - y)\).
3Step 3: Understand Factoring Requirements
To factor \(a^{2} - 5ab + 6b^{2}\), we need two numbers whose product is 6 and sum is -5. Think of \(6b^{2}\) as \((3b)(2b)\) and find appropriate factors.
4Step 4: Find Suitable Factors
Match up the numbers that multiply to 6 \((3b \times 2b)\) and that sum up to -5 \(-3b - 2b\). These are \(-3b\) and \(-2b\).
5Step 5: Factor the Expression
Write the expression \(a^2 - 5ab + 6b^2\) in terms of these factors: \( (a - 3b)(a - 2b)\). Therefore, the expression can be factored as \((a - 3b)(a - 2b)\).
6Step 6: Verify the Solution
Expand \((a - 3b)(a - 2b)\) to check if it equals the original expression. Multiply: \[(a - 3b)(a - 2b) = a^{2} - 2ab - 3ab + 6b^2 = a^2 - 5ab + 6b^2\]. The factored form is correct.
Key Concepts
Trinomial ExpressionsPolynomial FactorizationAlgebraic Expressions
Trinomial Expressions
Trinomial expressions are a type of polynomial that includes exactly three terms. These terms are usually separated by a plus or minus sign. In the given expression, \(a^{2} - 5ab + 6b^{2}\), each term consists of different combinations of the variables \(a\) and \(b\). Specifically, it features:
- First term: \(a^{2}\) - The square of \(a\).
- Second term: \(-5ab\) - This term involves both \(a\) and \(b\) and combines them linearly.
- Third term: \(6b^{2}\) - The square of \(b\) multiplied by 6.
Polynomial Factorization
Polynomial factorization is the process of breaking down a polynomial into simpler 'factors' that, when multiplied together, yield the original polynomial. This is similar to breaking down numbers into prime factors but done in an algebraic context. When handling trinomial expressions like \(a^{2} - 5ab + 6b^{2}\), we often aim to transform the expression into a product of binomials.
Consider the target expression to be factored:
Consider the target expression to be factored:
- Identify possible binomial factors: We need to determine two binomials that multiply to give the trinomial.
- Find pairs of numbers: For terms other than \(a^{2}\), find numbers that satisfy specific multiplication and addition properties related to the trinomial's coefficients.
- Utilize trial and error: Sometimes, it's necessary to test different combinations until the multiplication and addition properties fit perfectly.
Algebraic Expressions
Algebraic expressions are combinations of letters and numbers where letters represent variables. They are used to represent general or specific relationships between quantities.
In the expression \(a^{2} - 5ab + 6b^{2}\), we have two variables, \(a\) and \(b\). These expressions form the foundation of algebra, allowing for the representation of general relationships that can be manipulated to solve problems.
Key characteristics of algebraic expressions include:
In the expression \(a^{2} - 5ab + 6b^{2}\), we have two variables, \(a\) and \(b\). These expressions form the foundation of algebra, allowing for the representation of general relationships that can be manipulated to solve problems.
Key characteristics of algebraic expressions include:
- Coefficients: Numbers multiplying the variables, such as -5 in \(-5ab\).
- Variables: Letters like \(a\) and \(b\) can take different numerical values, depending on the context.
- Constants: Numbers on their own, if present, but absent in this specific trinomial.
Other exercises in this chapter
Problem 45
The following is a list of random factoring problems. Factor each expression. If an expression is not factorable, write "prime." See Examples 1-5. $$ 8 v^{2}-14
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Factor. If a polynomial can't be factored, write "prime." $$ a^{2}+b^{2} $$
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Solve each equation. $$ s^{2}=16 s $$
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Factor. $$ x^{4}-216 x $$
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