Problem 45
Question
A sled is pulled horizontally over ice by a rope attached to its front. A20-lb force acting at an angle of \(60^{\circ}\) with the horizontal moves the sled \(100 \mathrm{ft}\). Find the work done.
Step-by-Step Solution
Verified Answer
The work done is 1000 ft-lb.
1Step 1: Understand the Problem Scenario
We are given a force of 20 lb acting at an angle of \(60^\circ\) to the horizontal and we need to calculate the work done in moving the sled horizontally by 100 feet.
2Step 2: Recall the Formula for Work
The work done by a force when moving an object is calculated using the formula: \( W = F \cdot d \cdot \cos(\theta) \). Here, \( F \) is the magnitude of the force, \( d \) is the displacement, and \( \theta \) is the angle between the force and the displacement direction.
3Step 3: Identify the Values for the Variables
From the problem, we have: \( F = 20 \) lb, \( d = 100 \) ft, and \( \theta = 60^\circ \).
4Step 4: Calculate the Work
Substitute the known values into the formula: \[W = 20 \cdot 100 \cdot \cos(60^\circ)\] Calculate \( \cos(60^\circ) = \frac{1}{2} \), then \( W = 20 \cdot 100 \cdot 0.5 = 1000 \).
5Step 5: Conclusion
The work done by the force is \( 1000 \) foot-pounds.
Key Concepts
Calculating WorkForce and Angle RelationshipPhysics Problem Solving
Calculating Work
"Work" in physics involves calculating how much effort is applied to move an object over a distance. It's not simply about applying a force—it's about applying that force in a way that moves your object. To do this, we use the formula:
- Work (W) = Force (F) \(\times\) Distance (\(d\)) \(\times\) \(\cos(\theta)\) \
- The magnitude of the force applied.
- The distance the object is moved.
- The angle (\(\theta\)) at which the force is applied relative to the direction of movement.
Force and Angle Relationship
Force is a vector—it has both a magnitude and a direction. When lifting or pushing an object, the angle at which you apply the force significantly affects how effective your effort will be. This is where trigonometry, especially the cosine function, becomes crucial in physics calculations.In the scenario with the sled, the force was not aligned with the direction of movement; it was at a 60-degree angle. Such angular misalignment requires us to break down the force into components, specifically, its horizontal component.The horizontal component of a force is calculated as:
- \(F_{\text{horizontal}} = F \times \cos(\theta)\)
Physics Problem Solving
Problem-solving in physics involves breaking down complex scenarios into manageable components, allowing us to analyze and compute various physical phenomena effectively. Mastering physics problem-solving often means becoming comfortable with deconstructing each part of a problem to clearly understand the principles at play. Here's a basic approach:
- Read and Understand the Problem: Carefully identify what you are being asked to find, and make a note of all given values. Contextual understanding helps in visualizing the physical setup.
- Identify the Relevant Equations: Choose the correct formula(s) related to the problem. This involves connecting the relevant principles, like Newton’s laws or work-energy relationships, to your problem.
- Substitute Known Values: Input the values given in the problem into your formula. Ensure units are consistent when performing these calculations.
- Calculate and Conclude: Finally, perform the mathematical operations, interpret the results, and check if they make sense in the context.
Other exercises in this chapter
Problem 44
\(\mathbf{a}=\langle 1,-3,2\rangle, \mathbf{b}=\langle-1,1,1\rangle\), and \(\mathbf{c}=\langle 2,6,9\rangle .\) Find the indicated vector or scalar. \(4(\mathb
View solution Problem 44
A vector is said to be tangent to a curve at a point if it is parallel to the tangent line at the point. Find a unit tangent vector to the given curve at the in
View solution Problem 45
In Problems, find, if possible, an equation of a plane that contains the given points. $$ (3,5,2),(2,3,1),(-1,-1,4) $$
View solution Problem 45
\(\mathbf{a}=\langle 1,-3,2\rangle, \mathbf{b}=\langle-1,1,1\rangle\), and \(\mathbf{c}=\langle 2,6,9\rangle .\) Find the indicated vector or scalar. \(\|\mathb
View solution