Problem 44
Question
What continuous interest rate is equivalent to an annual rate of \(9 \% ?\) Extra credit: Telephone a bank for both rates and check their calculation.
Step-by-Step Solution
Verified Answer
The equivalent continuous interest rate is approximately 8.62%.
1Step 1: Understand the Problem
We need to find the continuous interest rate that is equivalent to a given nominal annual interest rate of 9%. This involves converting a nominal rate to a continuously compounded rate.
2Step 2: Use the Formula for Continuous Interest Rate
The relationship between the nominal annual interest rate \( r \) and the equivalent continuous interest rate \( r_c \) is given by the formula \( e^{r_c} = 1 + r \), where \( r \) is expressed as a decimal.
3Step 3: Express the Annual Rate as a Decimal
The given annual rate is 9%, which we express in decimal form as \( r = 0.09 \).
4Step 4: Solve the Equation for Continuous Rate
Substitute \( r = 0.09 \) into the equation \( e^{r_c} = 1 + r \), we get: \[ e^{r_c} = 1 + 0.09 = 1.09 \] Now, solve for \( r_c \) by taking the natural logarithm of both sides: \[ r_c = \ln(1.09) \]
5Step 5: Calculate the Continuous Rate
Compute \( r_c \) using a calculator: \[ r_c = \ln(1.09) \approx 0.0862 \] Convert it back to a percentage: \( r_c \approx 8.62\% \).
Key Concepts
Nominal Annual Interest RateCompounded RateNatural LogarithmExponential Function
Nominal Annual Interest Rate
The nominal annual interest rate is a way to represent the annual percentage rate of return on an investment, or the borrowing cost for a loan, without adjusting for the effects of compounding within the year. It is typically expressed as a percentage.
For example, if a bank offers an interest rate of 9% per annum, this 9% is the nominal annual rate. It is straightforward and does not account for how interest may be compounded, like monthly or quarterly.
For example, if a bank offers an interest rate of 9% per annum, this 9% is the nominal annual rate. It is straightforward and does not account for how interest may be compounded, like monthly or quarterly.
- It is used to compare the effective cost or yield of loans and investments.
- It does not necessarily reflect what you actually earn or pay; the compounded rate does that.
Compounded Rate
The compounded rate refers to the interest rate if it is applied not only to the initial principal each period but also to the accumulated interest from previous periods. Compounding can occur in various frequencies such as annually, semi-annually, quarterly, monthly, or even daily.
This concept is key to understanding how interest accumulates over time. The frequency of compounding matters greatly:
This concept is key to understanding how interest accumulates over time. The frequency of compounding matters greatly:
- More frequent compounding results in more interest being accrued over time.
- The compounded rate often leads to a higher effective yield compared to the nominal rate, especially when interest compounds frequently.
Natural Logarithm
The natural logarithm, represented as \( \ln \), is the logarithm to the base of the mathematical constant \( e \) (approximately equal to 2.71828). It is a critical function in mathematics, especially for calculations involving growth processes like continuous compounding.
- Natural logarithms simplify the calculation of continuously compounded rates.
- They convert exponential growth rates to linear operations, making complex computations manageable.
Exponential Function
An exponential function is a mathematical function of the form \( f(x) = e^x \), where \( e \) is Euler's number, a fundamental constant in mathematics. These functions describe processes that grow or decay at a constant relative rate, such as population growth or radioactive decay.
- The strength of exponential functions lies in their ability to model continuous growth or compounding.
- In finance, the exponential function is used to determine the future value of investments under continuous compounding.
Other exercises in this chapter
Problem 43
Verify the derivatives \(43-46\), which give useful anti derivatives: $$ \frac{d}{d x} \ln \left(x+\sqrt{x^{2}+1}\right)=\frac{1}{\sqrt{1+x^{2}}} $$
View solution Problem 43
If \(d y / d x=y\) find the derivative of \(e^{-x} y\) by the product rule. Deduce that \(y(x)=C e^{x}\) for some constant \(C\).
View solution Problem 44
Verify the derivatives , which give useful anti derivatives: $$ \frac{d}{d x} \ln \left(\frac{x-a}{x+a}\right)=\frac{2 a}{\left(x^{2}-a^{2}\right)} $$
View solution Problem 44
Prove that \(x^{e}=e^{x}\) has only one positive solution.
View solution