Problem 44
Question
Use the fundamental principle of counting or permutations to solve each problem. In how many ways can 7 of 10 chemicals be added to a beaker for an experiment? (Assume that the order in which the chemicals are add is important.)
Step-by-Step Solution
Verified Answer
There are 604,800 ways to add 7 of 10 chemicals to the beaker.
1Step 1: Identify the Problem Type
This problem involves selecting a subset of chemicals from a larger set, where the order of selection matters. Therefore, it is a permutation problem.
2Step 2: Understand Permutation Formula
The formula for permutation where order matters is given by \( P(n, r) = \frac{n!}{(n-r)!} \), where \( n \) is the total number of items to choose from and \( r \) is the number of items to choose.
3Step 3: Apply the Permutation Formula
For this problem, we need to choose 7 chemicals from a set of 10, so \( n = 10 \) and \( r = 7 \). Plug these values into the permutation formula: \[ P(10, 7) = \frac{10!}{(10-7)!} = \frac{10!}{3!} \]
4Step 4: Calculate the Permutations
Compute the factorial values: \( 10! = 10 \times 9 \times 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 3,628,800 \) \( 3! = 3 \times 2 \times 1 = 6 \)Now substitute back into the equation:\[ P(10, 7) = \frac{3,628,800}{6} = 604,800 \]
5Step 5: Finalize the Solution
Thus, the number of ways to add 7 chemicals out of 10 to a beaker, considering the order of addition, is \( 604,800 \).
Key Concepts
Fundamental Principle of CountingPermutation FormulaFactorialsOrder in Combinatorics
Fundamental Principle of Counting
At its core, the Fundamental Principle of Counting is a straightforward concept used in combinatorics. It helps us determine the number of possible ways events can occur. Simply put, if one event can happen in "m" ways and a second event can happen independently in "n" ways, the two events can occur in a total of \( m \times n \) ways.
- For multiple events, you simply multiply the number of possible outcomes of each event.
- For instance, if you're picking a shirt and pants for an outfit, and you have 3 shirts and 4 pants to choose from, you have \( 3 \times 4 = 12 \) possible outfits.
Permutation Formula
Permutations are a way to count arrangements or sequences where order matters. The permutation formula helps us calculate how many different ways a set of items can be arranged.
The formula for permutations is \( P(n, r) = \frac{n!}{(n-r)!} \), where:
The formula for permutations is \( P(n, r) = \frac{n!}{(n-r)!} \), where:
- \( n \) is the total number of items.
- \( r \) is the number of items to arrange.
- \( ! \) denotes a factorial, a product of all positive integers up to that number.
Factorials
Factorials are a mathematical operation often used in permutations and combinations. The notation for a factorial is an exclamation mark "!" following a number. This represents the product of all positive integers up to and including that number. For example:
In permutation problems, factorials help us understand the total number of ways to arrange a set of items without repetition. For example, for \( n \) items, arranging all of them is \( n! \). This provides a foundation to solve problems that require counting specific arrangements where order counts.
- \( 5! = 5 \times 4 \times 3 \times 2 \times 1 = 120 \)
- \( 3! = 3 \times 2 \times 1 = 6 \)
In permutation problems, factorials help us understand the total number of ways to arrange a set of items without repetition. For example, for \( n \) items, arranging all of them is \( n! \). This provides a foundation to solve problems that require counting specific arrangements where order counts.
Order in Combinatorics
The concept of order in combinatorics addresses whether the sequence of items does or does not matter. In permutations, order significantly affects the result.
However, when order is important, permutations provide the right framework for calculating arrangements. It's crucial to identify this aspect in problems because it influences whether to use permutation formulas like \( P(n, r) = \frac{n!}{(n-r)!} \) or methods for combinations when calculating possible outcomes. Understanding this distinction is key for accurately arranging items in sequences or sets.
- Every different arrangement or sequence is considered unique if order matters.
- For example, the sequences "123" and "321" are different when order is considered.
However, when order is important, permutations provide the right framework for calculating arrangements. It's crucial to identify this aspect in problems because it influences whether to use permutation formulas like \( P(n, r) = \frac{n!}{(n-r)!} \) or methods for combinations when calculating possible outcomes. Understanding this distinction is key for accurately arranging items in sequences or sets.
Other exercises in this chapter
Problem 43
Find the sum for each series. $$\sum_{i=-1}^{5}\left(i^{2}-2 i\right)$$
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Find the sum of the first 10 terms of each arithmetic sequence. $$a_{1}=-8, a_{10}=-1.25$$
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Write the indicated tem of each binomial expansion. Tenth term of \(\left(a^{3}+3 b\right)^{11}\)
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CONCEPT CHECK The number 0.999 ... can be written as the sum of the terms of an infinite geometric sequence: \(0.9+0.09+0.009+\cdots\) Here we have \(a_{1}=0.9\
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