Problem 44
Question
Use Heron's Area Formula to find the area of the triangle. $$a=2.4, \quad b=2.75, \quad c=2.25$$
Step-by-Step Solution
Verified Answer
The area of the triangle is approximately 2.82 square units.
1Step 1: Calculate the Semi-Perimeter
Before the area can be calculated, the semi-perimeter of the triangle must be found. This is done by adding the lengths of the triangle's sides and dividing by 2. The equation for this is \(s = (a + b + c) / 2\).\nUsing the known values \(a = 2.4\), \(b = 2.75\), and \(c = 2.25\), the semi-perimeter is calculated as \(s = (2.4 + 2.75 + 2.25) / 2 = 3.7\).
2Step 2: Calculate the Area
Once the semi-perimeter is calculated, the area of the triangle can be found using Heron's Area Formula. This is obtained by substituting the values for \(s\), \(a\), \(b\), and \(c\) into the formula \(A = \sqrt{s \cdot (s - a) \cdot (s - b) \cdot (s - c)}\).\nSubstituting the values of \(s = 3.7\), \(a = 2.4\), \(b = 2.75\), and \(c = 2.25\) results in \(A = \sqrt{(3.7 - 2.4) \cdot (3.7 - 2.75) \cdot (3.7 - 2.25) \cdot 3.7}\). Continuing with the calculation, the area \(A\) equals approximately 2.82 square units.
Key Concepts
Understanding the Semi-PerimeterTriangle BasicsArea Calculation Using Heron's Formula
Understanding the Semi-Perimeter
To find a triangle's area using Heron's Area Formula, you first need to determine the semi-perimeter. This is an essential step because it simplifies the way you will later calculate the area. The semi-perimeter, denoted as \(s\), is half the perimeter of the triangle.
It acts as a central parameter in Heron's formula.The formula to calculate the semi-perimeter is straightforward:
It acts as a central parameter in Heron's formula.The formula to calculate the semi-perimeter is straightforward:
- Add the lengths of all three sides of the triangle.
- Divide the sum by two.
Triangle Basics
A triangle is a basic geometric shape with three sides, three vertices, and three angles. Triangles can vary greatly in shape and size, but all possess some inherent properties that make area calculations possible.
These include the relationships among the sides and angles, and the concept of a perimeter. For this discussion, it is vital to understand that regardless of the specific type of triangle—be it equilateral, isosceles, or scalene—the properties used in Heron's formula sum up the triangle's whole perimeter initially, which then transitions into a semi-perimeter for further calculations.
The symmetry and form of triangles make them uniquely simple but endlessly useful in geometry and trigonometry.
These include the relationships among the sides and angles, and the concept of a perimeter. For this discussion, it is vital to understand that regardless of the specific type of triangle—be it equilateral, isosceles, or scalene—the properties used in Heron's formula sum up the triangle's whole perimeter initially, which then transitions into a semi-perimeter for further calculations.
The symmetry and form of triangles make them uniquely simple but endlessly useful in geometry and trigonometry.
Area Calculation Using Heron's Formula
Once the semi-perimeter \(s\) of a triangle is known, you can use Heron's formula to calculate the area. This allows you to find the area without needing the height, which is typically required in other area calculations.
The formula is:\[A = \sqrt{s \cdot (s - a) \cdot (s - b) \cdot (s - c)}\]Here are the steps to compute the area using Heron's formula:
This method is efficient and works well for any given triangle's side lengths.
The formula is:\[A = \sqrt{s \cdot (s - a) \cdot (s - b) \cdot (s - c)}\]Here are the steps to compute the area using Heron's formula:
- Compute the semi-perimeter \(s\).
- Subtract each side length from \(s\), giving you the values \((s - a)\), \((s - b)\), and \((s - c)\).
- Multiply these differences with \(s\) (i.e., \(s \cdot (s-a) \cdot (s-b) \cdot (s-c)\)).
- Take the square root of the result to find the area \(A\).
This method is efficient and works well for any given triangle's side lengths.
Other exercises in this chapter
Problem 43
A plane flies 500 kilometers with a bearing of \(316^{\circ}\) (clockwise from north) from Naples to Elgin. The plane then flies 720 kilometers from Elgin to Ca
View solution Problem 44
Determine whether \(\mathbf{u}\) and \(\mathbf{v}\) are orthogonal. $$\begin{aligned} &\mathbf{u}=\langle 12,4\rangle\\\ &\mathbf{v}=\left\langle\frac{1}{4},-\f
View solution Problem 44
Represent the complex number graphically, and find the trigonometric form of the number. $$-3+i$$
View solution Problem 44
A flagpole at a right angle to the horizontal is located on a slope that makes an angle of \(12^{\circ}\) with the horizontal. The flagpole casts a 16 -meter sh
View solution