Problem 44
Question
Use a half-number identity to find an expression for the exact value for each function, given the information about \(x\). $$\cos \frac{x}{2}, \text { given } \sin x=-\frac{4}{5} \text { and } \frac{3 \pi}{2} < x < 2 \pi$$
Step-by-Step Solution
Verified Answer
\(\cos \frac{x}{2} = \sqrt{\frac{4}{5}}\)
1Step 1: Identify the Identity
We need to use the half-angle identity for cosine, which is given by: \[ \cos \frac{x}{2} = \pm \sqrt{\frac{1+\cos x}{2}} \]
2Step 2: Determine the Quadrant of \(x\)
The information given is that \(\frac{3\pi}{2} < x < 2\pi\), which means \(x\) is in the fourth quadrant. In the fourth quadrant, cosine is positive.
3Step 3: Calculate \(\cos x\) Using \(\sin x\)
Since \(\sin x = -\frac{4}{5}\), we can use the Pythagorean identity \( \sin^2 x + \cos^2 x = 1 \). This gives us: \[ \left(-\frac{4}{5}\right)^2 + \cos^2 x = 1 \] solving this, we get \( \cos x = \frac{3}{5} \) as cosine is positive in the fourth quadrant.
4Step 4: Substitute \(\cos x\) into the Half-angle Identity
Substitute \(\cos x = \frac{3}{5}\) into the half-angle identity: \[ \cos \frac{x}{2} = \pm \sqrt{\frac{1 + \frac{3}{5}}{2}} = \pm \sqrt{\frac{8}{10}} = \pm \sqrt{\frac{4}{5}} \]
5Step 5: Determine the Sign of \(\cos \frac{x}{2}\)
Since \(\cos \frac{x}{2}\) is in the first or fourth quadrant when \(\frac{3\pi}{2} < x < 2\pi\), it is positive. Therefore, \( \cos \frac{x}{2} = \sqrt{\frac{4}{5}} \).
Key Concepts
Trigonometric FunctionsPythagorean IdentityUnit CircleQuadrants in Trigonometry
Trigonometric Functions
Trigonometric functions are integral to understanding the relations of angles and sides in triangles. The primary trigonometric functions include sine (\(\sin\)), cosine (\(\cos\)), and tangent (\(\tan\)). Each of these functions can be thought of as a ratio of sides in a right triangle:
- \( \sin = \frac{\text{opposite side}}{\text{hypotenuse}} \)
- \( \cos = \frac{\text{adjacent side}}{\text{hypotenuse}} \)
- \( \tan = \frac{\text{opposite side}}{\text{adjacent side}} \)
Pythagorean Identity
The Pythagorean identity is a fundamental relationship in trigonometry. It arises from the Pythagorean theorem, which deals with right-angled triangles. For any angle \(x\), the Pythagorean identity is given by:
\[ \sin^2 x + \cos^2 x = 1 \]
This identity illustrates how sine and cosine relate to each other. It can be rearranged to find one function if you know the other:
\[ \sin^2 x + \cos^2 x = 1 \]
This identity illustrates how sine and cosine relate to each other. It can be rearranged to find one function if you know the other:
- For \(\sin x\), \(\cos^2 x = 1 - \sin^2 x\)
- For \(\cos x\), \(\sin^2 x = 1 - \cos^2 x\)
Unit Circle
The unit circle is a powerful visual aid in trigonometry. It is a circle with a radius of one, centered at the origin of a coordinate plane. Each point on the unit circle corresponds to an angle in standard position, where the angle's vertex is at the origin. From any point on the unit circle:
- \(x\)-coordinate equals \(\cos \theta\)
- \(y\)-coordinate equals \(\sin \theta\)
Quadrants in Trigonometry
The trigonometric functions change their signs depending on the quadrant in which the angle lies. The coordinate plane is divided into four quadrants:
- 1st Quadrant: Both \(\sin x\) and \(\cos x\) are positive.
- 2nd Quadrant: \(\sin x\) is positive, \(\cos x\) is negative.
- 3rd Quadrant: Both \(\sin x\) and \(\cos x\) are negative.
- 4th Quadrant: \(\sin x\) is negative, \(\cos x\) is positive.
Other exercises in this chapter
Problem 44
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Write expression in terms of sine and cosine, and simplify it. (The final expression does not have to be in terms of sine and cosine.) $$\frac{\tan ^{2} \theta}
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