Problem 44
Question
The standard Gibbs energy change for the reaction $$\mathrm{NH}_{3}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1) \rightleftharpoons \mathrm{NH}_{4}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})$$ is \(29.05 \mathrm{kJ} \mathrm{mol}^{-1}\) at \(298 \mathrm{K}\). Use this thermodynamic quantity to decide in which direction the reaction is spontaneous when the concentrations of \(\mathrm{NH}_{3}(\mathrm{aq})\) \(\mathrm{NH}_{4}^{+}(\mathrm{aq}),\) and \(\mathrm{OH}^{-}(\mathrm{aq})\) are \(0.10 \mathrm{M}, 1.0 \times 10^{-3} \mathrm{M}\) and \(1.0 \times 10^{-3} \mathrm{M},\) respectively.
Step-by-Step Solution
Verified Answer
After comparing \( Q \) and \( K \), the direction of the spontaneous reaction is determined.
1Step 1: Calculation of Equilibrium Constant from Gibbs Energy Change
Using the formula \( \Delta G = -RT \ln K \), where \(\Delta G\) is the standard Gibbs energy change (-29050 J/mol), \(R\) is the universal gas constant (8.314 J/(mol K)), and \(T\) is the temperature (298 K), one isolates \(K\) to find that \( K = \exp(-\Delta G / RT) \).
2Step 2: Calculation of Reaction Quotient
The reaction quotient is defined as \( Q = [NH_{4}^{+}][OH^{-}] / [NH_{3}][H_{2}O] \). As the concentration of water is essentially constant and large, it is usually neglected in the reaction quotient, so it simplifies to \( Q = [NH_{4}^{+}][OH^{-}] / [NH_{3}] \). The provided concentrations are then inserted into \( Q \) to calculate its value.
3Step 3: Determine Spontaneity of Reaction
The spontaneity of the reaction is determined by comparing \( Q \) and \( K \). If \( Q < K \), the reaction will proceed in the forward direction to reach equilibrium, because equilibrium lies to the right. If \( Q > K \), the reverse reaction is spontaneous, as equilibrium lies to the left. If \( Q = K \), the reaction is in equilibrium, and no net change occurs.
Key Concepts
Equilibrium ConstantReaction QuotientSpontaneity of Reactions
Equilibrium Constant
The Equilibrium Constant, represented as \( K \), is a vital concept when discussing chemical reactions and their dynamics. It provides a quantitative measure of the position of equilibrium for a reaction. In thermodynamic terms, the equilibrium constant relates directly to the standard Gibbs free energy change \( (\Delta G^0) \) for the reaction.
To find the equilibrium constant \( K \), we use the formula: \[ \Delta G^0 = -RT \ln K \] where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta G^0 \) is the standard Gibbs free energy change. By rearranging this formula, it allows you to calculate \( K \) as:
To find the equilibrium constant \( K \), we use the formula: \[ \Delta G^0 = -RT \ln K \] where \( R \) is the universal gas constant, \( T \) is the temperature in Kelvin, and \( \Delta G^0 \) is the standard Gibbs free energy change. By rearranging this formula, it allows you to calculate \( K \) as:
- \( K = \exp(-\Delta G^0 / RT) \)
Reaction Quotient
The Reaction Quotient, represented as \( Q \), is a snapshot measurement that tells us what the concentration of reactants and products are at any given moment before a reaction reaches equilibrium. This is useful in predicting which way a reaction will have to go to reach equilibrium.
To compute \( Q \), one must know the concentrations of the products and reactants at that specific moment in time, using the formula:
To compute \( Q \), one must know the concentrations of the products and reactants at that specific moment in time, using the formula:
- \( Q = \frac{[Products]}{[Reactants]} \)
- \( Q = \frac{[\mathrm{NH}_{4}^{+}][\mathrm{OH}^{-}]}{[\mathrm{NH}_{3}]} \)
Spontaneity of Reactions
Spontaneity in reactions is about predicting whether a reaction is naturally favorable towards proceeding in the forward direction. The spontaneity can be deduced by comparing the values of \( Q \), the reaction quotient, and \( K \), the equilibrium constant.
The key considerations when comparing these two values are:
The key considerations when comparing these two values are:
- If \( Q < K \): The reaction will proceed forward to produce more products until equilibrium is achieved.
- If \( Q > K \): The reaction will tend to reverse, forming more reactants until equilibrium is reached.
- If \( Q = K \): The system is at equilibrium and there is no net change in the concentrations of reactants and products.
Other exercises in this chapter
Problem 41
Use thermodynamic data at \(298 \mathrm{K}\) to decide in which direction the reaction $$2 \mathrm{SO}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightleftharp
View solution Problem 43
The standard Gibbs energy change for the reaction \(\mathrm{CH}_{3} \mathrm{CO}_{2} \mathrm{H}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightleftharp
View solution Problem 45
For the reaction \(2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NO}_{2}(\mathrm{g})\) all but one of the following equations i
View solution Problem 46
Why is \(\Delta G^{\circ}\) such an important property of a chemical reaction, even though the reaction is generally carried out under nonstandard conditions?
View solution