Problem 44
Question
The \(\mathrm{Na}^{+}\)present in \(\mathrm{NaCl}\) is (a) acidic radical (b) basic radical (c) neutral radical (d) none of these
Step-by-Step Solution
Verified Answer
The \( \mathrm{Na}^{+} \) in \( \mathrm{NaCl} \) is a basic radical.
1Step 1: Understanding the Problem
We need to classify the nature of the \( \mathrm{Na}^{+} \) ion present in \( \mathrm{NaCl} \) as either acidic, basic, neutral, or none.
2Step 2: Define Radical Types
A radical can be acidic if it typically dissociates to provide \( \mathrm{H}^{+} \) ions in water, basic if it typically dissociates to provide \( \mathrm{OH}^{-} \) ions, and neutral if it does not affect the \( \text{pH} \) of a solution.
3Step 3: Analyze \( \mathrm{NaCl} \) Dissociation
Sodium chloride dissociates in water to form \( \mathrm{Na}^{+} \) and \( \mathrm{Cl}^{-} \) ions. Neither of these ions releases \( \mathrm{H}^{+} \) or \( \mathrm{OH}^{-} \), meaning they do not directly alter the \( \text{pH} \) of the solution.
4Step 4: Identify \( \mathrm{Na}^{+} \) Characteristic
The \( \mathrm{Na}^{+} \) ion does not contribute \( \mathrm{H}^{+} \) or \( \mathrm{OH}^{-} \) ions; hence it is neither acidic nor basic. It pairs with \( \mathrm{Cl}^{-} \) to form neutral compounds like \( \mathrm{NaCl} \).
5Step 5: Determine the Right Answer
Since \( \mathrm{Na}^{+} \) does not affect \( \text{pH} \) and forms a neutral compound with chloride, it is a basic radical according to convention, because it is a positive ion formed from a metal.
Key Concepts
Acidic RadicalsBasic RadicalsNeutral Radicals
Acidic Radicals
Acidic radicals are typically related to the components that lead to the formation of an acid when combined with hydrogen ions. They tend to dissociate in water and produce hydrogen ions (\( \mathrm{H}^+ \)), leading to a decrease in the pH of a solution.
Some common examples of acidic radicals include:
Overall, acidic radicals are non-metal ions or negative ions that help form acids and typically decrease the pH of a solution when dissociated.
Some common examples of acidic radicals include:
- Sulphate (\( \mathrm{SO}_4^{2-} \))
- Nitrate (\( \mathrm{NO}_3^- \))
- Chloride (\( \mathrm{Cl}^- \))
Overall, acidic radicals are non-metal ions or negative ions that help form acids and typically decrease the pH of a solution when dissociated.
Basic Radicals
Basic radicals originate from bases and are usually associated with the release of hydroxide ions (\( \mathrm{OH}^- \)) in water, leading to an increase in pH. These radicals are typically derived from metal elements and are positive ions.
Examples include:
In the case of sodium (\( \mathrm{Na}^+ \)) in sodium chloride (\( \mathrm{NaCl} \)), the \( \mathrm{Na}^+ \) ion does not alter the pH of the solution significantly on its own. However, by convention, it is still considered a basic radical because it originates from a metal that can form bases.
Examples include:
- Sodium (\( \mathrm{Na}^+ \))
- Potassium (\( \mathrm{K}^+ \))
- Calcium (\( \mathrm{Ca}^{2+} \))
In the case of sodium (\( \mathrm{Na}^+ \)) in sodium chloride (\( \mathrm{NaCl} \)), the \( \mathrm{Na}^+ \) ion does not alter the pH of the solution significantly on its own. However, by convention, it is still considered a basic radical because it originates from a metal that can form bases.
Neutral Radicals
Neutral radicals are neither acidic nor basic and tend to have little to no effect on the pH of a solution when dissolved in water. These radicals do not dissociate to release either hydrogen (\( \mathrm{H}^+ \)) or hydroxide (\( \mathrm{OH}^- \)) ions.
Examples of neutral radicals might include certain complex ions or radicals in specific contexts, but typically:
It is important to identify the role of each radical in a chemical reaction to understand its properties fully. Although some radicals might seem neutral in a specific context, their behavior needs to be assessed based on their interactions with other compounds.
Examples of neutral radicals might include certain complex ions or radicals in specific contexts, but typically:
- Inert gases
- Certain organic molecules
It is important to identify the role of each radical in a chemical reaction to understand its properties fully. Although some radicals might seem neutral in a specific context, their behavior needs to be assessed based on their interactions with other compounds.
Other exercises in this chapter
Problem 41
The compound formed in the borax bead test of \(\mathrm{Cu}^{2+}\) ion in oxidizing flame is (a) \(\mathrm{CuBO}_{2}\) (b) \(\mathrm{Cu}\left(\mathrm{BO}_{2}\ri
View solution Problem 42
In borax bead test which compound is formed (a) ortho borate (b) meta borate (c) double oxide (d) tetra borate
View solution Problem 45
In India at the occasion of marriages, the fire works are used, which of the following gives green flame? (a) \(\mathrm{K}\) (b) \(\mathrm{Ba}\) (c) \(\mathrm{B
View solution Problem 46
lons of \(\mathrm{Ca}\), Ba and Sr precipitate in \(\mathrm{V}\) group as their (a) sulphides (b) sulphates (c) oxides (d) carbonates
View solution