Problem 44
Question
Solve for \(x\) and \(y\). $$3\left[\begin{array}{ll}x & y \\ y & x\end{array}\right]=\left[\begin{array}{rr}6 & -9 \\ -9 & 6\end{array}\right]$$
Step-by-Step Solution
Verified Answer
The solution is \(x = 2\) and \(y = -3\).
1Step 1: Write the system of equations
We begin by equating each element of the left matrix with its corresponding element in the right matrix, since the matrices must be equal.The matrix equation is: \[3\begin{bmatrix} x & y \ y & x \end{bmatrix} = \begin{bmatrix} 6 & -9 \ -9 & 6 \end{bmatrix}\]From this, we can derive the individual equations:1. \(3x = 6\)2. \(3y = -9\)3. \(3y = -9\) (This is a repetition and confirms consistency)4. \(3x = 6\) (Another repetition that shows symmetry and consistency)We will solve these equations for \(x\) and \(y\).
2Step 2: Solve for x
Using the equation \(3x = 6\) from Step 1, solve for \(x\):Divide both sides by 3:\[x = \frac{6}{3}\]Therefore,\[x = 2\]
3Step 3: Solve for y
Using the equation \(3y = -9\) from Step 1, solve for \(y\):Divide both sides by 3:\[y = \frac{-9}{3}\]Therefore,\[y = -3\]
4Step 4: Verify the solution
Substitute \(x = 2\) and \(y = -3\) back into the original equations to ensure consistency.\[3\begin{bmatrix} 2 & -3 \ -3 & 2 \end{bmatrix} = \begin{bmatrix} 6 & -9 \ -9 & 6 \end{bmatrix}\]Calculate the left matrix by multiplying each element by 3:\[\begin{bmatrix}3 \times 2 & 3 \times (-3) \3 \times (-3) & 3 \times 2\end{bmatrix} = \begin{bmatrix} 6 & -9 \ -9 & 6 \end{bmatrix}\]Both sides match, confirming that \(x = 2\) and \(y = -3\) is correct.
Key Concepts
Solving Systems of EquationsMatrix EqualityElementwise Operations
Solving Systems of Equations
When faced with a system of equations, you are essentially dealing with multiple equations simultaneously. These equations often contain more than one variable, and the goal is to find values for these variables that satisfy all equations in the system. In the context of matrices, solving systems of equations becomes visually intuitive because each entry in the matrix corresponds to an equation derived from the equality of matrices.
For instance, in the exercise, we have a matrix equation that provides us two distinct equations when we equate each element from the resulting matrix:
For instance, in the exercise, we have a matrix equation that provides us two distinct equations when we equate each element from the resulting matrix:
- For the first equation, the upper-left elements are taken: \(3x = 6\).
- The second equation, derived from the upper-right (and confirmed by lower-left) elements, is \(3y = -9\).
Matrix Equality
Matrix equality is a fundamental concept which states that two matrices are equal if and only if each corresponding element in the matrices is identical. This can be visualized by comparing both matrices side-by-side and ensuring that every element at each position matches.
In the exercise, matrix equality provided the system of equations to be solved. The matrix on the left needs to be equal to the matrix on the right for the given equation to hold true. Each element comparison gave rise to a separate equation:
In the exercise, matrix equality provided the system of equations to be solved. The matrix on the left needs to be equal to the matrix on the right for the given equation to hold true. Each element comparison gave rise to a separate equation:
- Comparing top left, \(3x\) must equal 6.
- And from both the top right and bottom left, \(3y\) must equal -9.
Elementwise Operations
Elementwise operations in matrices involve executing arithmetic operations such as addition, subtraction, or multiplication on corresponding elements across matrices. For any operation to be applicable, two matrices need to be of the same dimension.
In our example, we deal specifically with elementwise multiplication during matrix scaling. The matrix on the left is being scaled by multiplying each of its elements by 3, which must then align elementwise with the matrix on the right for the equation to hold true:
In our example, we deal specifically with elementwise multiplication during matrix scaling. The matrix on the left is being scaled by multiplying each of its elements by 3, which must then align elementwise with the matrix on the right for the equation to hold true:
- Top left element: \(3 \times x = 6\)
- Top right and bottom left elements: \(3 \times y = -9\)
- Bottom right element: \(3 \times x = 6\), which is consistent with the top left element.
Other exercises in this chapter
Problem 43
Determine whether the system of linear equations is inconsistent or dependent. If it is dependent, find the complete solution. $$\left\\{\begin{aligned} x-y+3 z
View solution Problem 44
$$\left\\{\begin{array}{r} x>0 \\ y>0 \\ x+y9 \end{array}\right.$$
View solution Problem 44
Use Cramer's Rule to solve the system. $$\left\\{\begin{array}{l} \frac{1}{2} x+\frac{1}{3} y=1 \\ \frac{1}{4} x-\frac{1}{6} y=-\frac{3}{2} \end{array}\right.$$
View solution Problem 44
Solve the system, or show that it has no solution. If the system has infinitely many solutions, express them in the ordered-pair form given in Example 6. $$\lef
View solution