Problem 44
Question
Solve each exponential equation. Express the solution set in terms of natural logarithms or common logarithms. Then use a calculator to obtain a decimal approximation, correct to two decimal places, for the solution. $$e^{2 x}-2 e^{x}-3=0$$
Step-by-Step Solution
Verified Answer
The solution to the exponential equation is \(x = \ln3\) or in decimal form, \(x \approx 1.10\).
1Step 1 Title: Recognize the Form
The equation \(e^{2 x}-2 e^{x}-3=0\) can be seen as an expression similar to a quadratic equation, if you set \(u=e^x\). Then, the equation will be in the form \(u^2 -2u- 3 = 0\).
2Step 2 Title: Convert Into Quadratic Equation
Substitute \(u=e^x\) into the equation, which gives \(u^2 -2u -3= 0\).
3Step 3 Title: Solve Quadratic Equation
Solving for \(u\), using the quadratic formula \(u = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), we get \(u = 3\) and \(u = -1\).
4Step 4 Title: Convert Back to Original Variable
Substitute \(e^x\) back in for \(u\), giving \(e^x = 3\) and \(e^x = -1\). Note that there are no solutions for \(e^x = -1\) as the exponential function is always positive.
5Step 5 Title: Solve for the Natural Logarithms
Given \(e^x = 3\), taking the natural logarithm on both sides of the equation gives \(x = \ln3\). Please note that natural log (ln) is the inverse of the exponential function.
6Step 6 Title: Obtain Decimal Approximation
Using a calculator, \(\ln3\) is approximately 1.10, correct to two decimal places.
7Step 7 Title: Formulate the Solution Set
The solution set, in terms of natural logarithms, of the exponential equation is \(x = \ln3\), and the decimal approximation is \(x = 1.10\).
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