Problem 44
Question
Solution of the equation \(\frac{d y}{d x}=e^{x-y}\left(e^{x}-e^{y}\right)\) is (A) \(e^{y}=e^{x}-1+c e^{-e^{\prime}}\) (B) \(e^{y}=e^{x}-1+c e^{e^{*}}\) (C) \(e^{x}=e^{y}-1+c e^{-e^{\prime}}\) (D) None of these
Step-by-Step Solution
Verified Answer
The differential equation solution isn't directly solvable into given forms; hence (D) None of these is plausible.
1Step 1: Identify the Differential Equation Type
The given differential equation is \( \frac{d y}{d x}=e^{x-y}(e^{x}-e^{y}) \). This is a first-order differential equation and looks separable as we can express the terms involving \( y \) on one side and \( x \) on the other.
2Step 2: Separate Variables
Rewrite the equation to separate the variables. Start by expressing as:\[ \frac{d y}{d x} = e^{x}e^{-y} \cdot (e^x - e^y) \]This simplifies the equation to try and get all \( y \)-terms on one side and \( x \)-terms on the other.
3Step 3: Simplify and Integrate
Attempt to express it in the form \( M(x)dx + N(y)dy = 0 \).From the separation: \( e^{y} dy = e^xe^{-y} (e^x - e^y) dx \), simplify to integral terms. Though tricky, initial approach would use algebraic manipulation to bring into standard form before integrating.
4Step 4: Verify Separability with Incorrect Attempts
With complex forms, errors suggest misinterpretation. Checking option offers insight:Using potential identity can caution off confirming options such as if \( e^y = e^x - 1 + ce^{-e'} \) satisfy base rearranged states substituting back fully aligns with study enjoy!
Key Concepts
Variable Separable MethodIntegrationAlgebraic Manipulation
Variable Separable Method
In solving first-order differential equations, one effective strategy is the variable separable method. This technique is most useful when we can express the equation in a way that the variables can stand alone on each side of the equation.
The main idea is to rearrange the equation such that:
Once separation is complete, the equation turns into an ideal candidate for integration, thus transitioning us to the next fundamental step.
The main idea is to rearrange the equation such that:
- All terms involving the dependent variable (e.g., \( y \)) are on one side
- All terms involving the independent variable (e.g., \( x \)) are on the other side
Once separation is complete, the equation turns into an ideal candidate for integration, thus transitioning us to the next fundamental step.
Integration
After successfully separating the variables, the next crucial step is integration. This mathematical process allows us to solve for the general solution of the differential equation.
In its essence, integration is the operation of finding the integral of a function—a reverse of differentiation. Once the variables are separated, integrating each side with respect to their respective variable is essential.
In its essence, integration is the operation of finding the integral of a function—a reverse of differentiation. Once the variables are separated, integrating each side with respect to their respective variable is essential.
- The left side of the equation, concerning the dependent variable, will be integrated with respect to \( y \)
- The right side, involving the independent variable, will be integrated with respect to \( x \)
Algebraic Manipulation
Even after separating variables and integrating, algebraic manipulation remains key in simplifying and solving the equation.
Once the integrations are done, it might result in a complicated expression, which requires careful handling to isolate the desired variable. This involves simplifying expressions, performing algebraic operations, and sometimes assuming initial conditions or known values to find the constant of integration.
Once the integrations are done, it might result in a complicated expression, which requires careful handling to isolate the desired variable. This involves simplifying expressions, performing algebraic operations, and sometimes assuming initial conditions or known values to find the constant of integration.
- Rewriting expressions to achieve a clear form
- Applying identities or rearrangements to verify the solution
- Utilizing known functions or properties to further simplify results
Other exercises in this chapter
Problem 41
The general solution of the differential equation \(\frac{d y}{d x}+y g^{\prime}(x)=g(x) \cdot g^{\prime}(x)\) where \(g(x)\) is a given function of \(x\), is (
View solution Problem 43
Solution of the equation \(x d y=\left(y+x \frac{f(y / x)}{f^{\prime}(y / x)}\right) d x\) is (A) \(f\left(\frac{x}{y}\right)=c y\) (B) \(f\left(\frac{y}{x}\rig
View solution Problem 45
Solution of the equation \(x\left(\frac{d y}{d x}\right)^{2}+(y-x) \frac{d y}{d x}-y\) \(=0\) is (A) \((x-y+c)(x y-c)=0\) (B) \((x+y+c)(x y-c)=0\) (C) \((x-y+c)
View solution Problem 46
The differential equation of the family of general circles is (A) \(y^{\prime \prime \prime}\left(1+y^{\prime 2}\right)-3 y^{\prime} y^{\prime \prime 2}=0\) (B)
View solution