Problem 44
Question
Simplify. See Examples 3 and 4 $$ \sqrt[5]{32 z^{12}} $$
Step-by-Step Solution
Verified Answer
\( 2z^2 \sqrt[5]{z^2} \)
1Step 1: Understand the Problem
We need to simplify the expression \( \sqrt[5]{32z^{12}} \). This means finding the fifth root of the product \( 32z^{12} \), which simplifies the expression under the radical sign.
2Step 2: Simplify the Radicand
The expression inside the radical is \( 32z^{12} \). We can express 32 as \( 2^5 \) because 32 is \( 2 \times 2 \times 2 \times 2 \times 2 \). Thus, the expression becomes \( \sqrt[5]{2^5 z^{12}} \).
3Step 3: Apply the Fifth Root
Since the fifth root of \( 2^5 \) is 2, we can simplify \( \sqrt[5]{2^5} \) to 2. This reduces the expression to \( 2 \cdot \sqrt[5]{z^{12}} \).
4Step 4: Apply the Root to the Variable Part
For \( z^{12} \), we find the fifth root, which involves dividing the exponent by 5: \( (z^{12})^{1/5} = z^{12/5} \). To express this as an integer power and a remainder, we rewrite \( z^{12/5} \) as \( z^2 \cdot z^{2/5} \).
5Step 5: Combine Results
The simplified expression is the product of the constants and remaining radical: \( 2z^2 \sqrt[5]{z^2} \). This is our simplified form of the original expression.
Key Concepts
Fifth RootsExponent RulesRadicals in Algebra
Fifth Roots
In algebra, a "fifth root" refers to a number, which when multiplied by itself five times, returns the original number under the radical sign. For example, the fifth root of 32 is 2 because \(2^5 = 32\). Understanding roots is essential in simplifying expressions like \(\sqrt[5]{32z^{12}}\). To approach this concept, first identify numbers and variables under the radical sign.
- Determine if the number can be expressed as a power of another number, such as rewriting 32 as \(2^5\).
- Similarly, examine the variable part, like \(z^{12}\) in the expression, for simplification.
Exponent Rules
Understanding exponent rules is crucial for simplifying expressions such as \(\sqrt[5]{32z^{12}}\). Exponents provide a way to express repeated multiplication compactly. For instance, \(z^{12}\) signifies multiplying \(z\) by itself twelve times.
To simplify radical expressions involving exponents, it is essential to apply the property \[(x^a)^{1/b} = x^{a/b}\]This formula helps in rewriting radicals as fractional exponents, which then aids in simplification.
In our example, \((z^{12})^{1/5} = z^{12/5}\). Often, this fractional exponent can be split into an integer part and a remainder, such as rewriting \(z^{12/5}\) as \[z^2 \cdot z^{2/5}\]By understanding these rules, you can break down complex radical expressions into simpler parts.
To simplify radical expressions involving exponents, it is essential to apply the property \[(x^a)^{1/b} = x^{a/b}\]This formula helps in rewriting radicals as fractional exponents, which then aids in simplification.
In our example, \((z^{12})^{1/5} = z^{12/5}\). Often, this fractional exponent can be split into an integer part and a remainder, such as rewriting \(z^{12/5}\) as \[z^2 \cdot z^{2/5}\]By understanding these rules, you can break down complex radical expressions into simpler parts.
Radicals in Algebra
Radicals play a significant role in algebra by simplifying expressions and solving equations that involve roots. The expression \(\sqrt[5]{32z^{12}}\) contains a radical, which represents the process of taking a root - in this case, the fifth root.When simplifying expressions with radicals, it’s helpful to:
- Express numbers and variables under the radical as a power of another number or variable, as seen with 32 and \(z^{12}\).
- Apply the correct root to both numerical and variable components.
Other exercises in this chapter
Problem 44
Rationalize each denominator. See Example 4. $$ \frac{-8}{\sqrt{y}+4} $$
View solution Problem 44
Add or subtract. $$ \frac{\sqrt[3]{y^{5}}}{8}+\frac{5 y \sqrt[3]{y^{2}}}{4} $$
View solution Problem 45
Simplify. Assume that the variables represent any real number. $$ \sqrt[3]{(-8)^{3}} $$
View solution Problem 45
Solve. \(\sqrt{2 x-1}=\sqrt{1-2 x}\)
View solution