Problem 44
Question
Show that if \(\sum a_{2}\) is absolutely convergent and \(\left|b_{k}\right| \leq\left|a_{k}\right|\) for at \(J k,\) then \(\sum b_{k}\) is absolutely convergent.
Step-by-Step Solution
Verified Answer
Since \(\sum \left| a_k \right|\) is absolutely convergent and \(\left|b_{k}\right| \leq\left|a_{k}\right|\) for all \(k\), by the Comparison Test, it follows that the series \(\sum b_k\) and \(\sum |b_k|\) must also be convergent. Thus, \(\sum b_{k}\) is absolutely convergent.
1Step 1: Find the absolute values of the series
Since we are dealing with an absolutely convergent series, we first need to find the absolute values of both series, that is:
\[\sum\left|a_k\right|\]
and
\[\sum\left|b_k\right|\]
2Step 2: Apply the Comparison Test
Given the inequality \(\left| b_{k} \right| \leq \left| a_{k} \right|\) for all \(k\), we can now apply the Comparison Test:
Since \(\sum \left| a_k \right|\) is absolutely convergent and \(\left|b_{k}\right| \leq\left|a_{k}\right|\) for all \(k\), by the Comparison Test, it follows that the series \(\sum b_k\) must also be convergent, which means that \(\sum b_k\) is also absolutely convergent since it implies that also \(\sum |b_k|\) converges.
3Step 3: Conclusion
Based on Steps 1 and 2, we have now shown that if \(\sum a_{k}\) is absolutely convergent and \(\left| b_{k} \right| \leq \left| a_{k} \right|\) for at \(J k\), then the series \(\sum b_{k}\) is absolutely convergent.
Key Concepts
Comparison TestConvergent SeriesInequality in Series
Comparison Test
The Comparison Test is a powerful tool used to determine the convergence of series. It involves comparing the series in question with another series that is already known to be convergent or divergent. Here's how it works:
If you have two series, say \( \sum a_k \) and \( \sum b_k \), and you know that \( |b_k| \leq |a_k| \) for all terms \(k\) beyond a certain point, then the behavior of \( \sum b_k \) can be inferred from \( \sum a_k \). This is especially useful when \( \sum a_k \) is a series we understand well.
Applying to absolute convergence, if \( \sum |a_k| \) is a known absolutely convergent series, and we have \( |b_k| \leq |a_k| \) for all \(k\), then by the Comparison Test, it follows that \( \sum |b_k| \) is also convergent. This implies that \( \sum b_k \) is absolutely convergent. Thus, the Comparison Test allows transferring the convergence property from one series to another under given inequalities.
If you have two series, say \( \sum a_k \) and \( \sum b_k \), and you know that \( |b_k| \leq |a_k| \) for all terms \(k\) beyond a certain point, then the behavior of \( \sum b_k \) can be inferred from \( \sum a_k \). This is especially useful when \( \sum a_k \) is a series we understand well.
Applying to absolute convergence, if \( \sum |a_k| \) is a known absolutely convergent series, and we have \( |b_k| \leq |a_k| \) for all \(k\), then by the Comparison Test, it follows that \( \sum |b_k| \) is also convergent. This implies that \( \sum b_k \) is absolutely convergent. Thus, the Comparison Test allows transferring the convergence property from one series to another under given inequalities.
Convergent Series
A convergent series is a series whose terms approach a specific number as more terms are added, meaning that the series sum approaches a finite limit. For example, the series \( \sum a_k \) is said to be convergent if the sequence of partial sums \( S_N = a_1 + a_2 + \cdots + a_N \) gets arbitrarily close to some number \( L \) as \( N o \infty \).
In the case of absolute convergence, a series \( \sum a_k \) is absolutely convergent if the series of absolute values \( \sum |a_k| \) is convergent. This is a stronger condition than regular convergence.
In the case of absolute convergence, a series \( \sum a_k \) is absolutely convergent if the series of absolute values \( \sum |a_k| \) is convergent. This is a stronger condition than regular convergence.
- When we have absolute convergence, any rearrangement of the series will also converge to the same limit.
- Absolute convergence guarantees the series is consistent and stable in terms of its limiting behavior.
Inequality in Series
Inequality plays a critical role in comparing series to judge their convergence properties through tests like the Comparison Test. For two sequences \( \{a_k\} \) and \( \{b_k\} \), knowing the inequality \( |b_k| \leq |a_k| \) for each term \(k\) provides foundational information to apply the Comparison Test.
Here's why the inequality is essential:
Here's why the inequality is essential:
- The inequality helps establish an upper bound for the sequence \( \{b_k\} \) by comparing it to the sequence \( \{a_k\} \), which possesses known convergence properties (e.g., absolute convergence in \( \sum |a_k| \)).
- It directs us to assess whether the sum of series \( \sum b_k \) might inherit convergence properties from the better-known series \( \sum a_k \).
Other exercises in this chapter
Problem 44
Set \(f(x)=\frac{e^{x}-1}{x}\) (a) Expand \(f(x)\) in a power series. (b) Integrate the series and show that .$$\sum_{n=1}^{\infty} \frac{n}{(n+1) !}=1$$
View solution Problem 44
Let \(r>0\) be arbitrary. Give an example of a power series \(\sum a_{k} x^{k}\) with radius of convergence \(r\)
View solution Problem 45
(a) Show that if \(\sum a_{\underline{f}}\) is absolutely convergent, then \(\sum a_{k}^{2}\) is convergent. (b) Show by means of an example that the converse o
View solution Problem 45
Let \(P_{n}\) be the \(n\) th Taylor polynomial for the function $$f(x)=\ln (1+x)$$ Find the least integer \(n\) for which: (a) \(P_{n}(0.5)\) approximates in 1
View solution