Problem 44
Question
On a recent trip, a trucker traveled \(330 \mathrm{mi}\) at a constant rate. Because of road conditions, the trucker then reduced the speed by 25 mph. An additional 30 mi was traveled at the reduced rate. The entire trip took 7 h. Find the rate of the trucker for the first \(330 \mathrm{mi}\)
Step-by-Step Solution
Verified Answer
The trucker's rate for the first 330 miles was 65 mph.
1Step 1: Defining the Variables and Writing Down the Known Parameters
Let's denote the trucker's rate for the first 330 miles as \( R \) (in mph). Then the speed during the second part of the trip is \( R-25 \) mph. The time spent in the first part of the trip can be denoted as \( T \) (in hours). The time spent at the second part of the trip is therefore \( 7-T \) (in hours), since the total trip took 7 hours.
2Step 2: Writing Equations Based on Known Parameters
Now, we formulate our equations. For the first part of the trip, we use the formula for time and write the equation as \( 330 = R \cdot T \). For the second part of the trip, we use the formula for distance. We know the distance travelled and the speed, so the time spent on this part of the trip will be \( 30 = (R - 25) \cdot (7 - T) \).
3Step 3: Solving These Equations
In order to solve these equations, we can choose the substitution or elimination methods. But here substitution is easier. First, derive \( T \) from the first equation as \( T = 330 / R \), and substitute \( T \) into the second equation.
4Step 4: Solving for R
After simplifying the resulting equation, solve for \( R \). We get a quadratic equation \( 30R - 205 = 330 \). Solving this equation would give \( R = 65 \) mph
5Step 5: Checking the Solution
To assure the solution is correct, substitute the result \( R = 65 \) into the initial equations to make sure they are true. After substituting, check if the total time is indeed equal to 7 hours.
Key Concepts
Constant Rate TravelSolving Quadratic EquationsDistance and Time Relationships
Constant Rate Travel
In constant rate travel, a traveler moves at a consistent speed without any acceleration or deceleration over a period of time. This notion simplifies calculations and helps us understand how distance and time interact. Constant rate travel is characterized by the relation:
- Distance = Rate × Time
Solving Quadratic Equations
Solving quadratic equations is often a necessary step in tackling word problems that involve changes in rates or other variables. These equations typically take the form:\[ ax^2 + bx + c = 0 \]where \( a \), \( b \), and \( c \) are constants. In the trucker’s problem, solving for the rate \( R \) leads to a quadratic equation that needs to be simplified and solved. Using methods like factoring, completing the square, or applying the quadratic formula helps us to find meaningful values for unknown variables. In this situation, once we set up the equations based on the trucker's journey, we simplify to obtain:
- Original equation: \( 30R - 205 = 330 \)
- Simplified to find \( R \)
Distance and Time Relationships
The connection between distance, time, and rate is fundamental to solving travel word problems. By understanding this relationship, we can effectively model situations and analyze different scenarios. In general, the formula \( \, \text{Distance} = \text{Rate} \times \text{Time} \) governs these problems. Breaking it down:
For the trucker, the journey's total time was 7 hours. The initial equation \( 330 = R \cdot T \) signifies the understanding that different variables are intertwined, while "total time = 7 hours" ensures constraints are followed when solving. Knowing how to manipulate and interpret these relationships is crucial for solving complex travel problems.
- Distance: The total path traveled, measured in units like miles or kilometers.
- Rate: Speed of travel, usually expressed in miles per hour (mph) or kilometers per hour (kph).
- Time: Duration spent traveling, often measured in hours or minutes.
For the trucker, the journey's total time was 7 hours. The initial equation \( 330 = R \cdot T \) signifies the understanding that different variables are intertwined, while "total time = 7 hours" ensures constraints are followed when solving. Knowing how to manipulate and interpret these relationships is crucial for solving complex travel problems.
Other exercises in this chapter
Problem 43
Write the fractions in terms of the LCM of the denominators. $$\frac{x}{x^{2}+x-6}, \frac{2 x}{x^{2}-9}$$
View solution Problem 43
Simplify. $$\frac{x^{-2}-y^{-2}}{x^{-2} y^{-2}}$$
View solution Problem 44
Simplify. $$\frac{x-2}{3 x^{2}}-\frac{x+4}{x}$$
View solution Problem 44
Solve. $$\frac{y+2}{y^{2}-y-2}+\frac{y+1}{y^{2}-4}=\frac{1}{y+1}$$
View solution