Problem 44
Question
$$\left\\{\begin{array}{r} x>0 \\ y>0 \\ x+y<10 \\ x^{2}+y^{2}>9 \end{array}\right.$$
Step-by-Step Solution
Verified Answer
Points within the first quadrant, below \( x + y = 10 \), and outside the circle \( x^2 + y^2 = 9 \).
1Step 1: Analyze the Inequalities
We have a system of four inequalities: 1. \( x > 0 \) which means \( x \) is a positive number. 2. \( y > 0 \) meaning \( y \) is also a positive number. 3. \( x + y < 10 \) which restricts the sum of \( x \) and \( y \) to be less than 10. 4. \( x^2 + y^2 > 9 \) indicating that the sum of their squares is more than 9.
2Step 2: Understand the Region Defined by x + y < 10
The inequality \( x + y < 10 \) describes a region in the coordinate plane. This is a half-plane below the line \( x + y = 10 \), excluding the line itself. Since \( x > 0 \) and \( y > 0 \), we are interested in the first quadrant (where both \( x \) and \( y \) are positive).
3Step 3: Visualize x^2 + y^2 > 9
The inequality \( x^2 + y^2 > 9 \) represents the region outside the circle centered at the origin with radius 3. Any point (\( x, y \)) satisfying this inequality lies strictly outside this circle.
4Step 4: Find the Intersection of Regions
The solution to the system consists of points where all conditions are satisfied simultaneously: - Positive \( x \) and \( y \), - The line \( x + y = 10 \) creates a boundary, and - Points lie outside the circle with radius 3. By visualizing, notes that these conditions form a region that is in the first quadrant, below the 10 line, and outside the circle.
Key Concepts
Coordinate PlaneQuadrantAlgebraic Inequalities
Coordinate Plane
The coordinate plane is a central concept in algebra and geometry. It is a flat surface designed for plotting points, lines, and curves. You can think of it as a giant grid divided into four sections by two perpendicular lines called axes. These axes are labeled as the x-axis (horizontal) and the y-axis (vertical).
Here's how you use it:
Here's how you use it:
- The intersection of the x-axis and y-axis is called the origin, often labeled as the point \( (0, 0) \).
- Coordinates are written as pairs \( (x, y) \) and indicate specific locations on the plane.
- The x-coordinate tells how far to move horizontally from the origin, while the y-coordinate tells how far to move vertically.
Quadrant
The coordinate plane is divided into four parts, known as quadrants, each with its unique properties. Quadrants help categorize points based on their x and y coordinates:
- First Quadrant: Both x and y are positive, \( (x > 0, y > 0) \).
- Second Quadrant: x is negative while y is positive, \( (x < 0, y > 0) \).
- Third Quadrant: Both x and y are negative, \( (x < 0, y < 0) \).
- Fourth Quadrant: x is positive and y is negative, \( (x > 0, y < 0) \).
Algebraic Inequalities
Algebraic inequalities are expressions involving variables, constants, and inequality signs like \( >, <, \leq, \geq \). They define ranges of values rather than exact numbers, offering flexibility in solutions.
Each inequality in a system contributes to the shape and extent of the solution space. Here's how they work in practice:
Each inequality in a system contributes to the shape and extent of the solution space. Here's how they work in practice:
- Inequality \( x > 0 \): This simply indicates that x must be positive. Graphically, this covers the right side of the y-axis.
- Inequality \( y > 0 \): Similarly, y must be positive, covering the area above the x-axis.
- Inequality \( x + y < 10 \): This forms a boundary with points below the line \( x + y = 10 \).
- Inequality \( x^2 + y^2 > 9 \): This defines an area outside a circle of radius 3 centered at the origin, keeping solutions away from the origin.
Other exercises in this chapter
Problem 43
Find the partial fraction decomposition of the rational function. $$\frac{x^{5}-2 x^{4}+x^{3}+x+5}{x^{3}-2 x^{2}+x-2}$$
View solution Problem 43
Determine whether the system of linear equations is inconsistent or dependent. If it is dependent, find the complete solution. $$\left\\{\begin{aligned} x-y+3 z
View solution Problem 44
Solve for \(x\) and \(y\). $$3\left[\begin{array}{ll}x & y \\ y & x\end{array}\right]=\left[\begin{array}{rr}6 & -9 \\ -9 & 6\end{array}\right]$$
View solution Problem 44
Use Cramer's Rule to solve the system. $$\left\\{\begin{array}{l} \frac{1}{2} x+\frac{1}{3} y=1 \\ \frac{1}{4} x-\frac{1}{6} y=-\frac{3}{2} \end{array}\right.$$
View solution