Problem 44
Question
Inventory Management The annual inventory cost for a manufacturer is given by \(C=1,008,000 / Q+6.3 Q\) where \(Q\) is the order size when the inventory is replenished. Find the change in annual cost when \(Q\) is increased from 350 to \(351,\) and compare this with the instantaneous rate of change when \(Q=350 .\)
Step-by-Step Solution
Verified Answer
This task involves the analysis of the change in cost when \(Q\) is increased from 350 to 351 and comparing this with the instantaneous rate of change of the cost function at \(Q = 350\). After performing these calculations, the comparison provides insight into how closely the actual change in cost for a small increase in \(Q\) matches the rate of change predicted by the derivative at \(Q = 350\).
1Step 1: Identify the Function
The first step is to recognize the given function. The annual inventory cost \(C\) depends on the order size \(Q\) and is given by \(C = 1,008,000/Q + 6.3Q\). This will be the function to differentiate.
2Step 2: Calculate the Change in Cost
Next, the change in cost when \(Q\) is increased from \(Q = 350\) to \(Q = 351\) needs to be calculated. First, determine the cost for \(Q = 350\) and \(Q = 351\), and then subtract the cost for \(Q = 350\) from the cost for \(Q = 351\) to find the change in cost.
3Step 3: Compute the Derivative of the Cost Function
Then the instantaneous rate of change of the cost function at \(Q=350\) is required. This involves calculating the derivative of the function \(C(Q) = 1,008,000/Q + 6.3Q\) with respect to \(Q\) and then evaluating this derivative at \(Q=350\).\nThe derivative of a function provides the rate of change of the function at a specific point. This will give the instantaneous rate of change of the cost when the order size is 350.
4Step 4: Compare the Results
The final step is to compare the change in cost obtained in Step 2 with the instantaneous rate of change obtained in Step 3. This involves just a simple comparison of the two values. This will give a sense of how the cost changes with small increments in \(Q\) around \(Q = 350\).
Key Concepts
Inventory Management in CalculusDerivative of a FunctionChange in Cost CalculationOptimizing Order Size
Inventory Management in Calculus
Understanding how calculus plays a crucial role in inventory management is essential in the fields of operations and business optimization. In this context, calculus helps in determining the best order size that minimizes inventory costs. Inventory costs typically include storage, holding, and ordering costs. A well-known formula for inventory management is the Economic Order Quantity (EOQ) model, which provides a method to calculate the optimum number of units that a company should add to inventory with each order to minimize total costs.
When considering the function for the annual inventory cost, such as the given function \(C = 1,008,000/Q + 6.3Q\), calculus enters the fray by allowing us to find the optimal point, where the total cost would be the least. This is done by finding the derivative (the rate of change) of the cost function and determining where this derivative is zero, indicating a minimum cost. Clearly, it is essential to understand how to manipulate and derive functions in order to utilize calculus effectively for inventory management.
When considering the function for the annual inventory cost, such as the given function \(C = 1,008,000/Q + 6.3Q\), calculus enters the fray by allowing us to find the optimal point, where the total cost would be the least. This is done by finding the derivative (the rate of change) of the cost function and determining where this derivative is zero, indicating a minimum cost. Clearly, it is essential to understand how to manipulate and derive functions in order to utilize calculus effectively for inventory management.
Derivative of a Function
The derivative of a function is a fundamental concept in calculus that measures how a function changes as its input changes. In simpler terms, it's the 'rate of change' or 'slope' of a function at any given point. To compute the derivative, we use the rules of differentiation, which include the power rule, product rule, quotient rule, and chain rule among others. For the cost function \(C(Q) = 1,008,000/Q + 6.3Q\), we can apply the power rule and the quotient rule to find the derivative with respect to the order size \(Q\).
Once we've calculated the derivative, we can determine the instantaneous rate of change of the cost relative to small variations in the order size. This information is incredibly valuable, as it informs managers of how sensitive the cost is to changes in order size and can guide in making responsive inventory decisions.
Once we've calculated the derivative, we can determine the instantaneous rate of change of the cost relative to small variations in the order size. This information is incredibly valuable, as it informs managers of how sensitive the cost is to changes in order size and can guide in making responsive inventory decisions.
Change in Cost Calculation
Calculating the change in cost due to adjustments in order size is an integral part of inventory management. For discrete increases in order size, we can simply compute the total cost for two different sizes and then determine the absolute difference between these costs. This provides a tangible figure for the increase or decrease in costs based on the adjustment made.
For instance, to calculate the change in annual cost when order size is increased from 350 to 351 units, one would evaluate the cost function at both quantities and subtract the former from the latter. It is essential in inventory management to understand not only this discrete change but also how costs evolve at a very granular level, for which we use derivatives to compute the instantaneous rate of change.
For instance, to calculate the change in annual cost when order size is increased from 350 to 351 units, one would evaluate the cost function at both quantities and subtract the former from the latter. It is essential in inventory management to understand not only this discrete change but also how costs evolve at a very granular level, for which we use derivatives to compute the instantaneous rate of change.
Optimizing Order Size
Calculating the optimal order size in inventory management ensures that companies maintain a balance between the competing cost factors of ordering and holding inventory. This is where calculus becomes a powerful tool. By utilizing the derivative of the cost function with respect to the order size, we can capture the precise instant when the rate of change of costs switches from decreasing to increasing, which signifies the optimal order level.
In practical terms, once we differentiate the cost function and set the derivative equal to zero, solving for \(Q\) will yield the order size that should minimize costs. This optimized order size is critical for businesses as it can significantly impact profitability. Organizations strive to reach this equilibrium, where each additional unit ordered is as cost-effective as possible, without incurring unnecessary inventory expenses.
In practical terms, once we differentiate the cost function and set the derivative equal to zero, solving for \(Q\) will yield the order size that should minimize costs. This optimized order size is critical for businesses as it can significantly impact profitability. Organizations strive to reach this equilibrium, where each additional unit ordered is as cost-effective as possible, without incurring unnecessary inventory expenses.
Other exercises in this chapter
Problem 43
Find an equation of the tangent line to the graph of \(f\) at the point \((2, f(2)) .\) Use a graphing utility to check your result by graphing the original fun
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Find \(f^{\prime}(x)\) $$ f(x)=\frac{2 x^{2}-3 x+1}{x} $$
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Find the rate of change of \(x\) with respect to \(p .\) \(p=\sqrt{\frac{500-x}{2 x}}, \quad 0
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