Problem 44
Question
In \(38-45,\) find the multiplicative inverse of each of the following in \(a+b i\) form. $$ \frac{5}{6}+3 i $$
Step-by-Step Solution
Verified Answer
The multiplicative inverse is \( \frac{30}{349} - \frac{108}{349}i \).
1Step 1: Understand the formula for the multiplicative inverse
The multiplicative inverse of a complex number \(a + bi\) is given by \(\frac{a}{a^2 + b^2} - \frac{b}{a^2 + b^2}i\). This formula involves multiplying the number by its conjugate and dividing by the magnitude squared.
2Step 2: Identify real and imaginary parts
For the complex number \(\frac{5}{6} + 3i\), identify the real part \(a\) as \(\frac{5}{6}\) and the imaginary part \(b\) as \(3\).
3Step 3: Calculate the magnitude squared
The magnitude squared \(a^2 + b^2\) is calculated as: \[\left(\frac{5}{6}\right)^2 + (3)^2 = \frac{25}{36} + 9 = \frac{25}{36} + \frac{324}{36} = \frac{349}{36}\]
4Step 4: Use the formula to find the multiplicative inverse
The multiplicative inverse is given by:\[ \frac{\frac{5}{6}}{\frac{349}{36}} - \frac{3}{\frac{349}{36}}i \] Simplifying each term:\[ \frac{1}{\frac{349}{36}} = \frac{36}{349} \] Thus:\[ \frac{5}{6} \times \frac{36}{349} = \frac{30}{349} \]\[ 3 \times \frac{36}{349} = \frac{108}{349} \] Resulting in the conjugate:\[ \frac{30}{349} - \frac{108}{349}i \]
5Step 5: Simplify the result
Combine the terms to arrive at the solution in standard form:\[ \frac{30}{349} - \frac{108}{349}i \] This is the multiplicative inverse of \( \frac{5}{6} + 3i \).
Key Concepts
Complex NumbersConjugateMagnitude SquaredReal and Imaginary Parts
Complex Numbers
Complex numbers are fascinating as they extend our number system beyond the familiar real numbers. A complex number is any number that can be written in the form of \( a + bi \), where \( a \) and \( b \) are real numbers, and \( i \) represents the imaginary unit. The imaginary unit, \( i \), is defined by the property \( i^2 = -1 \). This property is what allows us to step into the realm of imaginary numbers, bridging a gap left by the inability to square root negative numbers in the set of real numbers.
A complex number has two distinct parts:
A complex number has two distinct parts:
- The real part: This is denoted by \( a \).
- The imaginary part: This is denoted by \( bi \), where \( b \) is a real number.
Conjugate
The conjugate of a complex number is like its mirror image across the real axis on the complex plane. If you have a complex number \( a + bi \), its conjugate is \( a - bi \).
This simple operation of flipping the sign of the imaginary part helps a lot in complex arithmetic, especially when dividing complex numbers.
This simple operation of flipping the sign of the imaginary part helps a lot in complex arithmetic, especially when dividing complex numbers.
- When you multiply a complex number by its conjugate, the result is a real number.
- This process helps find the magnitude squared of a complex number, which is instrumental in computing its multiplicative inverse.
Magnitude Squared
The magnitude of a complex number is like its length or distance from the origin in the complex plane. To find the magnitude squared of a complex number \( a + bi \), you use the formula \( a^2 + b^2 \).
For the complex number \( \frac{5}{6} + 3i \), the magnitude squared calculation follows these steps:
For the complex number \( \frac{5}{6} + 3i \), the magnitude squared calculation follows these steps:
- Square the real part: \((\frac{5}{6})^2\).
- Square the imaginary part: \(3^2\).
- Add them together to get \( \frac{25}{36} + 9 = \frac{349}{36} \).
Real and Imaginary Parts
The real and imaginary parts are fundamental to understanding complex numbers. Identifying these parts is crucial for performing operations like addition, subtraction, and multiplication.
For example, in the complex number \( \frac{5}{6} + 3i \):
For example, in the complex number \( \frac{5}{6} + 3i \):
- The real part \( a \) is \( \frac{5}{6} \).
- The imaginary part \( b \) is \( 3 \), associated with \( i \).
Other exercises in this chapter
Problem 44
In \(44-51 :\) a. Graph the given inequality. b. Determine if the given point is in the solution set. $$ x^{2} \leq 2 x+y ;(5,4) $$
View solution Problem 44
One root of a quadratic equation is three more than the other. The sum of the roots is 15. Write the equation.
View solution Problem 45
In \(44-51 :\) a. Graph the given inequality. b. Determine if the given point is in the solution set. $$ x^{2}+5 \geq y ;(-1,3) $$
View solution Problem 45
The difference between the roots of a quadratic equation is 4i. The sum of the roots is 12. Write the equation.
View solution