Problem 44
Question
$$ \frac{x-a}{b}=\frac{y-a}{c} \text { for } y $$
Step-by-Step Solution
Verified Answer
\( y = \frac{cx - ac + ab}{b} \)
1Step 1: Cross Multiply
To eliminate the fractions, perform cross multiplication. Multiply the numerator of the first fraction by the denominator of the second and vice versa. This results in \( (x-a)c = (y-a)b \).
2Step 2: Expand the Equation
Distribute the constants across the expressions in parentheses. Expand the equation to obtain \( cx - ac = by - ab \).
3Step 3: Isolate the Term with y
We aim to solve for \( y \). Begin by moving terms not involving \( y \) to the other side of the equation. Add \( ab \) to both sides to get \( cx - ac + ab = by \).
4Step 4: Solve for y
To isolate \( y \), divide every term by \( b \) on both sides of the equation. This gives \( y = \frac{cx - ac + ab}{b} \).
Key Concepts
Cross MultiplicationIsolation of VariablesEquation Expansion
Cross Multiplication
Cross multiplication is a powerful method used to eliminate fractions in equations with two fractions set equal to each other, like in the equation \(\frac{x-a}{b} = \frac{y-a}{c}\). It helps simplify the equation by removing the fractions, making further simplification easier.
To apply cross multiplication, you multiply the numerator of one fraction by the denominator of the other fraction. This technique can be visualized with a crisscross pattern:
To apply cross multiplication, you multiply the numerator of one fraction by the denominator of the other fraction. This technique can be visualized with a crisscross pattern:
- Multiply the numerator of the first fraction, \((x-a)\), by the denominator of the second fraction, \(c\).
- Then, multiply the numerator of the second fraction, \((y-a)\), by the denominator of the first fraction, \(b\).
Isolation of Variables
Isolation of variables is an important technique for solving equations where you need to find the value of one particular variable, such as \(y\) in our example. The goal is to manipulate the equation until you have the variable you're solving for on one side by itself.
Once we have the equation \( cx - ac = by - ab \) after cross multiplying and expanding, we start isolating \(y\):
Divide each term by \( b \), and you get \( y = \frac{cx - ac + ab}{b} \). Now, \(y\) is isolated, and you have solved the equation for \(y\).
Once we have the equation \( cx - ac = by - ab \) after cross multiplying and expanding, we start isolating \(y\):
- First, get all the terms containing \( y \) on one side and the rest on the other side. You can do this by adding \( ab \) to both sides to ensure all terms without \( y \) are cleanly grouped together: \(cx - ac + ab = by \).
Divide each term by \( b \), and you get \( y = \frac{cx - ac + ab}{b} \). Now, \(y\) is isolated, and you have solved the equation for \(y\).
Equation Expansion
Equation expansion involves multiplying out terms that are inside brackets to simplify or eliminate them, making the equation easier to solve. This can help reveal new terms that can be combined or isolated depending on what's needed.
In our solution, following the cross multiplication step, you get \( (x-a)c = (y-a)b \). The next step is to expand these terms by distributing the constants:
In our solution, following the cross multiplication step, you get \( (x-a)c = (y-a)b \). The next step is to expand these terms by distributing the constants:
- Multiply \(c\) by both \(x\) and \(-a\) to obtain \(cx - ac\).
- Similarly, multiply \(b\) by both \(y\) and \(-a\) to get \(by - ab\).
Other exercises in this chapter
Problem 43
$$ \frac{y-a}{b}=\frac{x+b}{c} \text { for } x $$
View solution Problem 44
$$ \sum_{i=1}^{5} 2\left(\frac{1}{3}\right)^{i} \frac{242}{243} $$
View solution Problem 45
Find the sum of each infinite geometric sequence. If the sequence has no sum, so state. \(2,1, \frac{1}{2}, \frac{1}{4}, \ldots\) 4
View solution Problem 45
2+8+14+20+\cdots+146 \quad 1850
View solution