Problem 44
Question
For each of the following pairs, indicate which element has the smaller first ionization energy: (a) Ti, Ba; (b) \(\mathrm{Ag}, \mathrm{Cu}\); (c) \(\mathrm{Ge}, \mathrm{Cl}\); (d) \(\mathrm{Pb}, \mathrm{Sb}\).
Step-by-Step Solution
Verified Answer
In the given pairs, the elements with the smaller first ionization energy are:
(a) Ba (Barium)
(b) Ag (Silver)
(c) Ge (Germanium)
(d) Pb (Lead)
1Step 1: (a) Comparing Ti and Ba
Titanium (Ti) has an atomic number of 22 and is in Period 4 and Group 4 of the periodic table, whereas Barium (Ba) has an atomic number of 56 and is in Period 6 and Group 2. Since Ba is located towards the left and down from Ti in the periodic table, we can conclude that Ba has a larger atomic radius. The larger atomic radius of Ba results in weaker electrostatic attraction between its nucleus and outer electrons, which means it will have a smaller first ionization energy than Ti.
Smaller first ionization energy: Ba
2Step 2: (b) Comparing Ag and Cu
Silver (Ag) has an atomic number of 47 and is in Period 5 and Group 11, whereas Copper (Cu) has an atomic number 29 and is in Period 4 and Group 11. They are both in the same group, meaning they have the same number of valence electrons and similar electronic configurations. However, Ag is in a higher period, which means it has a larger atomic radius. The larger atomic radius of Ag results in weaker electrostatic attraction between its nucleus and outer electrons, which means it will have a smaller first ionization energy than Cu.
Smaller first ionization energy: Ag
3Step 3: (c) Comparing Ge and Cl
Germanium (Ge) has an atomic number of 32 and is in Period 4 and Group 14, whereas Chlorine (Cl) has an atomic number of 17 and is in Period 3 and Group 17. Since Cl is to the right and up from Ge in the periodic table, we can conclude that Cl has a smaller atomic radius. The smaller atomic radius of Cl results in stronger electrostatic attraction between its nucleus and outer electrons, which means it will have a larger first ionization energy than Ge.
Smaller first ionization energy: Ge
4Step 4: (d) Comparing Pb and Sb
Lead (Pb) has an atomic number of 82 and is in Period 6 and Group 14, whereas Antimony (Sb) has an atomic number of 51 and is in Period 5 and Group 15. Pb is located beneath Sb in the periodic table, which means Pb has a larger atomic radius. The larger atomic radius of Pb results in weaker electrostatic attraction between its nucleus and outer electrons, which means it will have a smaller first ionization energy than Sb.
Smaller first ionization energy: Pb
Key Concepts
Atomic RadiusPeriodic TableElectrostatic Attraction
Atomic Radius
The atomic radius of an element is the distance from the nucleus of an atom to the outermost electrons. It is a key factor in understanding various chemical behaviors, such as ionization energy.
Atomic radius generally increases as you move down a group in the periodic table. This is because new electron shells are added, making the atoms larger. As you move across a period from left to right, the atomic radius decreases.
This decrease is due to protons being added to the nucleus, which increases the positive charge and pulls the electrons closer to the nucleus, thereby reducing the size.
Atomic radius generally increases as you move down a group in the periodic table. This is because new electron shells are added, making the atoms larger. As you move across a period from left to right, the atomic radius decreases.
This decrease is due to protons being added to the nucleus, which increases the positive charge and pulls the electrons closer to the nucleus, thereby reducing the size.
- Larger atomic radii are found in elements to the left and at the bottom of the periodic table.
- Elements with larger atomic radii tend to have lower ionization energies because their outer electrons are farther from the nucleus.
Periodic Table
The periodic table is a powerful tool that arranges all the known elements in an informative grid. It not only organizes the elements by increasing atomic number but also groups them by similar chemical properties.
The vertical columns are called groups, and they contain elements with similar valence electron configurations. This means elements within the same group display similar behavior chemically.
Horizontal rows are called periods. As you move across a period from left to right, the number of protons in the nucleus increases, resulting in a stronger attraction between the nucleus and the electrons.
The vertical columns are called groups, and they contain elements with similar valence electron configurations. This means elements within the same group display similar behavior chemically.
Horizontal rows are called periods. As you move across a period from left to right, the number of protons in the nucleus increases, resulting in a stronger attraction between the nucleus and the electrons.
- Moving down a group, each element has an additional electron shell, making the atomic radius larger.
- Elements in the same period have increasing atomic numbers and generally decreasing atomic radii.
Electrostatic Attraction
Electrostatic attraction is the force that holds the electrons close to the nucleus in an atom. This attraction is due to the opposite charges of the positively charged nucleus and the negatively charged electrons.
The strength of this attraction impacts how much energy is needed to remove an electron from an atom, known as ionization energy.
When the atomic radius is large, electrons are farther from the nucleus and experience weaker electrostatic attraction. Conversely, smaller atomic radii lead to stronger attraction, as electrons are closer to the nucleus.
The strength of this attraction impacts how much energy is needed to remove an electron from an atom, known as ionization energy.
When the atomic radius is large, electrons are farther from the nucleus and experience weaker electrostatic attraction. Conversely, smaller atomic radii lead to stronger attraction, as electrons are closer to the nucleus.
- Weaker electrostatic attraction means lower ionization energy, as less energy is needed to remove an outer electron.
- Stronger attraction requires more energy for electron removal, resulting in higher ionization energy.
Other exercises in this chapter
Problem 42
(a) What is the trend in first ionization energies as one proceeds down the group 7A elements? Explain how this trend relates to the variation in atomic radii.
View solution Problem 43
Based on their positions in the periodic table, predict which atom of the following pairs will have the smaller first ionization energy: (a) \(\mathrm{Cl}, \mat
View solution Problem 45
Write the electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Co}^{2+}\), (b) \(\mathrm{Sn}^{2+}\),
View solution Problem 46
Write the electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Ru}^{3+}\), (b) \(\mathrm{As}^{3-}\),
View solution