Problem 44
Question
Find the slope and \(y\) -intercept (if possible) of the line specified by the equation. Then sketch the line. \(2 x+5=0\)
Step-by-Step Solution
Verified Answer
The given line \(2x + 5 = 0\) has an undefined slope, and does not have a y-intercept. The line can be sketched as a vertical line passing through the point -5/2 on the x-axis.
1Step 1: Identify the Type of Line
This equation \(2x + 5 = 0\) represents a vertical line x = -5/2. Vertical lines have an undefined slope as they do not 'rise over run'.
2Step 2: Slope of the Line
A vertical line like the one represented by the given equation does not have a slope, as the concept of rise over run doesn't apply to vertical lines. Hence, the slope is undefined.
3Step 3: y-Intercept of the Line
A vertical line does not intersect the y-axis except when the line is the y-axis itself, so for this equation, there is no y-intercept.
4Step 4: Sketching the Line
To sketch this line, draw a straight, vertical line that passes through the point -5/2 on the x-axis. The line doesn't intersect with the y-axis as expected.
Key Concepts
Understanding SlopeGrasping the Y-InterceptEquation of a Line Basics
Understanding Slope
When we talk about the slope of a line in mathematics, we refer to its steepness or inclination. The slope is calculated as the 'rise' (change in the y-coordinates) divided by the 'run' (change in the x-coordinates). This can be represented by the formula: \[ m = \frac{\Delta y}{\Delta x} \] where \( m \) is the slope. However, it's important to note that vertical lines, such as the one in our original exercise equation \( 2x + 5 = 0 \), have an undefined slope. Why? Because vertical lines do not 'run'; they don't extend horizontally.
- For horizontal lines, the slope is 0.
- For vertical lines, the slope is undefined because they stretch infinitely upwards or downwards without any horizontal movement.
Grasping the Y-Intercept
The y-intercept of a line is the specific point where it crosses the y-axis. This is often denoted as \( (0, b) \) in the linear equation \( y = mx + b \). At this intersection, the value of \( x \) is always zero, which makes it easy to spot on a graph. However, vertical lines such as the one derived from the equation \( 2x + 5 = 0 \) do not have a y-intercept. This is because they aren't crossing the y-axis—rather, they run parallel (or coincidentally with) it. Of course, there's an exception: when the line itself *is* the y-axis, in which case the whole line could be considered as crossing every point on the y-axis. Knowing if a line has a y-intercept is very helpful for graphing and understanding its behavior in the Cartesian coordinate system.
Equation of a Line Basics
The equation of a line, usually written as \( y = mx + b \), is a fundamental aspect of algebra. Here, \( m \) represents the slope, and \( b \) the y-intercept. This form is known as the slope-intercept form and is especially useful for quickly graphing a line. For vertical lines—like the line described by the equation \( 2x + 5 = 0 \)—we use a different approach. This equation can simply be rearranged to \( x = -\frac{5}{2} \), indicating that every point on that line has \( x = -\frac{5}{2} \). This is known as the standard form for a vertical line, and it helps to highlight that such lines do not follow the familiar \( y = mx + b \) format.
- Horizontal lines can be written as \( y = c \).
- Vertical lines are represented as \( x = d \), showing that their nature diverges from the standard slope-intercept form.
Other exercises in this chapter
Problem 44
Sketch the graph of the function and determine whether the function is even, odd, or neither. \(g(t)=\sqrt[3]{t-1}\)
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Check for symmetry with respect to both axes and the origin. \(x^{3} y=1\)
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Find two functions \(f\) and \(g\) such that \((f \circ g)(x)=h(x)\). (There are many correct answers.) \(h(x)=(2 x+1)^{2}\)
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