Problem 44
Question
Express the given function h as a composition of two functions f and g so that \(h(x)=(f \circ g)(x)\) $$h(x)=|3 x-4|$$
Step-by-Step Solution
Verified Answer
The function \(h(x) = |3x - 4|\) can be expressed as a composition: \(h(x) = (f \circ g)(x)\), where \(f(x) = |x|\) and \(g(x) = 3x - 4\).
1Step 1: Identify the operations
The function \(h(x)\) is executing two operations: 1) Multiplying \(x\) by 3 and subtracting 4 (3x - 4), 2) Taking the absolute value. The function \(g(x)\) can be the first operation, and the function \(f(x)\) can be the second operation.
2Step 2: Define the two functions
Let's define the function \(g(x) = 3x - 4\). This is the first operation happening inside the absolute value operation. Then, let's define function \(f(x) = |x|\). This function is taking the absolute value of whatever argument we pass it.
3Step 3: Make sure the composition matches the original function
The composition of the functions is \(f(g(x)) = |3x - 4|\). This is the same as the original function \(h(x)\), so our functions \(f\) and \(g\) form the function \(h\) as a composition.
Key Concepts
Absolute ValueAlgebraic FunctionsComposite Functions
Absolute Value
The absolute value of a number is a fundamental concept in algebra that represents the distance of that number from zero on a number line. This means no matter whether the number is positive or negative, its absolute value is always non-negative.
For example, the absolute value of -5 is 5, and the absolute value of 5 is also 5. Mathematically, it is denoted using vertical bars, like this:
The absolute value function transforms the variable inside it to be non-negative, making it crucial in many areas such as calculus and algebra when dealing with real-world distances or magnitudes. For expressions like \(|3x - 4|\), it ensures the entire expression inside becomes non-negative, which is particularly useful when solving equations where the sign must be considered.
For example, the absolute value of -5 is 5, and the absolute value of 5 is also 5. Mathematically, it is denoted using vertical bars, like this:
- \(|x|\)
The absolute value function transforms the variable inside it to be non-negative, making it crucial in many areas such as calculus and algebra when dealing with real-world distances or magnitudes. For expressions like \(|3x - 4|\), it ensures the entire expression inside becomes non-negative, which is particularly useful when solving equations where the sign must be considered.
Algebraic Functions
Algebraic functions are the building blocks of almost all mathematical expressions that appear in algebra. They consist of polynomial, rational, or root functions, which involve basic arithmetic operations like addition, subtraction, multiplication, division, and taking roots. These are expressed as equations with one or more variables.
A simple algebraic function could be linear, such as
Algebraic functions can become complex, comprising multiple terms and operations, but they retain the essence of mathematical operations that define how inputs are transformed into outputs.
A simple algebraic function could be linear, such as
- \(f(x) = 3x - 4\)
Algebraic functions can become complex, comprising multiple terms and operations, but they retain the essence of mathematical operations that define how inputs are transformed into outputs.
Composite Functions
Composite functions involve combining two or more functions to form a new function. This is represented by the notation
Taking the given problem, we are interested in the composite function
- \((f \circ g)(x) = f(g(x))\)
Taking the given problem, we are interested in the composite function
- \(h(x) = |3x - 4|\)
- \(g(x) = 3x - 4\)
- \(f(x) = |x|\)
Other exercises in this chapter
Problem 44
Begin by graphing the standard cubic function, \(f(x)=x^{3} .\) Then use transformations of this graph to graph the given function. $$ r(x)=(x-2)^{3}+1 $$
View solution Problem 44
Give the slope and y-intercept of each line whose equation is given. Then graph the line. $$y=\frac{3}{4} x-3$$
View solution Problem 44
In Exercises \(33-44\), find and simplify the difference quotient $$\frac{f(x+h)-f(x)}{h}, h \neq 0$$for the given function. $$f(x)=\frac{1}{2 x}$$
View solution Problem 44
Give the center and radius of the circle described by the equation and graph each equation. $$ (x-2)^{2}+(y-3)^{2}=16 $$
View solution