Problem 44
Question
Evaluate the expression for the given value of the variable. \(9(-2)(-r)^{3}\) when \(r=2\)
Step-by-Step Solution
Verified Answer
The evaluated output of the expression \(9(-2)(-r)^{3}\) when \(r=2\) is 144.
1Step 1: Substitute the Given Value
Substitute the given value of 'r' into the expression. So, the expression \(9(-2)(-r)^{3}\) becomes \(9(-2)(-2)^{3}\).
2Step 2: Apply the Power to the Variable
Solve \((-2)^{3}\) first according to the rule of precedence (BIDMAS/BODMAS). This results in \(-8\) . So we update our expression to \(9(-2)(-8)\).
3Step 3: Complete the Multiplication
Complete the multiplication operation for the expression \(9(-2)(-8)\) which gives result as \(144\).
Key Concepts
SubstitutionExponentsOrder of Operations
Substitution
When evaluating mathematical expressions, we often first encounter the concept of **substitution**. Substitution involves replacing a variable in an expression with its given numerical value. In this case, the original expression is given as \(9(-2)(-r)^{3}\) and we know that \(r\) equals 2.
Here's how substitution works step-by-step:
Here's how substitution works step-by-step:
- Identify the variable in the expression, which is \(r\) in our exercise.
- Replace the variable with its assigned numerical value. Since \(r = 2\), wherever there is \(-r\), substitute \(-2\).
- The expression now becomes \(9(-2)(-2)^{3}\). Each occurrence of \(r\) is replaced, simplifying further calculations.
Exponents
An exponent refers to the number of times a number, known as the base, is multiplied by itself. In our example, the expression \((-r)^{3}\) features an exponent. This means we will multiply the base by itself three times.
Here's how it breaks down for \(-r = -2\), with the exponent of 3:
Here's how it breaks down for \(-r = -2\), with the exponent of 3:
- Multiply \(-2\) by itself three times, which is \((-2) \times (-2) \times (-2)\).
- The first multiplication: \((-2) \times (-2) = 4\).
- The second multiplication: \(4 \times (-2) = -8\).
- A negative number raised to an odd exponent, such as 3, remains negative.
- When you perform operations involving exponents, do so before proceeding with addition, subtraction, or multiplication outside the powers.
Order of Operations
The **order of operations** is a fundamental concept ensuring that expressions are evaluated consistently. In mathematics, the order is often summarized by the acronym BIDMAS/BODMAS. This stands for Brackets, Indices (another term for exponents), Division and Multiplication (from left to right), Addition and Subtraction (from left to right).
Let's consider our expression, \(9(-2)(-8)\):
Let's consider our expression, \(9(-2)(-8)\):
- The original expression involves multiplication and an exponent, so according to BIDMAS, we handle the exponent first.
- After evaluating the exponent step as described earlier, we address the multiplication. Simplifying from left to right, multiply the constants in sequence:
- First, \(9 \times (-2) = -18\) because multiplication of a positive and negative number results in a negative product.
- Next, multiply \(-18 \times (-8) = 144\). Multiplying two negative numbers results in a positive number.
Other exercises in this chapter
Problem 44
Use the distributive property to rewrite the expression without parentheses. $$ (2+t)(-2) $$
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Find the sum. $$-24.5+6+8$$
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Determine whether to use a positive or a negative number to represent the velocity. The velocity of a rising rocket
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Write the numbers in increasing order. \(4.6,0.7,-4,-1.8,3,-0.6\)
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