Problem 44
Question
Evaluate each expression. Do not use a calculator. $$\sqrt{2} \ln e^{\sqrt{2}}$$
Step-by-Step Solution
Verified Answer
The expression simplifies to 2.
1Step 1: Understanding the Logarithmic Identity
Remember that the natural logarithm \( \ln \) has the property \( \ln(a^b) = b \ln a \). Also note that \( \ln e = 1 \) because \( e \) is the base of the natural logarithm.
2Step 2: Applying the Logarithmic Identity
In the expression \( \ln e^{\sqrt{2}} \), apply the identity to rewrite it as \( \sqrt{2} \ln e \). Since \( \ln e = 1 \), it simplifies further to \( \sqrt{2} \cdot 1 = \sqrt{2} \).
3Step 3: Simplifying the Entire Expression
Now, substitute the result from Step 2 back into the original expression \( \sqrt{2} \ln e^{\sqrt{2}} \), which now becomes \( \sqrt{2} \cdot \sqrt{2} \).
4Step 4: Multiplying the Square Roots
When you multiply \( \sqrt{2} \times \sqrt{2} \), it simplifies to \( 2 \), because \( \sqrt{2} \times \sqrt{2} = 2 \).
Key Concepts
Natural LogarithmLogarithmic IdentitySquare Roots
Natural Logarithm
The natural logarithm, denoted as \( \ln \), is a logarithm with the base \( e \), where \( e \approx 2.71828 \). It is widely used in mathematics, especially in calculus and exponential growth models. The main characteristic of the natural logarithm is its relationship with the exponential function. The function \( \ln(e^x) = x \) is what makes it particularly useful.- **Why use natural logarithms?**
They simplify complex mathematical expressions involving exponential functions.
- **Fun fact:** The natural logarithm can be expressed as an integral: \( \ln(x) = \int_1^x \frac{1}{t} \, dt \).In solving logarithmic problems, remembering that \( \ln(e) = 1 \) is quite crucial. It simplifies expressions significantly, as seen in the problem, where \( \ln(e^{\sqrt{2}}) \) uses these properties to break down into simpler components.
They simplify complex mathematical expressions involving exponential functions.
- **Fun fact:** The natural logarithm can be expressed as an integral: \( \ln(x) = \int_1^x \frac{1}{t} \, dt \).In solving logarithmic problems, remembering that \( \ln(e) = 1 \) is quite crucial. It simplifies expressions significantly, as seen in the problem, where \( \ln(e^{\sqrt{2}}) \) uses these properties to break down into simpler components.
Logarithmic Identity
Logarithmic identities are handy shortcuts to simplify complex logarithmic expressions. These identities stem from the fundamental properties of logarithms.- The key identity in this context is: \( \ln(a^b) = b \ln a \).
This identity stems from exponent rules and allows the exponents to "come down" out of the logarithm, which is useful for simplification.- **How it works:**
In the problem, we have \( \ln(e^{\sqrt{2}}) \). Using the identity, this becomes \( \sqrt{2} \cdot \ln(e) \). Given \( \ln(e) = 1 \), it simplifies directly to \( \sqrt{2} \).Understanding and applying these identities can transform and ease the computation process, especially when evaluating expressions manually.
This identity stems from exponent rules and allows the exponents to "come down" out of the logarithm, which is useful for simplification.- **How it works:**
In the problem, we have \( \ln(e^{\sqrt{2}}) \). Using the identity, this becomes \( \sqrt{2} \cdot \ln(e) \). Given \( \ln(e) = 1 \), it simplifies directly to \( \sqrt{2} \).Understanding and applying these identities can transform and ease the computation process, especially when evaluating expressions manually.
Square Roots
Square roots are numbers that, when multiplied by themselves, give the original number. The square root of a number \( x \) is often expressed as \( \sqrt{x} \).- **Why they matter:**
In mathematics, square roots appear in many different contexts, including geometry, algebra, and calculus. They are essential when solving quadratic equations or working with areas and volumes.- **Simplifying square roots:**
When you multiply two identical square roots, the result is the original number: \( \sqrt{a} \times \sqrt{a} = a \).
This principle is seen when \( \sqrt{2} \times \sqrt{2} = 2 \) in the given problem.Square roots are straightforward yet powerful tools for simplifying expressions, especially when combined with logarithms and other mathematical operations.
In mathematics, square roots appear in many different contexts, including geometry, algebra, and calculus. They are essential when solving quadratic equations or working with areas and volumes.- **Simplifying square roots:**
When you multiply two identical square roots, the result is the original number: \( \sqrt{a} \times \sqrt{a} = a \).
This principle is seen when \( \sqrt{2} \times \sqrt{2} = 2 \) in the given problem.Square roots are straightforward yet powerful tools for simplifying expressions, especially when combined with logarithms and other mathematical operations.
Other exercises in this chapter
Problem 44
Determine whether each function is one-to-one. If so, find its inverse. $$g=\\{(5,12),(10,22),(15,32),(20,42)\\}$$
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Explain how the graph of the given function can be obtained from the graph of y=\log _{2} x, and (b) graph the function. $$y=\log _{2}(x+4)$$
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