Problem 44
Question
Electricity through the body, I. A person with a body resistance of 10 \(\mathrm{k} \Omega\) between his hands accidentally grasps the terminals of a 14 \(\mathrm{kV}\) power supply. (a) If the internal resistance of the power supply is \(2000 \Omega,\) what is the current through the person's body? (b) What is the power dissipated in his body? (c) If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in the situation just described to be 1.00 \(\mathrm{mA}\) or less?
Step-by-Step Solution
Verified Answer
(a) 1.17 A, (b) 13,641 W, (c) 13.99 MΩ or higher.
1Step 1: Understand the Circuit
The person is in contact with a power supply of voltage 14 kV and has a body resistance of 10 kΩ. Additionally, the power supply has an internal resistance of 2000 Ω. This creates a series circuit where the total resistance is the sum of the internal resistance of the power supply and the body resistance. Calculate the total resistance: \[ R_{\text{total}} = 10\, \text{k}\Omega + 2000\, \Omega = 12\, \text{k}\Omega \]
2Step 2: Calculate the Current through the Body
Using Ohm's Law, the current through the series circuit with total resistance is given by: \[ I = \frac{V}{R_{\text{total}}} = \frac{14\, \text{kV}}{12\, \text{k}\Omega} \] Convert the voltage to volts before calculating: \[ I = \frac{14,000\, \text{V}}{12,000\, \Omega} = 1.167\, \text{A} \] Therefore, the current through the body is approximately 1.17 A.
3Step 3: Calculate the Power Dissipated in the Body
The power dissipated in the body can be calculated using the formula: \[ P = I^2 \cdot R_{\text{body}} \] Substitute the known values:\[ P = (1.167\, \text{A})^2 \times 10\, \text{k}\Omega = 13,640.89\, \text{W} \] Therefore, the power dissipated in the body is approximately 13,641 W.
4Step 4: Determine Required Resistance for Safety
To find the internal resistance that makes the circuit safe, limit the current to a maximum of 1 mA or less. Using 1 mA, rewrite Ohm's Law: \[ 0.001\, \text{A} = \frac{14,000\, \text{V}}{R_{\text{body}} + R_{\text{internal}}} \] Rearrange to solve for \( R_{\text{internal}} \):\[ R_{\text{internal}} = \frac{14,000\, \text{V}}{0.001\, \text{A}} - 10,000\, \Omega \]\[ R_{\text{internal}} = 14,000,000\, \Omega - 10,000\, \Omega = 13,990,000\, \Omega \]Therefore, the internal resistance should be 13.99 MΩ or higher.
Key Concepts
Ohm's LawBody resistancePower dissipationCircuit safety
Ohm's Law
Ohm's Law is a fundamental principle in the study of electricity. It states that the current flowing through a conductor between two points is directly proportional to the voltage across the two points and inversely proportional to the resistance between them. The mathematical expression for Ohm's Law is \[ I = \frac{V}{R} \]where:
- \( I \) is the current in amperes (A).
- \( V \) is the voltage in volts (V).
- \( R \) is the resistance in ohms (Ω).
Body resistance
The resistance of the human body plays a critical role in determining how much current flows through it in case of accidental contact with electrical sources. Body resistance can vary widely, depending on factors like moisture, skin condition, and the area of contact. For the illustrated example, a body resistance of 10 kΩ was assumed. This resistance can combine with other circuit components, influencing the total impedance and subsequently the current.
The overall concept here is that our bodies are not perfect insulators, and electricity can pass through us, potentially causing serious harm. Safety standards set limits on exposure, considering the body's resistance. The combination with external resistances—like that of the power supply in our scenario—can help mitigate the risk by reducing the current reaching lethal levels.
The overall concept here is that our bodies are not perfect insulators, and electricity can pass through us, potentially causing serious harm. Safety standards set limits on exposure, considering the body's resistance. The combination with external resistances—like that of the power supply in our scenario—can help mitigate the risk by reducing the current reaching lethal levels.
Power dissipation
Power dissipation in electrical circuits is the process of converting electrical energy into other forms, such as heat. In human and machine terms, power dissipation occurs when electric current flows through a resistance, creating a voltage drop and releasing energy.
This can be explained with the formula:\[ P = I^2 \cdot R \]where:
This can be explained with the formula:\[ P = I^2 \cdot R \]where:
- \( P \) is the power in watts (W).
- \( I \) is the current in amperes (A).
- \( R \) is the resistance in ohms (Ω).
Circuit safety
Circuit safety is vital when designing systems that humans will interact with. Ensuring that electrical equipment is safe involves controlling the amount of current that can flow through a circuit, particularly in situations where human contact is possible.
In the exercise, increasing the power supply's internal resistance is a method to make the system safer. By increasing this resistance, the total resistance of the circuit goes up, which reduces current according to Ohm's Law. To calculate a safer setup, we determined the necessary internal resistance to keep the body current below 1 mA, which is considered a safer threshold for humans.
In the exercise, increasing the power supply's internal resistance is a method to make the system safer. By increasing this resistance, the total resistance of the circuit goes up, which reduces current according to Ohm's Law. To calculate a safer setup, we determined the necessary internal resistance to keep the body current below 1 mA, which is considered a safer threshold for humans.
- Measures such as circuit breakers, fuses, and insulation are also commonly employed to protect people from electrical hazards.
- Understanding and implementing adequate resistance levels can prevent dangers like fires, electrical shocks, or even electrocution.
Other exercises in this chapter
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