Problem 44
Question
Determine whether each situation involves a permutation or a combination. Then find the number of possibilities. How many ways can 4 different gifts be placed into 4 different gift bags if each bag gets exactly 1 gift?
Step-by-Step Solution
Verified Answer
The situation involves a permutation, with 24 possible ways to place the gifts into the bags.
1Step 1: Identify the Type of Problem
In this scenario, we need to determine if the problem is a permutation or a combination. When dealing with arrangements where the order of items matters (like placing gifts into specific bags), it involves permutations. Since each gift is distinct and each bag is distinct, and each specific arrangement counts as different, it's a permutation problem.
2Step 2: Understand Permutation Formula
To solve a permutation problem, use the formula for permutations of n items in n positions, which is given by: \[ P(n, n) = n! \] Here, \( n! \) (read as 'n factorial') represents the product of all positive integers up to n.
3Step 3: Calculate Permutation
For this problem, there are 4 different gifts and 4 different bags, so we need to calculate \( 4! \): \[ 4! = 4 \times 3 \times 2 \times 1 = 24 \] Thus, there are 24 ways to arrange 4 different gifts into 4 different bags.
Key Concepts
Factorial CalculationArrangementsOrder Importance
Factorial Calculation
The concept of factorial calculation is a fundamental element in mathematics, especially when dealing with permutations. The factorial of a non-negative integer, represented as \( n! \), is the product of all positive integers less than or equal to \( n \). This operation is crucial in calculating the number of ways to arrange a set number of items.
For instance, in the problem above, to place 4 different gifts into 4 different bags, you calculate \( 4! \). The process involves multiplying all whole numbers from 4 down to 1, like this: \( 4 \times 3 \times 2 \times 1 = 24 \). Each time you see a factorial in permutation problems, you should think about multiplying a cascade of decreasing whole numbers until you reach one.
Here are a few key points about factorials:
For instance, in the problem above, to place 4 different gifts into 4 different bags, you calculate \( 4! \). The process involves multiplying all whole numbers from 4 down to 1, like this: \( 4 \times 3 \times 2 \times 1 = 24 \). Each time you see a factorial in permutation problems, you should think about multiplying a cascade of decreasing whole numbers until you reach one.
Here are a few key points about factorials:
- Factorials grow very fast as numbers increase. For example, \( 5! = 120 \), \( 6! = 720 \).
- The value of \( 0! \) is defined to be 1. This might seem counterintuitive, but it helps many formulas in mathematics work smoothly.
Arrangements
Arrangements refer to the different ways of organizing or ordering items. In permutations, where order matters, each unique ordering is considered a different arrangement. For example, when placing gifts into bags, we are concerned with which gift goes into which bag. This concern makes it an arrangement problem, requiring a permutation.
In mathematical terms, an arrangement's complexity goes up with the number of distinct items involved, because each item adds multiple possibilities to the ordering outcomes. Consider having the gifts labeled A, B, C, and D. Each possible permutation, such as ABCD, BACD, or DABC, represents a different arrangement.
This is a distinguishing factor between permutations and combinations. Permutations count different orders as separate arrangements, while combinations focus only on the group itself, not the order.
Key tips to remember about arrangements:
In mathematical terms, an arrangement's complexity goes up with the number of distinct items involved, because each item adds multiple possibilities to the ordering outcomes. Consider having the gifts labeled A, B, C, and D. Each possible permutation, such as ABCD, BACD, or DABC, represents a different arrangement.
This is a distinguishing factor between permutations and combinations. Permutations count different orders as separate arrangements, while combinations focus only on the group itself, not the order.
Key tips to remember about arrangements:
- Order matters: Different sequences count as different arrangements.
- Each permutation is unique, so increasing items or positions increases possibilities significantly.
Order Importance
The importance of order is what distinguishes permutations from combinations. In a permutation, not only the items matter, but also the sequence in which they are arranged. This is pivotal in many real-life scenarios, such as assigning awards, distributing tasks, or, as in the exercise, placing gifts into bags.
In the exercise scenario, changing the order of gifts in bags results in a different permutation. For example, if gift 1 goes in bag A and gift 2 in bag B, swapping their positions entirely changes the arrangement. This is why there are 24 different ways (or permutations) to arrange 4 gifts in 4 bags.
Order of items can influence outcomes in profound ways:
In the exercise scenario, changing the order of gifts in bags results in a different permutation. For example, if gift 1 goes in bag A and gift 2 in bag B, swapping their positions entirely changes the arrangement. This is why there are 24 different ways (or permutations) to arrange 4 gifts in 4 bags.
Order of items can influence outcomes in profound ways:
- Every shuffle or switch creates a new arrangement.
- Order sensitivity is critically important in competitive settings, like sports or rankings, where position is everything.
Other exercises in this chapter
Problem 44
CHALLENGE A textbook gives the following probability equation for events \(A\) and \(B\) that are mutually exclusive or inclusive. \(P(A \text { and } B)=P(A)+P
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Find each probability if 13 cards are drawn from a standard deck of cards and no replacement occurs. \(P(\text { all one suit })\)
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Darius can do his homework in pencil or pen, using lined or unlined paper, and on one or both sides of each page. How many ways can he do his homework?
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Evaluate each expression. \(\frac{7 !}{3 !}\)
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