Problem 44
Question
Convert the equation to polar form. $$ y=5 $$
Step-by-Step Solution
Verified Answer
The polar form of \( y = 5 \) is \( r \sin \theta = 5 \).
1Step 1: Understand the given equation
The given equation is in Cartesian coordinates and is a horizontal line: \( y=5 \). This line is parallel to the x-axis.
2Step 2: Recall the conversion formulas
In polar coordinates, any point is represented by \((r, \theta)\), where \(r\) is the distance from the origin, and \(\theta\) is the angle from the positive x-axis. The conversion formulas are: \( x = r \cos \theta \) and \( y = r \sin \theta \).
3Step 3: Substitute and simplify the equation
Substitute \( y = r \sin \theta \) in the equation \( y = 5 \), resulting in \( r \sin \theta = 5 \).
4Step 4: Express the equation in polar form
The equation \( r \sin \theta = 5 \) is the polar form of \( y = 5 \). This represents all points where their projection on the y-axis equals 5, in terms of polar coordinates.
Key Concepts
Conversion from Cartesian to PolarPolar EquationsTrigonometric Functions
Conversion from Cartesian to Polar
When working with coordinates, it is important to understand the difference between Cartesian and polar systems. Cartesian coordinates use horizontal and vertical axes to describe a point's location with
Polar coordinates, by contrast, specify a point with:
- **x-coordinate** indicates horizontal position, and
- **y-coordinate** indicates vertical position.
Polar coordinates, by contrast, specify a point with:
- **r**, the distance from the origin, and
- **\(\theta\)**, the angle from the positive x-axis.
- \(x = r \cos \theta\)
- \(y = r \sin \theta\)
Polar Equations
Understanding polar equations is crucial when dealing with curves and lines in polar coordinates. In the polar form of an equation, such as \(r \sin \theta = 5\), each point \((r, \theta)\) satisfies the relationship between the two elements: radius and angle.
This specific equation represents all points where the component along the y-axis, known as the projection, equals 5. It’s a direct translation of the Cartesian equation \(y = 5\) into the polar system.
With polar equations, visualization can be different but keeps the relationships consistent:
This specific equation represents all points where the component along the y-axis, known as the projection, equals 5. It’s a direct translation of the Cartesian equation \(y = 5\) into the polar system.
With polar equations, visualization can be different but keeps the relationships consistent:
- Any \(r\) satisfying \(r \sin \theta = 5\) will be on the same y-level.
- In contrast to straight horizontal lines in Cartesian coordinates, in polar, it involves circular paths centered around the origin.
Trigonometric Functions
Trigonometric functions like sine and cosine play a crucial role in easing the transition between coordinate systems. They relate angles and lengths, forming the backbone of the conversion formulas used between Cartesian and polar.
For instance, knowing that \(\sin \theta = \frac{y}{r}\) helps explain how \(r \sin \theta\) equals a consistent value such as 5. This showcases the constant nature of y-level lines in polar context.
Getting comfortable with trigonometric functions allows smoother calculations and a deeper appreciation of how angles affect distances in polar coordinates.
- **Sine** is utilized to calculate the y-component in polar coordinates: \(y = r \sin \theta\), explaining its use in our equation \(r \sin \theta = 5\).
- **Cosine** relates to the x-component since \(x = r \cos \theta\).
For instance, knowing that \(\sin \theta = \frac{y}{r}\) helps explain how \(r \sin \theta\) equals a consistent value such as 5. This showcases the constant nature of y-level lines in polar context.
Getting comfortable with trigonometric functions allows smoother calculations and a deeper appreciation of how angles affect distances in polar coordinates.
Other exercises in this chapter
Problem 44
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