Problem 44
Question
Calculate the rms speed for CO molecules at \(25^{\circ} \mathrm{C} .\) What is the ratio of this speed to that of \(\mathrm{Ar}\) atoms at the same temperature?
Step-by-Step Solution
Verified Answer
The ratio of rms speeds of CO to Ar at 25°C is \(\sqrt{28.01/39.95}\).
1Step 1: Convert Temperature to Kelvin
To calculate the root mean square (rms) speed, we need the temperature in Kelvin. The temperature in Celsius is given as 25°C. Convert this to Kelvin by adding 273.15: \[T = 25 + 273.15 = 298.15 \text{ K}\]
2Step 2: Use the RMS Speed Formula
The formula for the root mean square speed is given by \[v_{rms} = \sqrt{\frac{3kT}{m}}\]where:- \(k\) is the Boltzmann constant \((1.38 \times 10^{-23} \text{ J/K})\)- \(T\) is the temperature in Kelvin- \(m\) is the mass of a single molecule in kilograms. For CO, the molar mass is 28.01 g/mol, so the mass of one molecule is 28.01 g/mol divided by Avogadro's number \((6.022 \times 10^{23} \text{ mol}^{-1})\) converted to kg.\[m_{CO} = \frac{28.01 \times 10^{-3}}{6.022 \times 10^{23}} \text{ kg}\]
3Step 3: Calculate RMS Speed for CO
Substitute the values into the RMS speed formula:\[v_{rms, CO} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 298.15}{\frac{28.01 \times 10^{-3}}{6.022 \times 10^{23}}}}\]Calculate \(v_{rms, CO}\).
4Step 4: Calculate RMS Speed for Ar
Repeating the same process for Argon (Ar), which has a molar mass of 39.95 g/mol:\[m_{Ar} = \frac{39.95 \times 10^{-3}}{6.022 \times 10^{23}} \text{ kg}\]Use the RMS speed formula:\[v_{rms, Ar} = \sqrt{\frac{3 \times 1.38 \times 10^{-23} \times 298.15}{\frac{39.95 \times 10^{-3}}{6.022 \times 10^{23}}}}\]
5Step 5: Calculate the Ratio of RMS Speeds
Finally, calculate the ratio of the rms speeds of CO to Ar:\[\text{Ratio} = \frac{v_{rms, CO}}{v_{rms, Ar}}\]Substitute values from the previous calculations to find the ratio.
Key Concepts
Kinetic Molecular TheoryMolecular MassBoltzmann Constant
Kinetic Molecular Theory
The Kinetic Molecular Theory is a fundamental concept in physics and chemistry that explains the behavior of gases. It provides a detailed insight into how gas molecules move and interact. The theory suggests that gases are made up of a huge number of tiny particles, which are in constant, random motion. This motion is responsible for the pressure exerted by gases in a container.
- Molecules move in straight lines until they collide with each other or the walls of a container.
- Collisions are elastic, which means that the total kinetic energy is conserved.
- The average kinetic energy of gas molecules is proportional to the temperature in Kelvins.
Molecular Mass
Molecular mass, often referred to as molar mass, is the mass of a given molecule. It is calculated as the sum of the atomic masses of its constituent atoms. Molecular mass is crucial when determining the rms speed, as it affects how fast or slow a molecule can go.
- It is usually expressed in grams per mole (g/mol).
- To find the mass of a single molecule, the molecular mass is divided by Avogadro's number (approximately \(6.022 \times 10^{23}\) molecules per mole).
Boltzmann Constant
The Boltzmann constant (\(k\)) is a key player in physical chemistry and thermodynamics, especially within the realm of gases. It relates the average kinetic energy of particles in a gas with the temperature of the gas.
- Its value is approximately \(1.38 \times 10^{-23} \text{ J/K}\).
- It acts as a bridge, connecting the microscopic world, like atoms and molecules, with macroscopic properties such as temperature.
Other exercises in this chapter
Problem 41
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