Problem 44
Question
A set of data items is normally distributed with a mean of 60 and a standard deviation of 8 . In Exercises 33-48, convert each data item to a z-score. 44
Step-by-Step Solution
Verified Answer
The z-score for the data item 44 is -2.
1Step 1: Identify the values
From the problem statement, it is known that the mean (also symbolised by \(\mu\)) is 60, standard deviation (also symbolised by \(\sigma\)) is 8 and the individual item's value is 44.
2Step 2: Apply the z-score formula
The z-score is computed using the formula \(z= \frac{X - \mu}{\sigma}\), where \(X\) is the individual item's value. Substituting the provided values into the formula, it becomes \(z= \frac{44 - 60}{8}\).
3Step 3: Solve the equation
By carrying out the operation, the z-score becomes \(z = \frac{-16}{8} = -2\)
Key Concepts
Normal DistributionMeanStandard DeviationZ-Score
Normal Distribution
The normal distribution is a fundamental concept in statistics that describes how a set of data points is expected to be distributed across various values. It is often depicted as a bell-shaped curve, which is symmetric about the mean. The majority of the data points fall close to the mean, with fewer and fewer appearing as you move further away. This type of distribution is important because many natural phenomena follow it, making it a key tool in statistical analysis.
Normal distributions are characterized by two parameters:
Normal distributions are characterized by two parameters:
- The mean ( mu d) which determines the location of the center of the graph.
- The standard deviation ( sigma d) which defines the width of the curve.
Mean
The mean is the average value of a set of numbers, providing a central point around which the data is distributed. It is found by summing all the individual data points and dividing by the total number of points. This value helps describe the typical value you might expect in a data set.
In the context of a normal distribution, the mean ( mu d) is that point of highest frequency, or the peak, representing where most of the data points congregate. In the given example, the mean of 60 signifies that 60 is the most common value around which other data points scatter. Having a good understanding of the mean is crucial, especially when interpreting data because it is foundational to calculating other statistical measures like variance and standard deviation.
In the context of a normal distribution, the mean ( mu d) is that point of highest frequency, or the peak, representing where most of the data points congregate. In the given example, the mean of 60 signifies that 60 is the most common value around which other data points scatter. Having a good understanding of the mean is crucial, especially when interpreting data because it is foundational to calculating other statistical measures like variance and standard deviation.
Standard Deviation
Standard deviation is a statistic that measures the amount of variability or spread in a set of data. A small standard deviation means that the data points tend to be close to the mean, while a large standard deviation indicates that data points are spread out over a larger range.
- Standard deviation is symbolized by sigma d and calculated as the square root of the variance.
- It provides insight into the consistency and reliability of the mean as a representative of the data set.
Z-Score
A z-score is a statistical measure that describes a data point's relation to the mean of a group of points. It is expressed as the number of standard deviations away from the mean.
The formula for calculating a z-score is:
\[ z = \frac{X - \mu}{\sigma} \]
Where:
The formula for calculating a z-score is:
\[ z = \frac{X - \mu}{\sigma} \]
Where:
- \(X\): The value of the data point.
- \(\mu\): The mean.
- \(\sigma\): The standard deviation.
Other exercises in this chapter
Problem 43
What is a histogram?
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A woman insists that she will never marry a man as short or shorter than she, knowing that only one man in 400 falls into this category. Assuming a mean height
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Two classes took a statistics test. Both classes had a mean score of 73 . The scores of class \(A\) had a standard deviation of 5 and those of class B had a sta
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Find the mode for the data items in the frequency distribution in \(1.4,2.1,1.6,3.0,1.4,2.2,1.4,9.0,9.0,1.8\)
View solution