Problem 44
Question
A. Rewrite the division as multiplication involving a multiplicative inverse. B. Use the multiplication from part (a) to find the given quotient. $$-18 \div 6$$
Step-by-Step Solution
Verified Answer
-3
1Step 1: Rewrite Division as Multiplication With Inverse
To rewrite \( -18 \div 6 \) as a multiplication with inverse, we simply flip the divisor (6) to get its inverse and change the operation from division to multiplication. So we get \( -18 \times \frac{1}{6} \). We can keep the negative sign with the 18 as it is.
2Step 2: Perform Multiplication
Now we perform the multiplication operation with \( -18 \) and \( \frac{1}{6} \). For this operation, we simply multiply the numerator -18 with the numerator 1 and the denominator 1 with the denominator 6. This results in \( \frac{-18}{6} \).
3Step 3: Simplify Fraction
The result \(\frac{-18}{6}\) needs to be simplified. By dividing the numerator and the denominator by the common factor, which is 6, we get \(-3\) as the final answer.
Key Concepts
Multiplicative InverseMultiplicationSimplifying Fractions
Multiplicative Inverse
A multiplicative inverse (also called a reciprocal) is a number that, when multiplied by a given number, results in the identity, which is 1. In simpler terms, if you have a number like 6, its multiplicative inverse would be \( \frac{1}{6} \). When you multiply these two numbers together, \( 6 \times \frac{1}{6} = 1 \). This concept comes in very handy in division problems because division can be transformed into multiplication by using the multiplicative inverse.
For example, in the expression \( -18 \div 6 \), you can replace the division sign by multiplying by the inverse of 6, which is \( \frac{1}{6} \). The equation then becomes: \( -18 \times \frac{1}{6} \). Remember, for any non-zero number 'a', the multiplicative inverse is \( \frac{1}{a} \).
This approach simplifies calculations and is often used to solve problems more easily in algebra and arithmetic. Being comfortable with finding and using multiplicative inverses is key for tackling complex mathematical problems.
For example, in the expression \( -18 \div 6 \), you can replace the division sign by multiplying by the inverse of 6, which is \( \frac{1}{6} \). The equation then becomes: \( -18 \times \frac{1}{6} \). Remember, for any non-zero number 'a', the multiplicative inverse is \( \frac{1}{a} \).
This approach simplifies calculations and is often used to solve problems more easily in algebra and arithmetic. Being comfortable with finding and using multiplicative inverses is key for tackling complex mathematical problems.
Multiplication
Multiplication of fractions involves multiplying the numerators together and the denominators together. When you have an expression like \( -18 \times \frac{1}{6} \), you can think of -18 as \( \frac{-18}{1} \), making the multiplication straightforward.
Here's the step-by-step breakdown:
Here's the step-by-step breakdown:
- Multiply the numerators: \(-18 \times 1 = -18\).
- Multiply the denominators: \(1 \times 6 = 6\).
- Combine: You get the result \( \frac{-18}{6} \).
Simplifying Fractions
Simplifying fractions involves reducing the fraction to its smallest possible form. You achieve that by finding the greatest common factor (GCF) for both the numerator and the denominator and dividing them by this factor.
In the example of \( \frac{-18}{6} \), the GCF of 18 and 6 is 6. By dividing both the numerator and the denominator by their GCF, the fraction simplifies:
In the example of \( \frac{-18}{6} \), the GCF of 18 and 6 is 6. By dividing both the numerator and the denominator by their GCF, the fraction simplifies:
- \(-18 \div 6 = -3\) for the numerator.
- \(6 \div 6 = 1\) for the denominator.
- This gives \( \frac{-3}{1} \), which simplifies further to just \(-3\).
Other exercises in this chapter
Problem 43
Perform the indicated operation. Where possible, reduce the answer to its lowest terms. $$\frac{3}{8} \cdot \frac{7}{11}$$
View solution Problem 44
Perform the indicated subtraction. $$1.4-(-1.4)$$
View solution Problem 44
In Exercises \(29-72,\) use the order of operations to simplify each expression. $$(4-6)^{2}-(5-9)^{2}$$
View solution Problem 44
Use a form of the distributive property to rewrite each algebraic expression without parentheses. $$7(2 x+4+y)$$
View solution