Problem 44
Question
\(43-44\) Simplify using the Binomial Theorem. $$ \frac{(x+h)^{4}-x^{4}}{h} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(4x^3 + 6x^2h + 4xh^2 + h^3\).
1Step 1: Understand the Expression
The given expression is \( \frac{(x+h)^{4}-x^{4}}{h} \). It involves simplifying a difference quotient using the Binomial Theorem.
2Step 2: Apply the Binomial Theorem
The Binomial Theorem states that \((x + h)^4 = x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4\). Substitute this expansion into the expression.
3Step 3: Substitute the Expansion
Replace \((x+h)^4\) in the original expression: \( \frac{x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 - x^4}{h} \).
4Step 4: Simplify the Numerator
Cancel like terms in the numerator: \(x^4 - x^4\) cancels to zero, leaving \(4x^3h + 6x^2h^2 + 4xh^3 + h^4\).
5Step 5: Factor the Remaining Terms
Factor out \(h\) from the remaining terms: \(h(4x^3 + 6x^2h + 4xh^2 + h^3)\).
6Step 6: Simplify the Expression
Cancel \(h\) in the numerator and denominator: \(4x^3 + 6x^2h + 4xh^2 + h^3\).
7Step 7: Final Expression
The simplified form of the expression is \(4x^3 + 6x^2h + 4xh^2 + h^3\).
Key Concepts
Difference QuotientAlgebraic SimplificationPolynomial Expansion
Difference Quotient
The difference quotient is a fundamental concept in calculus. It is essential for understanding how functions change, serving as the foundation for derivatives. In the expression given, the difference quotient is represented as \( \frac{(x+h)^{4}-x^{4}}{h} \).
This setup reflects the change in a function's values over a small interval \( h \).
When functions involve higher powers, like \( (x+h)^4 \), methods like the Binomial Theorem help in expanding and simplifying the expression.
This setup reflects the change in a function's values over a small interval \( h \).
- The numerator \((x+h)^4 - x^4\) shows the difference in the function value due to a small change \( h \).
- The denominator \( h \) represents the size of that change.
When functions involve higher powers, like \( (x+h)^4 \), methods like the Binomial Theorem help in expanding and simplifying the expression.
Algebraic Simplification
Algebraic simplification in expressions is key to making complex problems easier to handle. Once \( (x+h)^4 \) is expanded using the Binomial Theorem, the next step is to simplify the resulting expression. This involves canceling terms and reducing complicated parts into simpler forms.
For the expression \( \frac{x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 - x^4}{h} \), note the following:
For the expression \( \frac{x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 - x^4}{h} \), note the following:
- The \( x^4 \) term in the expansion cancels with \( -x^4 \), removing them from the equation.
- What remains is \( 4x^3h + 6x^2h^2 + 4xh^3 + h^4 \), all terms now involving \( h \).
Polynomial Expansion
Polynomial expansion is a powerful technique for dealing with expressions like \( (x+h)^4 \). The Binomial Theorem allows us to break down such expressions into a series of terms that are more manageable. The theorem states that any binomial \((a + b)^n\) can be expanded using the formula:
\[\sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\]
In our case:
\[\sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\]
In our case:
- \((x + h)^4\) becomes \(x^4 + 4x^3h + 6x^2h^2 + 4xh^3 + h^4 \).
Other exercises in this chapter
Problem 43
39-44 Find the partial sum \(S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$a_{1}=55, d=12, n=10$$
View solution Problem 43
Find the sum. $$\sum_{i=1}^{8}\left[1+(-1)^{i}\right]$$
View solution Problem 44
Find the sum. $$ 1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\cdots-\frac{1}{512} $$
View solution Problem 44
39-44 Find the partial sum \(S_{n}\) of the arithmetic sequence that satisfies the given conditions. $$a_{2}=8, a_{5}=9.5, n=15$$
View solution