Problem 44
Question
\(29-46\) Simplify each expression. $$ \left(2 z^{2}\right)^{-5} z^{10} $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(\frac{1}{32}\).
1Step 1: Understand Negative Exponents
The expression \((2z^2)^{-5}\) has a negative exponent, which means we take the reciprocal of the base. So, \((2z^2)^{-5}\) is equal to \(\frac{1}{(2z^2)^5}\).
2Step 2: Simplify the Power of a Product
Expand the power for the term \((2z^2)^5\). This means we raise both 2 and \(z^2\) to the 5th power: \(2^5(z^2)^5 = 32z^{10}\).
3Step 3: Substitute Back into the Expression
Now substitute the simplified form back into the expression: \(\frac{1}{32z^{10}} \cdot z^{10}\).
4Step 4: Simplify the Multiplication
Multiply \(\frac{1}{32z^{10}}\) by \(z^{10}\). This effectively cancels out \(z^{10}\) in the numerator and denominator, resulting in \(\frac{1}{32}\).
5Step 5: Final Simplification
This leaves us with the simplified expression, \(\frac{1}{32}\), as there are no other terms to combine or simplify.
Key Concepts
Negative ExponentsSimplificationPower of a Product
Negative Exponents
Negative exponents might seem confusing at first, but they follow a simple rule. They tell us to take the reciprocal of the base while converting the exponent to positive. In other words, when you see a negative exponent, think about flipping the base. For instance, if you have a term like
- \(a^{-n}\), this is equivalent to \(\frac{1}{a^n}\).
Simplification
Simplification in algebra involves reducing expressions to their simplest form so they can be more easily understood or worked with. This includes combining like terms, simplifying fractions, and reducing expressions as much as possible.
In the original problem, the simplification started by understanding and applying the properties of exponents. Once revised, allow for more straightforward operations:
In the original problem, the simplification started by understanding and applying the properties of exponents. Once revised, allow for more straightforward operations:
- After applying the concept of negative exponents, we took the next steps to resolve the terms: changing \( (2z^2)^{-5} \) into \( \frac{1}{(2z^2)^5} \).
- Next, we combined terms, \( \frac{1}{(2z^2)^5} \times z^{10} \), focusing on canceling or reducing similar items in the numerator and denominator, especially common terms such as \( z^{10} \).
Power of a Product
When you raise a product to a power, each factor inside the parentheses must take on the exponentiation process. This is known as the power of a product rule. It tells us that:
- \((ab)^n = a^n \cdot b^n\)
- The factor 2 raised to the fifth power gives us \( 2^5 = 32 \).
- The factor \( z^2 \) raised to the fifth power follows the rule of multiplying exponents, resulting in \( (z^2)^5 = z^{10} \).
Other exercises in this chapter
Problem 43
Mary’s backyard vegetable garden measures 20 \(\mathrm{ft}\) by 30 \(\mathrm{ft}\) , so its area is \(20 \times 30=600 \mathrm{ft}^{2}\). She decides to make it
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Perform the multiplication or division and simplify. \(\frac{x}{y / z}\)
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Factor the expression completely. $$ 2 x^{2}+7 x-4 $$
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Express the inequality in interval notation, and then graph the corresponding interval. $$ -5
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