Problem 432
Question
For the following exercises, solve each problem. Prove that \((\cosh (x)+\sinh (x))^{n}=\cosh (n x)+\sinh (n x)\).
Step-by-Step Solution
Verified Answer
\((\cosh(x)+\sinh(x))^n = \cosh(nx)+\sinh(nx)\) is proven using exponential identities.
1Step 1: Understand Hyperbolic Functions
The hyperbolic functions are defined as: \(\cosh(x) = \frac{e^x + e^{-x}}{2}\)and\(\sinh(x) = \frac{e^x - e^{-x}}{2}\). These functions share some properties with trigonometric functions, such as addition formulas.
2Step 2: Express in Terms of Exponential Functions
Using the definitions: - \(\cosh(x) + \sinh(x) = \frac{e^x + e^{-x}}{2} + \frac{e^x - e^{-x}}{2} = e^x\). Therefore, \((\cosh(x) + \sinh(x))^n = (e^x)^n = e^{nx}\).
3Step 3: Use the Exponential Identities for Hyperbolic Functions
Find \(\cosh(nx)\) and \(\sinh(nx)\) using the definitions of hyperbolic functions:- \(\cosh(nx) = \frac{e^{nx} + e^{-nx}}{2}\)- \(\sinh(nx) = \frac{e^{nx} - e^{-nx}}{2}\).Thus, \(\cosh(nx) + \sinh(nx) = \frac{e^{nx} + e^{-nx}}{2} + \frac{e^{nx} - e^{-nx}}{2} = e^{nx}\).
4Step 4: Equate the Expressions
Since both the expanded expression \((\cosh(x) + \sinh(x))^n = e^{nx}\) and the hyperbolic function identity \(\cosh(nx) + \sinh(nx) = e^{nx}\) are equivalent, the problem is proven true by matching the expressions: \((\cosh(x) + \sinh(x))^n = \cosh(nx) + \sinh(nx)\).
Key Concepts
cosh(x) definitionsinh(x) definitionhyperbolic identitiesexponential functions in hyperbolic context
cosh(x) definition
The hyperbolic cosine function, written as \(\cosh(x)\), is a mathematical function that comes into play in many calculus and algebra problems. It is defined using exponential functions as: \(\cosh(x) = \frac{e^x + e^{-x}}{2}\).
The \(\cosh(x)\) function is similar in spirit to the cosine function in trigonometry. However, instead of involving circular relationships, \(\cosh(x)\) relates to hyperbolas.
The \(\cosh(x)\) function is similar in spirit to the cosine function in trigonometry. However, instead of involving circular relationships, \(\cosh(x)\) relates to hyperbolas.
- The \(e^x\) term that forms part of its definition illustrates its growth.
- It is an even function, meaning \(\cosh(-x) = \cosh(x)\).
- It primarily deals with real numbers, providing positive outputs.
sinh(x) definition
The hyperbolic sine function, noted as \(\sinh(x)\), operates alongside \(\cosh(x)\) and follows a similar exponential pattern. Its definition is given by \(\sinh(x) = \frac{e^x - e^{-x}}{2}\).
Unlike \(\cosh(x)\), \(\sinh(x)\) is analogous to the sine function but pertains to hyperbolic function systems.
Unlike \(\cosh(x)\), \(\sinh(x)\) is analogous to the sine function but pertains to hyperbolic function systems.
- The subtraction (\(-\)) in its formula causes its values to be zero-symmetric about the origin.
- \(\sinh(x)\) is an odd function, where \(\sinh(-x) = -\sinh(x)\).
- It represents the shape of a hyperbola, contrary to the circle-shaped relation in regular trigonometry.
hyperbolic identities
Hyperbolic identities are a set of math expressions involving hyperbolic functions like \(\sinh(x)\) and \(\cosh(x)\). These identities showcase relationships similar to trigonometric identities and are useful in various computations.
Some core hyperbolic identities include:
Mastering these formulas is paramount for resolving complex problems involving hyperbolic functions.
Some core hyperbolic identities include:
- Addition formula: \(\cosh(x+y) = \cosh(x)\cosh(y) + \sinh(x)\sinh(y)\)
- Subtraction formula: \(\cosh(x-y) = \cosh(x)\cosh(y) - \sinh(x)\sinh(y)\)
- Pythagorean identity: \(\cosh^2(x) - \sinh^2(x) = 1\)
Mastering these formulas is paramount for resolving complex problems involving hyperbolic functions.
exponential functions in hyperbolic context
In the domain of hyperbolic functions, exponential functions are central components. Hyperbolic functions \(\cosh(x)\) and \(\sinh(x)\) are fundamentally based on exponential functions \(e^x\) and \(e^{-x}\).
- The addition and subtraction in \(\cosh(x)\) and \(\sinh(x)\) illustrate how exponential properties unfold.
- Exponential growth in these functions is often linear in appearance due to their mathematical formations.
- The expression and manipulation of these hyperbolic functions in exponential format offer substantial ease in calculus solving.
Other exercises in this chapter
Problem 431
For the following exercises, solve each problem. Prove the formula for the derivative of \(y=\operatorname{sech}^{-1}(x)\) by differentiating \(x=\operatorname{
View solution Problem 432
For the following exercises, solve each problem. Prove that \((\cosh (x)+\sinh (x))^{n}=\cosh (n x)+\sinh (n x)\)
View solution Problem 433
For the following exercises, solve each problem. Prove the expression for \(\sinh ^{-1}(x)\) . Multiply \(x=\sinh (y)=(1 / 2)\left(e^{y}-e^{-y}\right)\) by 2\(e
View solution Problem 433
For the following exercises, solve each problem. Prove the expression for \(\sinh ^{-1}(x)\). Multiply \(x=\sinh (y)=(1 / 2)\left(e^{y}-e^{-y}\right)\) by \(2 e
View solution