Problem 43
Question
Which of the sequences \(\left\\{a_{n}\right\\}\) converge, and which diverge? Find the limit of each convergent sequence. $$ a_{n}=\frac{(-1)^{n+1}}{2 n-1} $$
Step-by-Step Solution
Verified Answer
The sequence converges to 0.
1Step 1: Clarify Sequence Behavior
The given sequence is \( a_n = \frac{(-1)^{n+1}}{2n - 1}\). We see that \((-1)^{n+1}\) alternates in sign depending on whether \(n\) is even or odd, meaning the sequence is alternating.
2Step 2: Analyze Denominator Growth
As \(n\) increases, the denominator \(2n - 1\) increases linearly. This suggests that as \(n \rightarrow \infty\), the terms of the sequence get smaller, because the denominator grows without bound and influences the magnitude of the fraction.
3Step 3: Consider the Alternating Nature
The numerator \((-1)^{n+1}\) causes the sequence to alternate. For even \(n\), \(a_n = \frac{1}{2n-1}\), and for odd \(n\), \(a_n = \frac{-1}{2n-1}\). Both of these approaches zero as \(n\) becomes very large.
4Step 4: Establish Convergence
Even with the alternating sign, the sequence approaches 0 as the magnitude of each term decreases. Hence, for both even and odd instances, the terms approach 0 sufficiently fast, implying convergence.
5Step 5: Conclusion on Limit
Since both positive and negative terms converge to 0, and given that the terms themselves oscillate in sign, the sequence actually converges to \(0\).
Key Concepts
Alternating SequencesLimit of a SequenceSequence ConvergenceBehavior of Sequences
Alternating Sequences
An alternating sequence is one where the terms change sign regularly. For example, a sequence may have terms that are positive, then negative, and continue this pattern as it progresses. This is particularly visible in the given sequence \( a_{n} = \frac{(-1)^{n+1}}{2n - 1} \) where the exponent of \((-1)^{n+1} \) dictates the sign of each term.
- For even values of \(n\), \((-1)^{n+1}\) is negative, resulting in negative terms.
- For odd \(n\), \((-1)^{n+1}\) becomes positive, resulting in positive terms.
Limit of a Sequence
The limit of a sequence refers to the value that the sequence's terms approach as the variable \(n\) becomes very large. In our specific sequence, \( a_{n} = \frac{(-1)^{n+1}}{2n - 1} \), we are interested in whether there is a particular number that the terms get closer to as \(n\) increases.
- Since the denominator \(2n - 1\) grows indefinitely, the size of each term becomes smaller and smaller.
- Even though alternating sequences have terms oscillating between positive and negative values, what really matters is the size of those terms.
Sequence Convergence
Sequence convergence is the idea that the terms of a sequence tend to get closer to a specific value, called the limit, as \(n\) increases. If this happens, the sequence is said to converge. In the context of our sequence, \( a_{n} = \frac{(-1)^{n+1}}{2n - 1} \), the convergence analysis hinges on:
- How the denominator \(2n - 1\) increases, causing the terms to shrink.
- Despite the sign changes due to \((-1)^{n+1}\), the absolute magnitude decreases as \(n\) becomes large.
Behavior of Sequences
Understanding sequence behavior involves looking at how the terms change over time as \(n\) increases. For the sequence \( a_{n} = \frac{(-1)^{n+1}}{2n - 1} \), the behavior is analyzed in terms of both the direction (sign) and size (magnitude) of the terms.
- The alternating pattern shows that terms switch from positive to negative, affecting direction.
- The magnitude of each term is impacted by the linear growth of \(2n - 1\), which makes terms smaller over larger \(n\).
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