Problem 43
Question
Which of the following can show optical isomerism? (a) 2-bromo-2-chlorobutane (b) 2 -methylpropane (c) 2,2-dimethyl-1-butanol (d) 2,2,4-trimethylpentane
Step-by-Step Solution
Verified Answer
(a) 2-bromo-2-chlorobutane
(b) 2-methylpropane
(c) 2,2-dimethyl-1-butanol
(d) 2,2,4-trimethylpentane
Answer: (a) 2-bromo-2-chlorobutane
1Step 1: Identify the chiral centers
In each compound, we need to find the carbon atom having four different atoms or groups attached to it, which is a chiral center.
(a) 2-bromo-2-chlorobutane:
Structure - CH3CHBrCHClCH3
The second carbon (C2) has four different groups attached: -H, -CH3, -Br, and -Cl. So, it is a chiral center.
(b) 2-methylpropane:
Structure - (CH3)3CH
The second carbon (C2) has only three different groups attached: -H and three -CH3. So, it doesn't have a chiral center.
(c) 2,2-dimethyl-1-butanol:
Structure - HOC(CH3)C(CH3)2CH2CH3
The second carbon (C2) has only three different groups attached: -OH, -CH3, and an -isopropyl group. So, it doesn't have a chiral center.
(d) 2,2,4-trimethylpentane:
Structure - (CH3)3CCH2CH(CH3)2
There are no carbons with four different groups attached, just carbons that have either -H, two -CH3, or three -CH3 attached. So, it doesn't have a chiral center.
2Step 2: Determining the compound that can show optical isomerism
The compound with a chiral center is 2-bromo-2-chlorobutane. Since it has a chiral center, it can show optical isomerism. So, the answer is (a) 2-bromo-2-chlorobutane.
Key Concepts
Chiral CenterOrganic Compounds2-bromo-2-chlorobutane
Chiral Center
A chiral center is a fundamental concept in stereochemistry that significantly impacts the behavior and properties of molecules. It is defined as a carbon atom that has four different atoms or groups attached to it. Such an arrangement results in two non-superimposable mirror images, similar to how left and right hands are mirror images yet distinct. These configurations are known as enantiomers.
Why is the chiral center so important? Because the presence of one or more chiral centers in a molecule allows it to exhibit optical isomerism, a phenomenon where the molecule can rotate plane-polarized light in different directions. This ability is crucial in fields like pharmaceuticals, where different enantiomers of a drug can have drastically different effects on the body.
Why is the chiral center so important? Because the presence of one or more chiral centers in a molecule allows it to exhibit optical isomerism, a phenomenon where the molecule can rotate plane-polarized light in different directions. This ability is crucial in fields like pharmaceuticals, where different enantiomers of a drug can have drastically different effects on the body.
- A molecule with one chiral center can exist in two forms: as a pair of enantiomers.
- These enantiomers often have identical physical properties except for their interaction with plane-polarized light.
- Recognizing chiral centers helps in understanding and predicting the optical activity of a compound.
Organic Compounds
Organic compounds are the center of organic chemistry, which is the study of carbon-containing compounds. These molecules can be incredibly simple, like methane, or incredibly complex, like proteins and DNA.
Carbon's unique ability to form four covalent bonds enables it to create an immense variety of structures, ranging from chains and rings to complex branched molecules. This versatility is the reason behind the vast number of organic compounds that exist.
Carbon's unique ability to form four covalent bonds enables it to create an immense variety of structures, ranging from chains and rings to complex branched molecules. This versatility is the reason behind the vast number of organic compounds that exist.
- Organic compounds primarily consist of carbon and hydrogen, but also frequently include other elements like oxygen, nitrogen, sulfur, and halogens (such as chlorine and bromine).
- They are widely found in all life forms as well as in synthetic materials.
- Organic compounds can be classified based on the functional groups they contain, which are specific groups of atoms within molecules that have characteristic properties and reactivity.
2-bromo-2-chlorobutane
2-bromo-2-chlorobutane is an example of an organic compound that can exhibit optical isomerism due to the presence of a chiral center. Its structure can be represented as CH extsubscript{3}CHBrCHClCH extsubscript{3}.
The chiral center in this molecule is located on the second carbon atom, which is connected to four different groups: a methyl group (CH extsubscript{3}), a bromine atom (Br), a chlorine atom (Cl), and a hydrogen atom (H). The distinct nature of these attachments makes the carbon chiral, enabling the compound to exist in two enantiomeric forms.
The chiral center in this molecule is located on the second carbon atom, which is connected to four different groups: a methyl group (CH extsubscript{3}), a bromine atom (Br), a chlorine atom (Cl), and a hydrogen atom (H). The distinct nature of these attachments makes the carbon chiral, enabling the compound to exist in two enantiomeric forms.
- Each enantiomer of 2-bromo-2-chlorobutane has a unique 3D orientation but maintains the same chemical formula.
- Optical activity arises because the two enantiomers rotate plane-polarized light in opposite directions, one being the dextrorotatory form and the other being the levorotatory form.
- In a racemic mixture, where both enantiomers are present in equal amounts, the optical effects cancel each other out, resulting in no net rotation of light.
Other exercises in this chapter
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R For which of the following is geometric isomerism possible? (a) \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{CCl}_{2}\) (b) \(\mathrm{CH}_{3} \mathrm
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Which of the following compounds can show optical isomerism? (a) dichloromethane (b) 1,2 -dichloroethane (c) bromochlorofluoromethane (d) 1 -bromoethanol
View solution Problem 47
Classify the following reactions as addition, substitution, elimination, or condensation. (a) \(\mathrm{C}_{2} \mathrm{H}_{2}(g)+\mathrm{HBr}(g) \rightarrow \ma
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