Problem 43
Question
What part of a zinc-carbon dry cell is the anode? Describe the reaction that takes place there
Step-by-Step Solution
Verified Answer
The anode in a zinc-carbon dry cell is the zinc container. The oxidation reaction that takes place at the anode is: \[ Zn(s) \rightarrow Zn^{2+}(aq) + 2e^- \] Zinc, in its solid state, loses two electrons and becomes a positively charged ion, \(Zn^{2+}\), in the aqueous state.
1Step 1: Identify the Components of a Zinc-Carbon Dry Cell
A zinc-carbon dry cell is a type of battery that consists of a zinc container (which acts as both a container and an electrode), a moist paste of ammonium chloride (as an electrolyte), manganese dioxide (as a depolarizer), and a porous graphite or carbon rod (as the second electrode).
2Step 2: Determine the Anode in the Dry Cell
In an electrochemical cell, the anode is the electrode where oxidation takes place, which means electrons are given up. In a zinc-carbon dry cell, it is the zinc container that acts as the anode.
3Step 3: Identify the Reaction at the Anode
At the anode, the following oxidation reaction takes place:
\[ Zn(s) \rightarrow Zn^{2+}(aq) + 2e^- \]
Here, zinc, in its solid state, is oxidized and loses two electrons, transforming into its positively charged ion, \(Zn^{2+}\), in the aqueous state. Thus, the reaction at the anode involves the oxidation of zinc.
Key Concepts
Anode ReactionOxidation ProcessElectrochemical CellZinc Oxidation
Anode Reaction
In a zinc-carbon dry cell, the anode is the site where the oxidation reaction occurs. This is crucial because it sets the stage for the electrochemical reactions that generate electrical energy. The zinc container itself serves as the anode. At this point, solid zinc (Zn) undergoes a chemical change. Specifically, the zinc atoms lose electrons, a process known as oxidation. This transformation can be represented by the following chemical equation: \[ Zn(s) \rightarrow Zn^{2+}(aq) + 2e^- \] This means each zinc atom releases two electrons, changing from a neutral to a positively charged ion (\(Zn^{2+}\)). By shedding these electrons at the anode, the flow of electrons moves through the external circuit, allowing the battery to power electrical devices.
Oxidation Process
The oxidation process is a key component in the function of electrochemical cells, like zinc-carbon dry cells. Oxidation involves the loss of electrons from a substance. In the context of the zinc-carbon dry cell, zinc oxidizes as it loses electrons at the anode.
- Oxidation results in the conversion of zinc atoms into zinc ions
- These ions have a positive charge because electrons, which are negatively charged, are removed from zinc
- This electrical charge difference is vital as it initiates electron flow within the battery circuit
Electrochemical Cell
An electrochemical cell is a device capable of generating electrical energy through chemical reactions. Zinc-carbon dry cells are a common type of these cells and are widely used in various household items. The way an electrochemical cell works involves the following:
- Anode and cathode: The anode is where oxidation takes place, losing electrons, while the cathode gains electrons
- Electrolyte: A chemical medium that allows ions to move between the electrodes, in this case, ammonium chloride is used
- Electron flow: The free electrons released at the anode travel through an external circuit to the cathode
Zinc Oxidation
Zinc oxidation is the core reaction driving the functionality of zinc-carbon dry cells. As a reactive metal, zinc naturally tends to give up electrons, resulting in zinc ions \[ Zn(s) \rightarrow Zn^{2+}(aq) + 2e^- \] This reaction not only gives zinc-carbon batteries their ability to produce electricity but also influences the lifespan and efficiency of the battery.
- The rate of zinc oxidation impacts how long the battery can supply power before depletion
- Over time, the build-up of zinc ions can also lead to changes in cell performance
- Strategies to manage this process involve tweaks in manufacturing and design, aiming to prolong cell life and efficiency
Other exercises in this chapter
Problem 40
Write the balanced chemical equation for the standard cell notations listed below. $$ \begin{array}{l}{\text { a. } \mathrm{I}^{-}\left|\mathrm{I}_{2} \| \mathr
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Calculate the cell potential for the following voltaic cells. $$ \begin{array}{l}{\text { a. } 2 \mathrm{Ag}^{+}(\mathrm{aq})+\mathrm{Pb}(\mathrm{s}) \rightarro
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How do primary and secondary batteries differ?
View solution Problem 45
Lead-Acid Battery What substance is reduced in a lead-acid storage battery? What substance is oxidized? What substances are produced in each reaction?
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