Problem 43
Question
Use your calculator to find the multiplicative inverse of \(\left[\begin{array}{ll}\frac{1}{2} & \frac{2}{5} \\ \frac{3}{4} & \frac{1}{4}\end{array}\right]\) What difficulty did you encounter?
Step-by-Step Solution
Verified Answer
The inverse matrix is \( \begin{bmatrix} -\frac{10}{7} & \frac{16}{7} \\ \frac{30}{7} & -\frac{20}{7} \end{bmatrix} \). Finding fractions by hand can be challenging.
1Step 1: Identify Matrix Elements
The given matrix is \( A = \begin{bmatrix} \frac{1}{2} & \frac{2}{5} \ \frac{3}{4} & \frac{1}{4} \end{bmatrix} \). Let's identify its elements: \( a = \frac{1}{2} \), \( b = \frac{2}{5} \), \( c = \frac{3}{4} \), \( d = \frac{1}{4} \).
2Step 2: Calculate the Determinant
The determinant of the 2x2 matrix \( A \) is calculated as follows:\[ \text{det}(A) = ad - bc = \left(\frac{1}{2} \times \frac{1}{4}\right) - \left(\frac{2}{5} \times \frac{3}{4}\right)\]\[ = \frac{1}{8} - \frac{6}{20} = \frac{1}{8} - \frac{3}{10} = \frac{5}{40} - \frac{12}{40} = -\frac{7}{40} \]Ensure that the determinant is non-zero; the matrix is invertible.
3Step 3: Calculate the Inverse Matrix
The formula for the inverse of a 2x2 matrix \( A \) is:\[ A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \]Substitute the known values:\[ A^{-1} = \frac{1}{-\frac{7}{40}} \begin{bmatrix} \frac{1}{4} & -\frac{2}{5} \ -\frac{3}{4} & \frac{1}{2} \end{bmatrix} \]\[ = -\frac{40}{7} \begin{bmatrix} \frac{1}{4} & -\frac{2}{5} \ -\frac{3}{4} & \frac{1}{2} \end{bmatrix} \]Multiply through by \(-\frac{40}{7}\):\[ A^{-1} = \begin{bmatrix} -\frac{40}{28} & \frac{80}{35} \ \frac{120}{28} & -\frac{40}{14} \end{bmatrix} \]Simplify:\[ A^{-1} = \begin{bmatrix} -\frac{10}{7} & \frac{16}{7} \ \frac{30}{7} & -\frac{20}{7} \end{bmatrix} \].
4Step 4: Use a Calculator
Use a calculator or matrix algebra software to verify your calculations of the inverse matrix. Ensure that the multiplication of \( A \) and \( A^{-1} \) gives the identity matrix \( I \).
5Step 5: Address Any Difficulties
In manually calculating the determinants and matrix inverses, maintaining accuracy in fractions can be challenging without a calculator. Ensure precision in simplifying fractions and arithmetic.
Key Concepts
Determinant CalculationMatrix AlgebraFraction Arithmetic
Determinant Calculation
The determinant is a special number that can be calculated from a square matrix. It is essential for finding the inverse of a matrix. For a 2x2 matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \), the determinant \( \text{det}(A) \) is computed as:
- \( \text{det}(A) = ad - bc \)
- \( a = \frac{1}{2} \), \( b = \frac{2}{5} \)
- \( c = \frac{3}{4} \), \( d = \frac{1}{4} \)
- \( \text{det}(A) = \left(\frac{1}{2} \cdot \frac{1}{4}\right) - \left(\frac{2}{5} \cdot \frac{3}{4}\right) = \frac{1}{8} - \frac{3}{10} \)
- Convert fractions to a common denominator: \( \frac{5}{40} - \frac{12}{40} \)
- So, \( \text{det}(A) = -\frac{7}{40} \)
Matrix Algebra
Matrix algebra involves operations with matrices, such as addition, multiplication, and finding inverses. To find the inverse of a matrix is a crucial operation. If a 2x2 matrix has a non-zero determinant, it is invertible. The inverse is found using the formula:
- For a matrix \( A = \begin{bmatrix} a & b \ c & d \end{bmatrix} \), its inverse is \( A^{-1} = \frac{1}{\text{det}(A)} \begin{bmatrix} d & -b \ -c & a \end{bmatrix} \)
- Substitute \( d = \frac{1}{4} \), \( -b = -\frac{2}{5} \), \( -c = -\frac{3}{4} \), and \( a = \frac{1}{2} \)
- The inverse matrix calculation involves multiplying these values by \( \frac{1}{-\frac{7}{40}} \) to balance the scale imposed by the determinant's reciprocal
- The result is \( A^{-1} = \begin{bmatrix} -\frac{10}{7} & \frac{16}{7} \ \frac{30}{7} & -\frac{20}{7} \end{bmatrix} \)
Fraction Arithmetic
Fraction arithmetic, crucial in matrix operations, involves addition, subtraction, multiplication, and division of fractions. When dealing with matrix elements in fractional form:
- Always find a common denominator when adding or subtracting: For \( \frac{1}{8} - \frac{3}{10} \), convert to \( \frac{5}{40} - \frac{12}{40} \)
- Multiply fractions across numerators and denominators: For example, \( \frac{1}{2} \cdot \frac{1}{4} = \frac{1}{8} \).
- Division of fractions is just as important, particularly when dealing with determinants: Multiply by the reciprocal of the divisor, for example, divide by \( -\frac{7}{40} \) is to multiply by its reciprocal \( -\frac{40}{7} \).
Other exercises in this chapter
Problem 42
Use your calculator to find the multiplicative inverse (if one exists) of each of the following matrices. Be sure to check your answers by showing that \(A^{-1}
View solution Problem 42
For Problems \(35-43\), use the following matrices. \( \begin{aligned} A &=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] & B &=\
View solution Problem 43
For Problems \(35-43\), use the following matrices. \( \begin{aligned} A &=\left[\begin{array}{ll} a_{11} & a_{12} \\ a_{21} & a_{22} \end{array}\right] & B &=\
View solution Problem 43
Describe in your own words the process of solving a system of inequalities.
View solution