Problem 43
Question
Use trigonometric identities to transform the left side of the equation into the right side \((0<\theta<\pi / 2)\). $$ (\sec \theta+\tan \theta)(\sec \theta-\tan \theta)=1 $$
Step-by-Step Solution
Verified Answer
After applying the difference of squares formula and the Pythagorean identity, the left-hand side of the equation simplifies to 1, which matches the right-hand side. Thus, the transformation is verified.
1Step 1: Apply the Difference of Squares Formula
We can regard \(\sec \theta\) as 'a' and \(\tan \theta\) as 'b', then apply the formula to the expression on the left-hand side. Therefore, we have that: \(\sec^2 \theta - \tan^2 \theta\).
2Step 2: Use the Pythagorean Identity
Introduce the Pythagorean identity, which states that \(\sec^2\theta = 1 + \tan^2\theta\). This allows us to substitute \(\sec^2 \theta\) in our expression with \(1 + \tan^2\theta\). Now the equation becomes \(1 + \tan^2 \theta - \tan^2 \theta\).
3Step 3: Simplify the Equation
Simplify the equation by eliminating the like-terms; \( \tan^2 \theta\) is subtracted from itself and completely removed from the equation. This leaves us with the equation equalling 1, which is the desired outcome: \(1 = 1\).
Key Concepts
Difference of Squares FormulaPythagorean IdentityAngle Simplification
Difference of Squares Formula
The Difference of Squares Formula is a foundational concept in algebra and calculus. It states that the product of the sum and difference of two terms can be expressed as the difference of their squares. In formula terms,
In the context of trigonometry, it can help transform complex expressions into simpler forms by recognizing and utilizing such patterns.
In the problem given,
- \[(a+b)(a-b) = a^2 - b^2\]
In the context of trigonometry, it can help transform complex expressions into simpler forms by recognizing and utilizing such patterns.
In the problem given,
- The terms \[a = \sec \theta\] and \[b = \tan \theta\] are split into a difference of squares.
Pythagorean Identity
Pythagorean Identities are essential tools in trigonometry that relate the squares of sine, cosine, and tangent functions to 1. These identities derive from the Pythagorean Theorem, common in geometry.
Specifically, the Pythagorean Identity that we use here is:
After applying this identity, the expression becomes \[1 + \tan^2 \theta - \tan^2 \theta\].
This step simplifies the equation significantly by setting the stage for final cancellation of terms.
Specifically, the Pythagorean Identity that we use here is:
- \[\sec^2 \theta = 1 + \tan^2 \theta\]
After applying this identity, the expression becomes \[1 + \tan^2 \theta - \tan^2 \theta\].
This step simplifies the equation significantly by setting the stage for final cancellation of terms.
Angle Simplification
Angle Simplification involves reducing an expression to its most simple form, often by eliminating unnecessary components or combining like-terms. As a final step in the solution process for trigonometric identities, simplification confirms equivalence or solves equations.
Once we get to \[1 + \tan^2 \theta - \tan^2 \theta\],
we notice that the \[\tan^2 \theta\] terms cancel each other out.
This skill is invaluable for students as they work through complex trigonometric equations.
Once we get to \[1 + \tan^2 \theta - \tan^2 \theta\],
we notice that the \[\tan^2 \theta\] terms cancel each other out.
- This leaves us with \[1 = 1\], confirming the identity transformation.
This skill is invaluable for students as they work through complex trigonometric equations.
Other exercises in this chapter
Problem 43
Sketch the graph of the function. (Include two full periods.) $$ y=\cos \frac{x}{2} $$
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Evaluate the trigonometric function of the quadrant angle. $$ \csc \pi $$
View solution Problem 43
Use the value of the trigonometric function to evaluate the indicated functions. \(\sin t=\frac{1}{2}\) (a) \(\sin (-t)\) (b) \(\csc (-t)\)
View solution Problem 43
Determine the quadrant in which each angle lies. (a) \(-132^{\circ} 50^{\prime}\) (b) \(-336^{\circ}\)
View solution