Problem 43
Question
Two rockets having the same acceleration start from rest, but rocket \(A\) travels for twice as much time as rocket \(B\). (a) If rocket \(A\) goes a distance of \(250 \mathrm{~km}\), how far will rocket \(B\) go? (b) If rocket \(A\) reaches a speed of \(350 \mathrm{~m} / \mathrm{s},\) what speed will rocket \(B\) reach?
Step-by-Step Solution
Verified Answer
Rocket B travels 125 km and reaches a speed of 175 m/s.
1Step 1: Understanding the Problem
We are given two rockets, A and B, with the same acceleration. Rocket A travels for twice the time rocket B does. We need to find the distance rocket B travels if A travels 250 km, and the speed B reaches if A reaches 350 m/s.
2Step 2: Using the Distance Formula
To find the distance traveled by rocket B, use the kinematic equation: \[ d = \frac{1}{2} a t^2 \]For rocket A, \(d_A = \frac{1}{2} a (2t)^2 = 2at^2\).Given \(d_A = 250 \text{ km}\), we can find that: \[ 2at^2 = 250 \times 10^3 \text{ m} \].
3Step 3: Solving for Rocket B's Distance
Rocket B's distance \(d_B = \frac{1}{2} a t^2\).Using the result from Step 2: \[ d_B = \frac{1}{2} (2at^2) / 2 = \frac{250 \times 10^3}{2} = 125 \text{ km} \].So, rocket B travels 125 km.
4Step 4: Using the Final Velocity Formula
To find the speed of rocket B, use the kinematics equation: \[ v = at \].For rocket A, \(v_A = a(2t) = 2at\).Given \(v_A = 350 \text{ m/s}\), we express it as \[ 2at = 350 \].
5Step 5: Solving for Rocket B's Speed
Rocket B's speed \(v_B = at\).From the result in Step 4: \[ v_B = \frac{350}{2} = 175 \text{ m/s} \].Thus, rocket B reaches a speed of 175 m/s.
Key Concepts
AccelerationDistance FormulaFinal VelocityKinematic Equations
Acceleration
Acceleration is a fundamental concept in kinematics, which is the branch of physics that describes the motion of objects. It refers to the rate at which an object changes its velocity.
Acceleration is not just about speeding up; it can also involve slowing down or changing direction. It is a vector quantity, which means it has both magnitude and direction.
Acceleration is not just about speeding up; it can also involve slowing down or changing direction. It is a vector quantity, which means it has both magnitude and direction.
- A constant acceleration implies that the object's velocity is changing at a steady rate over time.
- If two objects have the same acceleration, as in the case of rockets A and B, they have the same change in velocity over equal time intervals.
- The formula for acceleration is: \[ a = \frac{\Delta v}{\Delta t} \] where \( \Delta v \) is the change in velocity and \( \Delta t \) is the change in time.
Distance Formula
The distance formula in kinematics helps us calculate how far an object travels under constant acceleration. For an object starting from rest with uniform acceleration, we can use one of the kinematic equations to calculate the distance:
\[d = \frac{1}{2} a t^2\]
This formula originates from the integration of the acceleration function, accounting for the initial velocity of zero. The simplicity of the equation reflects how distance depends quadratically on time while under constant acceleration.
\[d = \frac{1}{2} a t^2\]
This formula originates from the integration of the acceleration function, accounting for the initial velocity of zero. The simplicity of the equation reflects how distance depends quadratically on time while under constant acceleration.
- When the time doubles, the distance increases by four times, assuming acceleration stays constant. This is because distance is proportional to the square of time.
- In our problem, rocket A travels for twice as long as rocket B, which significantly impacts the distance covered because time appears squared in the formula.
Final Velocity
Final velocity is a key concept in understanding the motion of an object under constant acceleration. It signifies the speed an object reaches after accelerating for a specific period of time.
Using the kinematic equation for velocity: \[ v = at \]
we can derive the final velocity of an object starting from rest. Here, \( v \) is the final velocity, \( a \) is the acceleration, and \( t \) is the time period for which it accelerates.
Using the kinematic equation for velocity: \[ v = at \]
we can derive the final velocity of an object starting from rest. Here, \( v \) is the final velocity, \( a \) is the acceleration, and \( t \) is the time period for which it accelerates.
- For example, rocket A's final velocity is achieved after accelerating for twice the time of rocket B. Thus, its velocity is twice that of rocket B, assuming the accelerations are the same.
- Understanding how final velocity is calculated is crucial for analyzing motion parameters like speed and distance over time.
Kinematic Equations
Kinematic equations are a set of equations that describe the motion of objects under constant acceleration. These equations are essential tools for solving problems involving linear motion.
The basic kinematic equations include:
The basic kinematic equations include:
- \[ v = u + at \]li>\[ d = ut + \frac{1}{2} at^2 \]
- \[ v^2 = u^2 + 2ad \]
- These equations relate all the motion variables and help in predicting one variable when others are known.
- In the problem with the rockets, these equations allow us to find the distance and velocity by using time, given the rockets start from rest (\( u = 0 \)).
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