Problem 43
Question
The half-lives of both zero-order and second-order reactions depend on the initial concentration, as well as on the rate constant. In one case, the half- life gets longer as the initial concentration increases, and in the other it gets shorter. Which is which, and why isn't the situation the same for both?
Step-by-Step Solution
Verified Answer
In the case of zero-order reactions, the half-life increases as the initial concentration increases. For second-order reactions, the half-life decreases as the initial concentration increases. This is because the rate of a zero-order reaction is independent of the concentration of reactant, while the rate of a second-order reaction is highly dependent on it.
1Step 1: Understand zero-order reactions
A zero order reaction has the rate law: rate = k[A]^0 = k. Its half-life equation is \(t_{1/2} = \frac{[A]_0}{2k}\), where [A]_0 is the initial concentration, and k is the rate constant. As we can see, as the initial concentration [A]_0 increases, the half-life also increases, meaning the reaction takes longer.
2Step 2: Understand second-order reactions
A second order reaction has the rate law: rate = k[A]^2. Its half-life equation is \(t_{1/2} = \frac{1}{2k[A]_0}\). In this case, as the initial concentration [A]_0 increases, the half-life decreases, meaning the reaction takes less time.
3Step 3: Explain why they differ
The reason why these two reactions have opposite dependencies on the initial concentration relates to their rate laws. For a zero-order reaction, the rate is independent of the concentration of reactant, while for a second-order reaction, the rate is highly dependent on the concentration of the reactant. Therefore, having a large initial concentration for a second-order reaction means there are more reactant molecules available to react, thus the reaction completes faster.
Key Concepts
Zero-Order ReactionsSecond-Order ReactionsHalf-Life Dependency
Zero-Order Reactions
In reaction kinetics, a zero-order reaction is one where the rate of reaction is constant and independent of the concentration of reactants. This can be expressed with the rate law: \( \text{rate} = k[A]^0 = k \), which implies that the rate is equal to the rate constant, \( k \). These reactions can occur when a catalyst is saturated by the reactant, making the reaction speed constant.
An important aspect of zero-order reactions is how the half-life changes with concentration. The half-life (the time it takes for half of the reactant to be consumed) for zero-order reactions is given by: \( t_{1/2} = \frac{[A]_0}{2k} \). Here, \( [A]_0 \) represents the initial concentration of the reactant, and this equation shows that the half-life increases with increasing initial concentration.
Thus, in a zero-order reaction, the more reactant you start with, the longer it will take for half of it to be used because the reaction rate doesn't change."
An important aspect of zero-order reactions is how the half-life changes with concentration. The half-life (the time it takes for half of the reactant to be consumed) for zero-order reactions is given by: \( t_{1/2} = \frac{[A]_0}{2k} \). Here, \( [A]_0 \) represents the initial concentration of the reactant, and this equation shows that the half-life increases with increasing initial concentration.
Thus, in a zero-order reaction, the more reactant you start with, the longer it will take for half of it to be used because the reaction rate doesn't change."
Second-Order Reactions
Second-order reactions exhibit a different behavior compared to zero-order reactions because their rate depends on the concentration of the reactants. The rate law for a second-order reaction is: \( \text{rate} = k[A]^2 \). This equation shows that the rate is proportional to the square of the concentration of the reactant.
Now, let’s discuss the half-life for second-order reactions. The half-life is determined by the equation: \( t_{1/2} = \frac{1}{2k[A]_0} \). In this case, \( [A]_0 \) is still the initial concentration, and you can observe that the half-life decreases as the initial concentration increases.
This means, for second-order reactions, a higher initial concentration results in a shorter half-life. Why? Because the reaction rate increases with more reactant available. More molecules mean more frequent collisions and reactions, leading to quicker depletion of reactants."
Now, let’s discuss the half-life for second-order reactions. The half-life is determined by the equation: \( t_{1/2} = \frac{1}{2k[A]_0} \). In this case, \( [A]_0 \) is still the initial concentration, and you can observe that the half-life decreases as the initial concentration increases.
This means, for second-order reactions, a higher initial concentration results in a shorter half-life. Why? Because the reaction rate increases with more reactant available. More molecules mean more frequent collisions and reactions, leading to quicker depletion of reactants."
Half-Life Dependency
The concept of half-life in chemical kinetics gives us insight into how long it takes for half of a given amount of reactant to be consumed in a reaction.
For zero-order and second-order reactions, the dependency of half-life on initial concentration varies significantly because of the different ways the reaction rates depend on concentration.
For zero-order and second-order reactions, the dependency of half-life on initial concentration varies significantly because of the different ways the reaction rates depend on concentration.
- Zero-order reactions: The half-life increases as the initial concentration increases, due to the constant reaction rate.
- Second-order reactions: The half-life decreases with higher initial concentrations, due to the increasing rate as more reactants are present.
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