Problem 43
Question
The graph of $$ y=\frac{x ! e^{x}}{x^{x} \sqrt{2 \pi x}} $$ has a horizontal asymptote of \(y=1\). Use this fact to find an approximation for \(n !\) if \(n\) is a large positive integer.
Step-by-Step Solution
Verified Answer
For large \(n\), use Stirling's approximation: \(n! \approx \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n\).
1Step 1: Identify the function components
The given function is \(y = \frac{x! e^{x}}{x^{x} \sqrt{2 \pi x}}\). It is composed of the factorial function \(x!\), the exponential function \(e^{x}\), a power \(x^{x}\), and the square root of a product \(\sqrt{2\pi x}\).
2Step 2: Recall Stirling's Approximation
Stirling's approximation states that for large \(n\), \(n! \approx \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n\). This approximation is based on the asymptotic behavior of \(n!\).
3Step 3: Analyze the horizontal asymptote
The horizontal asymptote \(y=1\) implies that for large \(x\), the value of \(y\) approaches 1. Therefore, \(\frac{x! e^{x}}{x^{x} \sqrt{2 \pi x}} \approx 1\).
4Step 4: Set up the equation
Given the horizontal asymptote, we have the equation \(x! e^{x} = x^{x} \sqrt{2\pi x}\). Rearrange it as \(x! = \frac{x^{x} \sqrt{2\pi x}}{e^{x}}\).
5Step 5: Compare with Stirling's Approximation
Using Stirling's approximation \(n! \approx \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n\), verify the equivalence \(\frac{n^{n} \sqrt{2\pi n}}{e^{n}} \approx \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n\), confirming the expression matches this asymptotic form.
Key Concepts
Factorial FunctionAsymptotic BehaviorHorizontal AsymptoteLarge Positive Integers
Factorial Function
The factorial function, denoted as \(n!\), is an essential mathematical operation often used in permutations, combinations, and many areas of calculus and analysis. For a given positive integer \(n\):
- If \(n = 0\), then \(n! = 1\).
- For any positive integer \(n\), \(n! = n \times (n-1) \times (n-2) \times \ldots \times 1\).
Asymptotic Behavior
Asymptotic behavior refers to the way functions behave as their inputs approach a specific value, often infinity. In the context of Stirling's Approximation, it relates to how the factorial function \(n!\) behaves as \(n\) becomes large. Stirling's Approximation provides us with a way to express the factorial in terms of other simpler functions and constants:
- \(n! \approx \sqrt{2 \pi n} \left( \frac{n}{e} \right)^n\)
Horizontal Asymptote
A horizontal asymptote of a function is a horizontal line \(y = c\) that the graph of the function approaches as \(x\) tends toward positive or negative infinity. For the function \(y = \frac{x! e^{x}}{x^{x} \sqrt{2 \pi x}}\), the horizontal asymptote is \(y = 1\). This means as \(x\) becomes very large, the function approaches the value 1. Understanding horizontal asymptotes is crucial because it helps us predict the behavior of complex functions without calculating them explicitly at infinity. In this particular example, knowing the behavior near this asymptote allows us to derive a more manageable form for \(n!\) using Stirling's Approximation. When analyzing functions, identifying the horizontal asymptote can thus give insights into the long-term trend of the function values.
Large Positive Integers
In mathematics, large positive integers typically refer to numbers that are significantly larger than typical everyday numbers. Handling such numbers often requires special approaches, like approximations, because direct computations become impractical. These integers are of particular interest when considering the factorial function, as \(n!\) grows extremely fast.Stirling's Approximation becomes relevant in this context, providing a feasible method to approximate the factorial values for large \(n\). Instead of performing numerous multiplications, Stirling's Approximation simplifies these calculations. Therefore, when solving problems involving large positive integers, relying on approximations and principles of asymptotic behavior can save time and computational resources. This is particularly beneficial in domains like algorithm analysis or probability theory, where understanding the behavior of large numbers is essential.
Other exercises in this chapter
Problem 43
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