Problem 43
Question
The \(2.728-\mathrm{K}\) blackbody radiation has its peak wave length at 1.062 \(\mathrm{mm} .\) What was the peak wavelength at \(t=\) \(700,000 \mathrm{y}\) when the temperature was 3000 \(\mathrm{K} ?\)
Step-by-Step Solution
Verified Answer
The peak wavelength at 3000 K is approximately 969 nm.
1Step 1: Identify Given Values
We are given the peak wavelength of blackbody radiation at a temperature of 2.728 K, which is 1.062 mm. We need to find the peak wavelength at a temperature of 3000 K.
2Step 2: Recall Wein's Law
Wein's Law states that the peak wavelength \( \lambda_{max} \) of blackbody radiation is inversely proportional to the temperature \( T \), represented as \( \lambda_{max} T = b \), where \( b \) is Wein's constant (\( 2.897 \times 10^{-3} \ \mathrm{m \cdot K} \)).
3Step 3: Calculate the Constant Using Current Values
Using the given temperature and peak wavelength at 2.728 K, we substitute into Wein's Law: \( \lambda_{max} = 1.062 \ \mathrm{mm} = 1.062 \times 10^{-3} \ \mathrm{m} \) and \( T = 2.728 \ \mathrm{K} \). This gives us \( b = \lambda_{max} \times T = 1.062 \times 10^{-3} \times 2.728 \).
4Step 4: Determine the Peak Wavelength at 3000 K
Now, we use the constant \( b \) and the new temperature \( T = 3000 \ \mathrm{K} \) to find \( \lambda_{max} \) by rearranging Wein’s Law: \( \lambda_{max} = \frac{b}{T} = \frac{1.062 \times 10^{-3} \times 2.728}{3000} \).
5Step 5: Compute the Value
Calculating the above expression yields the peak wavelength \( \lambda_{max} \) at 3000 K. The result is approximately 969 nm, or 0.969 micrometers.
Key Concepts
Understanding Blackbody RadiationPeak Wavelength and Its SignificanceThe Temperature Dependence of WavelengthPhysics Problem-Solving with Wein's Law
Understanding Blackbody Radiation
Blackbody radiation is a fundamental concept in physics that describes how idealized objects, known as blackbodies, emit radiation. A blackbody absorbs all incident light, meaning it does not reflect or transmit any light, leading to the perfect emission of thermal radiation.
- This emission is entirely dependent on the body's temperature.
- At higher temperatures, a blackbody emits more radiation and its color changes, moving from red to blue in the visible spectrum as it gets hotter.
- The radiation emitted covers a spectrum of wavelengths, including infrared and visible light.
Peak Wavelength and Its Significance
The peak wavelength of blackbody radiation is where the emission of radiation is most intense, and it shifts according to the temperature of the body.
We can visualize this through a spectrum where different colors represent various wavelengths. A shift in peak wavelength indicates a change in color.
We can visualize this through a spectrum where different colors represent various wavelengths. A shift in peak wavelength indicates a change in color.
- At lower temperatures, the peak wavelength is longer, usually in the infrared range.
- As the temperature increases, the peak wavelength moves towards shorter wavelengths, entering the visible spectrum.
- For example, the Sun emits most radiation in the visible light range, centered around green, which is why the Sun appears bright and white to our eyes.
The Temperature Dependence of Wavelength
The relationship between temperature and peak wavelength is elegantly described by Wein's Law, which forms the backbone of understanding thermal radiation. Wein's Law is presented as \( \lambda_{max} T = b \), showing that the peak wavelength \( \lambda_{max} \) is inversely proportional to the temperature \( T \).
- When the temperature of a blackbody increases, the peak wavelength decreases.
- This inverse relationship means hotter objects will have peak emissions at shorter wavelengths.
- The constant \( b \), known as Wein's constant, helps us quantify the relationship across different temperatures.
Physics Problem-Solving with Wein's Law
Applying Wein's Law to solve physics problems involves a clear understanding of the problem setup and a sequence of logical steps. Let's break it down:
- First, gather the known values, such as current temperature and peak wavelength.
- Next, use these values to calculate necessary constants, like \( b \) in Wein's Law.
- Finally, manipulate the law to find unknowns, such as the peak wavelength at a different temperature.
Other exercises in this chapter
Problem 36
(a) According to the Hubble law, what is the distance \(r\) from us for galaxies that are receding from us with a speed \(c ?\) (b) Explain why the distance cal
View solution Problem 38
(a) Show that the expression for the Planck length, \(\sqrt{\hbar G / c^{3}},\) has dimensions of length. (b) Evaluate the numerical value of \(\sqrt{\hbar G /
View solution Problem 45
In the LHC, each proton will be accelerated to a kinetic energy of 7.0 \(\mathrm{TeV}\) (a) In the colliding beams, what is the available energy \(E_{\mathrm{a}
View solution Problem 46
A proton and an antiproton collide head-on with equal kinetic energies. Two \(\gamma\) rays with wavelengths of 0.780 fm are produced. Calculate the kinetic ene
View solution