Problem 43
Question
Suppose your height is \(2.0 \mathrm{~m}\) and you are standing \(50 \mathrm{~cm}\) in front of a plane mirror. a) What is the image distance? b) What is the image height? c) Is the image inverted or upright? d) Is the image real or virtual?
Step-by-Step Solution
Verified Answer
Question: A person is standing 50 cm in front of a plane mirror with a height of 2.0 meters. Determine the image distance, image height, if the image is inverted or upright, and if it is real or virtual.
Answer: The image distance is 50 cm, image height is 2.0 meters or 200 cm, the image is upright, and it is a virtual image.
1Step 1: Determine the image distance
In a plane mirror, the image distance is always equal to the object distance. The person is standing 50 cm in front of the mirror, so the image distance is 50 cm.
2Step 2: Determine the image height
In a plane mirror, the image height is always equal to the object height. The person's height is 2.0 meters or 200 cm, so the image height is also 2.0 meters or 200 cm.
3Step 3: Determine if the image is inverted or upright
In a plane mirror, the image is always upright. This means the image is not inverted.
4Step 4: Determine if the image is real or virtual
In a plane mirror, the image is always virtual. A virtual image is formed when the light rays appear to converge after reflection, but do not actually converge in physical space. A real image, on the other hand, is one where the light rays actually converge after reflection. In the case of a plane mirror, the image appears to be behind the mirror, so it is virtual.
Key Concepts
Image DistanceImage HeightInverted vs Upright ImageReal vs Virtual Image
Image Distance
Understanding the concept of image distance is essential when studying reflections in plane mirrors. Image distance refers to how far the image appears to be from the mirror surface. In a plane mirror, the image distance is an interesting characteristic because it's always equal to the object distance. This means if you stand 50 centimeters away from the mirror, like in the textbook exercise, your image appears exactly 50 centimeters behind the mirror surface. This one-to-one correspondence makes drawing ray diagrams and visualizing image formation straightforward.
- The image distance equals the object distance.
- The property is always true for plane mirrors.
Image Height
The image height in a plane mirror is another straightforward concept to understand. The height of the image produced will be the same as the height of the object. For example, if you stand at 2 meters tall in front of a plane mirror, your reflection will appear to be 2 meters tall as well. This is because plane mirrors produce images with a 1:1 scale.
- Image height is equal to object height.
- Reflections in a plane mirror are at full scale, with no magnification or reduction.
Inverted vs Upright Image
When differentiating between inverted and upright images, plane mirrors are known to produce images that are always upright relative to the object. Unlike images formed by lenses or curved mirrors which can be inverted, the reflection in a plane mirror maintains the same orientation as the object.
- In a plane mirror, the image is always upright.
- There is no inversion of the image from head to toe.
Real vs Virtual Image
The distinction between real and virtual images is fundamental in the study of optics. Real images are those where light rays actually converge, while virtual images are locations from which light rays appear to come but do not actually converge. For plane mirrors,
- The image is always virtual.
- Light rays only appear to come from behind the mirror but do not actually converge there.
Other exercises in this chapter
Problem 41
Use Fermat's Principle to derive the law of reflection.
View solution Problem 42
Fermat's Principle, from which geometric optics can be derived, states that light travels by a path that minimizes the time of travel between the points. Consid
View solution Problem 44
A light ray of wavelength 700 . \(\mathrm{nm}\) traveling in air \(\left(n_{1}=1.00\right)\) is incident on a boundary with a liquid \(\left(n_{2}=1.63\right) .
View solution Problem 45
You have a spherical mirror with a radius of curvature of \(+20.0 \mathrm{~cm}\) (so it is concave facing you). You are looking at an object whose size you want
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