Problem 43
Question
$$ \sum_{i=1}^{6} 3\left(\frac{1}{2}\right)^{i} \quad 2 \frac{61}{64} $$
Step-by-Step Solution
Verified Answer
The sum is \( 2 \frac{61}{64} \).
1Step 1: Understand the Series
The expression given is a summation: \( \sum_{i=1}^{6} 3\left(\frac{1}{2}\right)^{i} \). This is a geometric series where the first term \( a = 3(\frac{1}{2})^{1} = \frac{3}{2} \) and the common ratio \( r = \frac{1}{2} \).
2Step 2: Identify the Formula for the Sum of a Geometric Series
The formula for the sum of the first \( n \) terms of a geometric series is given by \( S_n = a\frac{1-r^n}{1-r} \).
3Step 3: Substitute the Known Values into the Formula
Substitute \( a = \frac{3}{2} \), \( r = \frac{1}{2} \), and \( n = 6 \) into the formula: \[ S_6 = \frac{3}{2} \cdot \frac{1-(\frac{1}{2})^6}{1-\frac{1}{2}} \]
4Step 4: Calculate \((\frac{1}{2})^6\)
Determine the value of \((\frac{1}{2})^6\): \[ (\frac{1}{2})^6 = \frac{1}{64} \]
5Step 5: Compute the Series
Substitute \((\frac{1}{2})^6\) back into the sum formula: \[ S_6 = \frac{3}{2} \cdot \frac{1-\frac{1}{64}}{\frac{1}{2}} \] \[ S_6 = \frac{3}{2} \cdot \frac{\frac{63}{64}}{\frac{1}{2}} \] \[ S_6 = \frac{3}{2} \cdot \frac{63}{32} \] Simplify: \[ S_6 = \frac{189}{64} \]
6Step 6: Convert to Mixed Number
Convert \( \frac{189}{64} \) to a mixed number. Divide 189 by 64, the quotient is 2 remainder 61, so: \[ \frac{189}{64} = 2 \frac{61}{64} \]
7Step 7: Final Answer
The final solution matches the provided value in the problem. The series sums to \( 2 \frac{61}{64} \).
Key Concepts
Summation NotationSum Formula for Geometric SeriesConverting Improper Fractions to Mixed Numbers
Summation Notation
Summation notation is a convenient way to represent the addition of a sequence of numbers, typically following a pattern or rule. In essence, it provides a shorthand for adding up terms that follow a series. This is often symbolized by the Greek letter Sigma (\( \Sigma \)).
In our example, we see this notation in \( \sum_{i=1}^{6} 3\left(\frac{1}{2}\right)^{i} \), which tells us to calculate the sum by iterating the expression \( 3\left(\frac{1}{2}\right)^{i} \) for values of \( i \) from 1 to 6.
Mastering summation notation allows for easy manipulation of series and mathematical sequences, making them less cumbersome and more systematic.
In our example, we see this notation in \( \sum_{i=1}^{6} 3\left(\frac{1}{2}\right)^{i} \), which tells us to calculate the sum by iterating the expression \( 3\left(\frac{1}{2}\right)^{i} \) for values of \( i \) from 1 to 6.
- The lower number, 1, is the starting index, indicating where to begin the series.
- The upper number, 6, is the stopping index, marking the final value to use in the calculations.
Mastering summation notation allows for easy manipulation of series and mathematical sequences, making them less cumbersome and more systematic.
Sum Formula for Geometric Series
A geometric series is a list of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. To find the sum of the first \( n \) terms in a geometric series, we use the sum formula:
\[ S_n = a\frac{1-r^n}{1-r} \]
Here:
Following the steps, we've plugged these values into the formula, computed the powers, and performed the necessary arithmetic, ending up with a total sum of \( \frac{189}{64} \). Understanding this formula is key for tackling problems involving geometric series efficiently.
\[ S_n = a\frac{1-r^n}{1-r} \]
Here:
- \( S_n \) is the sum of the first \( n \) terms.
- \( a \) is the first term of the series.
- \( r \) is the common ratio between the terms.
Following the steps, we've plugged these values into the formula, computed the powers, and performed the necessary arithmetic, ending up with a total sum of \( \frac{189}{64} \). Understanding this formula is key for tackling problems involving geometric series efficiently.
Converting Improper Fractions to Mixed Numbers
Converting an improper fraction to a mixed number is a vital skill in simplifying expressions and making calculations more comprehensible. An improper fraction is one where the numerator is larger than the denominator. To convert it:
1. **Divide** the numerator by the denominator.2. The **whole number** result becomes the whole part of the mixed number.3. The **remainder** of the division becomes the new numerator.4. The **denominator** remains the same.
In this exercise, the sum \( \frac{189}{64} \) is an improper fraction. By dividing 189 by 64, we get a quotient of 2 with a remainder of 61. Thus, we convert it to the mixed number \( 2 \frac{61}{64} \).
This process of converting helps in visualizing quantities in a fraction, making them easier to interpret and use. Mastering this concept is helpful in both academic and real-world applications, enhancing numerical clarity and precision.
1. **Divide** the numerator by the denominator.2. The **whole number** result becomes the whole part of the mixed number.3. The **remainder** of the division becomes the new numerator.4. The **denominator** remains the same.
In this exercise, the sum \( \frac{189}{64} \) is an improper fraction. By dividing 189 by 64, we get a quotient of 2 with a remainder of 61. Thus, we convert it to the mixed number \( 2 \frac{61}{64} \).
This process of converting helps in visualizing quantities in a fraction, making them easier to interpret and use. Mastering this concept is helpful in both academic and real-world applications, enhancing numerical clarity and precision.
Other exercises in this chapter
Problem 41
$$ 3(x-2 y)=4 \quad \text { for } x $$
View solution Problem 42
Prove that \(n^{3}-n+3\) is divisible by 3 for all positive integer values of \(n\).
View solution Problem 43
Find the indicated sum. 1+5+9+13+\cdots+197 \quad 4950
View solution Problem 43
$$ \frac{y-a}{b}=\frac{x+b}{c} \text { for } x $$
View solution